blocks|key|1962009|text|您可以将CASE表达式与聚合一起使用，以根据outcomeId值获得总计：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1962010|select+companyId,
++sum(case+when+outcomeid+=+36+then+1+else+0+end)+SalesCount,
++sum(case+when+outcomeid+<>+36+then+1+else+0+end)+NonSalesCount
from+yourtable
group+by+companyId;|code-block|syntax|javascript|1962011|请参阅SQL+Fiddle+with+Demo|1962012|entityMap|0|LINK|mutability|MUTABLE|url|http://sqlfiddle.com/#!3/d41d8/15821^0|M|9|0|0|3|K|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|M|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

You can use a CASE expression with your aggregate to get a total based on the <code>outcomeId</code> value:

<pre><code>select companyId,
 sum(case when outcomeid = 36 then 1 else 0 end) SalesCount,
 sum(case when outcomeid &lt;&gt; 36 then 1 else 0 end) NonSalesCount
from yourtable
group by companyId;
</code></pre>

See <a href="http://sqlfiddle.com/#!3/d41d8/15821" rel="noreferrer">SQL Fiddle with Demo</a>

blocks|key|664700|text|如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|664701|SELECT+companyId,
++COUNT(CASE+WHEN+outcomeid+=+36+THEN+1+END)+SalesCount,
++COUNT(CASE+WHEN+outcomeid+<>+36+THEN+1+END)+NonSalesCount
FROM+
++yourtable
GROUP+BY+
++companyId|code-block|syntax|javascript|664702|应该有效--+COUNT()只计算非空值。|offset|length|style|CODE|664703|entityMap^0|0|0|7|7|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Something like this:

<pre><code>SELECT companyId,
 COUNT(CASE WHEN outcomeid = 36 THEN 1 END) SalesCount,
 COUNT(CASE WHEN outcomeid &lt;&gt; 36 THEN 1 END) NonSalesCount
FROM 
 yourtable
GROUP BY 
 companyId
</code></pre>

should work -- <code>COUNT()</code> counts only not null values.

blocks|key|1806320|text|是。Count不计算空值，因此您可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1806321|select
++COUNT('x')+as+Everything,
++COUNT(case+when+OutcomeID+=+36+then+'x'+else+NULL+end)+as+Sales,
++COUNT(case+when+OutcomeID+<>+36+then+'x'+else+NULL+end)+as+Other
from
++YourTable|code-block|syntax|javascript|1806322|或者，您可以使用SUM，就像bluefeet演示的那样。|1806323|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Yes. Count doesn't count NULL values, so you can do this:

<pre><code>select
 COUNT('x') as Everything,
 COUNT(case when OutcomeID = 36 then 'x' else NULL end) as Sales,
 COUNT(case when OutcomeID &lt;&gt; 36 then 'x' else NULL end) as Other
from
 YourTable
</code></pre>

Alternatively, you can use SUM, like bluefeet demonstrated.

blocks|key|1804708|text|SELECT
++++companyId,+SalesCount,+TotalCount-SalesCount+AS+NonSalesCount
FROM
++++(
++++select
++++++companyId,
++++++COUNT(case+when+outcomeid+=+36+then+1+else+NULL+end)+SalesCount,
++++++COUNT(*)+AS+TotalCount
++++from+yourtable
++++group+by+companyId
++++)+X;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1804709|在COUNT(*)中使用这种互斥模式|unstyled|offset|length|style|CODE|1804710|如果COUNT|1804711|gives可以为空，则|unordered-list-item|1804712|可以避免(非常小的)计算第二个条件outcomeid正确值的开销|1804713|1804714|1804715|使用@bluefeet的SQLFiddle并添加NULL|1804716|entityMap|0|LINK|mutability|MUTABLE|url|http://sqlfiddle.com/#!3/d41d8/15823^0|0|1|8|0|2|5|0|0|H|9|0|0|0|C|9|0|0^^$0|@$1|2|3|4|5|6|7|13|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|14|8|@$G|15|H|16|I|J]]|9|@]|A|$]]|$1|K|3|L|5|F|7|17|8|@$G|18|H|19|I|J]]|9|@]|A|$]]|$1|M|3|N|5|O|7|1A|8|@]|9|@]|A|$]]|$1|P|3|Q|5|O|7|1B|8|@$G|1C|H|1D|I|J]]|9|@]|A|$]]|$1|R|3|-4|5|F|7|1E|8|@]|9|@]|A|$]]|$1|S|3|-4|5|F|7|1F|8|@]|9|@]|A|$]]|$1|T|3|U|5|F|7|1G|8|@]|9|@$G|1H|H|1I|1|1J]]|A|$]]|$1|V|3|-4|5|F|7|1K|8|@]|9|@]|A|$]]]|W|$X|$5|Y|Z|10|A|$11|12]]]]

