Origin localhost: Access-Control-Allow-Origin不允许
Origin localhost: Access-Control-Allow-Origin不允许
提问于 2013-06-30 21:38:31
你好，我正在为我的家庭作业开发一个项目。首先，我知道有很多关于同一问题的标题，我看了很多，但我不能解决这个问题。如果有人能帮我，我会很高兴的。
我的ajax调用是：
function submit(name,surname,source,destination,distance,volume,weight,price){
var xml_string = '<?xml version="1.0" encoding="UTF-8" standalone="yes"?>'+ "<shippingData><FIRSTNAME>" + name + "</FIRSTNAME>"+
"<LASTNAME>" + surname + "</LASTNAME>"+
"<SOURCECITY>" + source + "</SOURCECITY>"+
"<DESTINATIONCITY>" + destination + "</DESTINATIONCITY>"+
"<DISTANCE>" + distance + "</DISTANCE>"+
"<VOLUME>" + volume + "</VOLUME>"+
"<WEIGHT>" + weight + "</WEIGHT>"+
"<PRICE>" + price + "</PRICE>"+
"</shippingData>";
$.ajax({
url: 'http://localhost:8084/ShippingDataService/webresources/generic/post',
type: 'POST',
data: xml_string,
dataType: 'xml',
contentType: 'application/xml',
success: function (data) {
alert("OK");
},
error: function (responseData, textStatus, errorThrown) {
alert('POST failed.');
}
}); }
根据我的作业规则，我必须使用XML来传输数据。我的服务器端是这样的：
@POST
@Consumes(MediaType.APPLICATION_XML)
@Produces(MediaType.APPLICATION_XML)
@Path("post")
public ShippingData postXML(ShippingData content) {
System.out.println("POST");
return content;
}Shippingdata类为：
package ship;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class ShippingData {
public int SID;
@XmlElement (name = "FIRSTNAME")public String firstName;
@XmlElement (name = "LASTNAME")public String lastName;
@XmlElement (name = "SOURCECITY")public String sourceCity;
@XmlElement (name = "DESTINATIONCITY")public String destinationCity;
@XmlElement (name = "DISTANCE")public int distance;
@XmlElement (name = "VOLUME")public int volume;
@XmlElement (name = "WEIGHT")public int weight;
@XmlElement (name = "PRICE")public int price;
public ShippingData() {
}
public ShippingData(int SID, String firstName, String lastName, String sourceCity, String destinationCity, int distance, int volume, int weight, int price) {
this.SID = SID;
this.firstName = firstName;
this.lastName = lastName;
this.sourceCity = sourceCity;
this.destinationCity = destinationCity;
this.distance = distance;
this.volume = volume;
this.weight = weight;
this.price = price;
}
}我还尝试将ajax call url改为'localhost:8084/ShippingDataService/webresources/generic/post'或'/ShippingDataService/webresources/generic/post'，但不起作用。我收到了ajax错误警报，我将其定义为"POST failed“。那么我该如何克服这个问题呢？
回答 1
Stack Overflow用户
回答已采纳
发布于 2013-07-01 01:39:49
你好，我是这样解决问题的：
在web.xml中，将以下内容添加到<servlet></servlet>之间：
<init-param>
<param-name>com.sun.jersey.spi.container.ContainerResponseFilters</param-name>
<param-value>"YOURPACKAGENAME".ResponseCorsFilter</param-value>
</init-param>并将这个类添加到包中
import com.sun.jersey.spi.container.ContainerRequest;
import com.sun.jersey.spi.container.ContainerResponse;
import com.sun.jersey.spi.container.ContainerResponseFilter;
import javax.ws.rs.core.Response;
import javax.ws.rs.core.Response.ResponseBuilder;
public class ResponseCorsFilter implements ContainerResponseFilter {
@Override
public ContainerResponse filter(ContainerRequest req, ContainerResponse contResp) {
ResponseBuilder resp = Response.fromResponse(contResp.getResponse());
resp.header("Access-Control-Allow-Origin", "*")
.header("Access-Control-Allow-Methods", "GET, POST, OPTIONS");
String reqHead = req.getHeaderValue("Access-Control-Request-Headers");
if(null != reqHead && !reqHead.equals("")){
resp.header("Access-Control-Allow-Headers", reqHead);
}
contResp.setResponse(resp.build());
return contResp;
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/17390918
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