blocks|key|1935256|text|var+aNumber:Array+=+new+Array(totalA+,+totalB+,+totalC+,+totalD+);
bigger+=+aNumber[0];
for(var+i:Number+=+1,+var+j:Number+=+(aNumber.length)-1;+i<j+;+i%2B%2B)
{
++++if(bigger+<+aNumber[i])+
++++{
++++++++bigger+=+aNumber[i];
++++}
}
var+highest:Array+=+new+Array();
highest[]+=+bigger;
for(var+i:Number+=+0,+var+j:Number+=+(aNumber.length);+i<j+;+i%2B%2B){
+++if(aNumber[i]+==+bigger){
+++++highest[]+=+aNumber[i];
+++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1935257|数组最高值现在将保持最高分数|unstyled|1935258|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>var aNumber:Array = new Array(totalA , totalB , totalC , totalD );
bigger = aNumber[0];
for(var i:Number = 1, var j:Number = (aNumber.length)-1; i&lt;j ; i++)
{
 if(bigger &lt; aNumber[i]) 
 {
 bigger = aNumber[i];
 }
}
var highest:Array = new Array();
highest[] = bigger;
for(var i:Number = 0, var j:Number = (aNumber.length); i&lt;j ; i++){
 if(aNumber[i] == bigger){
 highest[] = aNumber[i];
 }
}
</code></pre>

Array highest will now hold the highest score(s)

blocks|key|1791252|text|如果您想为分数输出一个字母/etc，我会使用一个对象/字典，而不是直接数组。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1791253|基本上，算法是：|1791254|1791255|捕获对象/字典中的分数，其中键是玩家的名称，值是他们在对象/字典中的每个项目/玩家，并将当前分数与最大分数进行比较。|unordered-list-item|1791256|如果当前分数大于最大分数，请清除所有以前的获胜者，设置新的最高分数，并将当前玩家添加到获胜者。|1791257|如果当前分数等于最大分数，则将当前玩家添加到赢家数组中。|1791258|1791259|下面是一些草率编写的actionscript。|1791260|var+scores:Object+=+{
++++'A':+totalA,
++++'B':+totalB,
++++'C':+totalC,
++++'D':+totalD
};

var+maxScore:Number+=+-1;
var+winners:Array+=+new+Array();

for(var+player:String+in+scores)
{
++++var+score:Number+=+scores[player];

++++if+(score+>+maxScore)
++++{
++++++++maxScore+=+score;

++++++++winners+=+new+Array();
++++++++winners.push(player);
++++}
++++else+if+(score+==+maxScore)
++++{
++++++++winners.push(player);
++++}
}|code-block|syntax|javascript|1791261|在这段代码的末尾，您应该在maxScore中获得最高分数，并在winners数组中获得获胜球员的姓名。|offset|length|style|CODE|1791262|entityMap^0|0|0|0|0|0|0|0|0|0|D|8|V|7|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|12|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|13|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|14|8|@]|9|@]|A|$]]|$1|H|3|I|5|G|7|15|8|@]|9|@]|A|$]]|$1|J|3|K|5|G|7|16|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|17|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|18|8|@]|9|@]|A|$]]|$1|O|3|P|5|Q|7|19|8|@]|9|@]|A|$R|S]]|$1|T|3|U|5|6|7|1A|8|@$V|1B|W|1C|X|Y]|$V|1D|W|1E|X|Y]]|9|@]|A|$]]|$1|Z|3|-4|5|6|7|1F|8|@]|9|@]|A|$]]]|10|$]]

If you're wanting to output a letter/etc for the scores, I'd use an object/dictionary rather than a straight array.

Basically, the algorithm would be:

<ul>
<li>Capture the scores in an object/dictionary, where the key is the name of the player and the value is their score.</li>
<li>Enumerate each item/player in the object/dictionary and compare the current score to the maximum score.</li>
<li>If the current score is greater than the maximum score, clear all previous winners, set the new maximum score and add the current player to the winners.</li>
<li>If the current score is equal to the maximum score, add the current player to the winners array.</li>
</ul>

Following is some hastily concocted actionscript.