<pre><code>SELECT
 companyId, SalesCount, TotalCount-SalesCount AS NonSalesCount
FROM
 (
 select
 companyId,
 COUNT(case when outcomeid = 36 then 1 else NULL end) SalesCount,
 COUNT(*) AS TotalCount
 from yourtable
 group by companyId
 ) X;
</code></pre>

Using this mutually exclusive pattern with <code>COUNT(*)</code>

<ul>
<li>avoids a (very small) overhead of evaluating a second conditional <code>COUNT</code></li>
<li>gives correct values if <code>outcomeid</code> can be NULL</li>
</ul>

Using @bluefeet's <a href="http://sqlfiddle.com/#!3/d41d8/15823" rel="nofollow">SQLFiddle</a> with added NULLs

blocks|key|4086805|text|已知COUNT()和SUM()仅计算非空值，并遵循以下规则：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4086806|true+or+null+=+true
false+or+null+=+null|code-block|syntax|javascript|4086807|对于胡乱摆弄，您可以接受Taryn的答案，以一种超级肮脏且容易出错的方式完全绕过CASE！|4086808|select+companyId,
++sum(outcomeid+=+36+or+null)+SalesCount,
++sum(outcomeid+<>+36+or+null)+NonSalesCount
from+yourtable
group+by+companyId;|4086809|忘记添加or+null，您将计算所有内容！|4086810|entityMap^0|2|7|A|5|0|0|14|4|0|0|4|7|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|R|$]]

Knowing <code>COUNT()</code> and <code>SUM()</code> only count non-null values and the following rule:
<pre><code>true or null = true
false or null = null
</code></pre>
For fiddling around, you can take Taryn's answer and circumvent <code>CASE</code> altogether in a super-dirty and error-prone way!
<pre><code>select companyId,
 sum(outcomeid = 36 or null) SalesCount,
 sum(outcomeid &lt;&gt; 36 or null) NonSalesCount
from yourtable
group by companyId;
</code></pre>
Forget to add an <code>or null</code> and you'll be counting everything!

I have a table as follows:

<pre><code>CallID | CompanyID | OutcomeID
----------------------------------
1234 | 3344 | 36
1235 | 3344 | 36
1236 | 3344 | 36
1237 | 3344 | 37
1238 | 3344 | 39
1239 | 6677 | 37
1240 | 6677 | 37
</code></pre>

I would like to create a SQL script that counts the number of Sales outcomes and the number of all the other attempts (anything &lt;> 36), something like:

<pre><code>CompanyID | SalesCount | NonSalesCount
------------------------------------------
3344 | 3 | 1
6677 | 0 | 2
</code></pre>

Is there a way to do a COUNT() that contains a condition like COUNT(CallID WHERE OutcomeID = 36)?

SQL: Count() based on column value

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个表，如下：CallID   | CompanyID  | OutcomeID----------------------------------1234     | 3344       | 361235     | 3344       | 361236     | 3344       | 361237     | 3344       | 371238     | 3344     

问SQL:基于列值的Count()
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回答 5

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问SQL:基于列值的Count()
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