Python列表按值赋值
Python列表按值赋值
提问于 2016-11-22 00:49:57
我有一个列表撤消和另一个ap，我想保存每次我修改ap列表时撤消的副本，但当我保存时，例如在Undo2上我对ap所做的事情，Undo1与Undo2相同，看起来它分配的是列表ap而不是ap的值。我发现了一个类似的问题，并试图分配ap，这样它就会复制一份，但它没有。
from Functionalitati import *
from Ui import *
from GlobalVr import *
Active = True
NumarApartamente = int(input("Numarul apartamentelor:"))
cntA = 0
while cntA < NumarApartamente:
ap.append({"gaz":{}, "apa":{}, "electricitate":{}, "canalizare":{}, "altele":{}})
cntA = cntA + 1
Undo = Undo + ap[ : ]
while Active:
while True:
op1 = Umenu()
if op1 > 6 and op1 < 0:
print(x,'Nu este o comanda valida')
else:
break
if op1 == 0:
break
op2 = Submenu(op1)
if op1 == 6 and UndoCont > 0:
UndoCont = UndoCont - 1
Undo.pop()
ap = Undo[UndoCont]
print (Undo)
elif op1 == 1 and op2 == 1 :
ap = AddCheltuiala(ap)
Undo = Undo + ap[ : ]
UndoCont = UndoCont + 1
elif op1 == 1 and op2 == 2 :
ap = ModCheltuiala(ap)
Undo.append(ap[0:NumarApartamente - 1])
UndoCont = UndoCont + 1
elif op1 == 2 and op2 == 1 :
ap = DelCheltuiala(ap)
Undo.append(ap[0:NumarApartamente - 1])
UndoCont = UndoCont + 1
elif op1 == 2 and op2 == 2 :
ap = DelCCheltuiala(ap)
Undo.append(ap[0:NumarApartamente - 1])
UndoCont = UndoCont + 1
elif op1 == 2 and op2 == 3 :
ap = DelTip(ap,NumarApartamente)
Undo.append(ap[0:NumarApartamente - 1])
UndoCont = UndoCont + 1我还尝试了append和Undo = Undo + ap，如您所见。如果代码有点乱，很抱歉。编辑:我删除了最后一次编辑，我想让它更清楚，所以我做了另一段代码来继续我想说的话
from Functionalitati import *
from Ui import *
import datetime
ap = [] #lista principala
UndoCont = 0
nrAp = int(input("Da-ti numarul apartamentelor:"))
Undo = [None] * nrAp
contor = 0
while contor < nrAp:
ap.append({"gaz":{}, "apa":{}, "electricitate":{}, "canalizare":{}, "altele":{}})
contor = contor + 1
Undo[0] = ap[:]
print(Undo)
print("space" * 4)
ap[1]["gaz"]["date"] = 100
Undo[1] = ap[:]
print (Undo)输出：
Da-ti numarul apartamentelor:2
[[{'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}, {'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}], None]
spacespacespacespace
[[{'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}, {'gaz': {'date': 100}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}], [{'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}, {'gaz': {'date': 100}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}]]为什么撤消修改为Undo1？我尝试了Undo.append(列表( ap ))和Undo =撤消+列表(Ap)和相同的ap，现在我尝试初始化Undo之前和相同的结果。
回答 1
Stack Overflow用户
发布于 2016-11-22 01:49:19
解决了。我真的不知道它是如何工作的，但我使用copy.deepcopy() (copy.copy()不工作)
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/40725295
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