<pre><code>var scores:Object = {
 'A': totalA,
 'B': totalB,
 'C': totalC,
 'D': totalD
};

var maxScore:Number = -1;
var winners:Array = new Array();

for(var player:String in scores)
{
 var score:Number = scores[player];

 if (score &gt; maxScore)
 {
 maxScore = score;

 winners = new Array();
 winners.push(player);
 }
 else if (score == maxScore)
 {
 winners.push(player);
 }
}
</code></pre>

At the end of this segment of code, you should have the highest score in <code>maxScore</code> and the names of the winning players in the <code>winners</code> array.

blocks|key|4059853|text|这个解决方案可以更优雅一些(假设一个数组包含整数值)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4059854|<?xml+version="1.0"+encoding="utf-8"?>
<mx:Application+xmlns:mx="http://www.adobe.com/2006/mxml"+creationComplete="init()">
++++<mx:Script>
++++++++<![CDATA[
++++++++++++import+mx.collections.ArrayCollection;
++++++++++++import+mx.collections.Sort;
++++++++++++import+mx.collections.SortField;
++++++++++++import+mx.controls.Alert;
++++++++++++private+var+array:Array+=+[1,2,3,4,3];

++++++++++++public+function+init():void{
++++++++++++++++var+maxValue:Number+=+getMaxValue(new+ArrayCollection(array));
++++++++++++++++Alert.show(String(maxValue));+//show+value+4
++++++++++++}

++++++++++++private+function+getMaxValue(tempArr:ArrayCollection):Number+{+
++++++++++++++++var+dataSort:Sort++++=+new+Sort();+
++++++++++++++++dataSort.fields++++++++=+[new+SortField(null,false,true,true)];;+
++++++++++++++++tempArr.sort+=+dataSort;+
++++++++++++++++tempArr.refresh();+
++++++++++++++++return+tempArr[0];
++++++++++++}
++++++++]]>
++++</mx:Script>
</mx:Application>|code-block|syntax|javascript|4059855|根据这个示例，我从最高到最低对数组进行排序，然后取第一个。它工作得很完美。我希望这能帮到你|4059856|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This solution can be a bit more elegant (assuming that a array contains integer values):

<pre><code>&lt;?xml version="1.0" encoding="utf-8"?&gt;
&lt;mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" creationComplete="init()"&gt;
 &lt;mx:Script&gt;
 &lt;![CDATA[
 import mx.collections.ArrayCollection;
 import mx.collections.Sort;
 import mx.collections.SortField;
 import mx.controls.Alert;
 private var array:Array = [1,2,3,4,3];

 public function init():void{
 var maxValue:Number = getMaxValue(new ArrayCollection(array));
 Alert.show(String(maxValue)); //show value 4
 }

 private function getMaxValue(tempArr:ArrayCollection):Number { 
 var dataSort:Sort = new Sort(); 
 dataSort.fields = [new SortField(null,false,true,true)];; 
 tempArr.sort = dataSort; 
 tempArr.refresh(); 
 return tempArr[0];
 }
 ]]&gt;
 &lt;/mx:Script&gt;
&lt;/mx:Application&gt;
</code></pre>

According to this example, I order the array from highest to lowest and take the first. Its works perfectly. I hope this helps

Need Help, I have totalA - totalB - totalC - totalD, need to select the highest variable from this 4 but if the highest one equal an other one, must show which variables equals. 

I have used this code but when it meets the equals ( A = B = C ) it dispalys just D

<pre><code>var aNumber:Array = new Array(totalA , totalB , totalC , totalD );

for(var i:Number = 0; i &lt; aNumber.length; i++)
{
 if(aNumber[i] &lt; aNumber[i+1]) 
 {
 bigger = aNumber[i+1];
 }
}
</code></pre>

Actionscript: compare variables from an array

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

需要帮助，我有totalA - totalB - totalC - totalD，需要从这4个变量中选择最高的变量，但如果最高的一个等于另一个，必须显示哪些变量等于。我用过这段代码，但当它满足等于条件(A=B=C)时，它只显示Dvar aNumber:Array = new Array(totalA , totalB ...

问Actionscript:比较数组中的变量
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问Actionscript:比较数组中的变量EN