我从一个网站上得到了这样的回复。我真的不知道如何解码并获得我想要的信息。
下面是JavaScript的响应:
{header:{code:0,message:{title:"",detail:""}},body:{parameters:{},dataStores:{"kccjStore":{pageSize:100,pageNumber:1,recordCount:3,name:"kccjStore",rowSetName:"pojo_com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel",order:"kclb asc",metaData:{"jxbmc":{dataType:12},"njzypm":{dataType:12},"xh":{dataType:12},"jxbh":{dataType:12},"sftg":{dataType:12},"zzcj":{dataType:12},"cjzt":{dataType:12},"bzw":{dataType:12},"class":{dataType:12},"xs":{dataType:12},"xq":{dataType:12},"jsxm":{dataType:12},"xnd":{dataType:12},"resource_id":{dataType:12},"jxbpm":{dataType:12},"jd":{dataType:12},"kch":{dataType:12},"kcywmc":{dataType:12},"kcmc":{dataType:12},"khfs":{dataType:12},"cjlcId":{dataType:12},"xf":{dataType:12},"kclb":{dataType:12},"zpcj":{dataType:12}},rowSet:{primary:[{"jxbpm":"79\/93","bzw":"00","cjzt":"2","cjlcId":"11895237815","kcywmc":"Mobile Information Engineering Training:Intermediate ","jxbh":"46000092161002","zpcj":"90","resource_id":"11895237815","xnd":"2016-2017","xq":"1","kch":"46000092","kcmc":"移动信息工程实训(中级)","kclb":"11","xf":"3.0","xs":"72.0","zzcj":"90","jd":"4.0","sftg":"1","xh":"14353379","njzypm":"304\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"},{"jxbpm":"74\/128","bzw":"00","cjzt":"2","cjlcId":"12825792491","kcywmc":"Database Systems Lab","jxbh":"46000085161003","jsxm":"桑应朋","khfs":"03","zpcj":"94","resource_id":"12825792491","xnd":"2016-2017","xq":"1","kch":"46000085","kcmc":"数据库系统实验","kclb":"21","xf":"1.0","xs":"36.0","zzcj":"94","jd":"4.4","sftg":"1","xh":"14353379","njzypm":"157\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"},{"jxbpm":"20\/167","bzw":"00","cjzt":"2","cjlcId":"12825622928","kcywmc":"Database Systems","jxbh":"46000084161001","jsxm":"桑应朋","khfs":"01","zpcj":"87","resource_id":"12825622928","xnd":"2016-2017","xq":"1","kch":"46000084","kcmc":"数据库系统","kclb":"21","xf":"2.0","xs":"36.0","zzcj":"87","jd":"3.7","sftg":"1","xh":"14353379","njzypm":"34\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"}]}}}}}我正在使用Python 3.4。下面是我的代码
html_doc = opener.open('http://wjw.sysu.edu.cn/api/score?year=2016-2017&term=1&pylb=01').read().decode('utf-8')提前感谢!
我之前错误地认为这是一个JSON文件,并问了一个糟糕的问题。对此我很抱歉。但是谢谢你帮我!希望你们中的一些人能帮助我回答我的新问题!
发布于 2017-01-17 13:19:16
您的输入有几个问题:
{.demjson.)将这些对象解析到python字典中
>>> import demjson
>>> parsed = demjson.decode('{header:{code:0,message:{title:"",detail:""}}}')
>>> parsed
{u'header': {u'message': {u'detail': '', u'title': ''}, u'code': 0}}话虽如此,您最初使用json.loads的直觉通常是正确的。如果你对你的输入有任何控制(例如,如果它是你可以重写的API或脚本的输出),你应该重写它来输出严格的JSON,使它可以被json.loads解析。
发布于 2017-01-17 12:43:12
看起来您的数据不是严格意义上的JSON,因为有些键不是字符串。
此外,似乎缺少一个匹配的大括号--应该添加为第一个字符,
{header:{code:0,message:{title:"",detail:""}},body:{parameters:{},dataStores:{"kccjStore":{pageSize:100,pageNumber:1,recordCount:3,name:"kccjStore",rowSetName:"pojo_com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel",order:"kclb asc",metaData:{"jxbmc":{dataType:12},"njzypm":{dataType:12},"xh":{dataType:12},"jxbh":{dataType:12},"sftg":{dataType:12},"zzcj":{dataType:12},"cjzt":{dataType:12},"bzw":{dataType:12},"class":{dataType:12},"xs":{dataType:12},"xq":{dataType:12},"jsxm":{dataType:12},"xnd":{dataType:12},"resource_id":{dataType:12},"jxbpm":{dataType:12},"jd":{dataType:12},"kch":{dataType:12},"kcywmc":{dataType:12},"kcmc":{dataType:12},"khfs":{dataType:12},"cjlcId":{dataType:12},"xf":{dataType:12},"kclb":{dataType:12},"zpcj":{dataType:12}},rowSet:{primary:[{"jxbpm":"79\/93","bzw":"00","cjzt":"2","cjlcId":"11895237815","kcywmc":"Mobile Information Engineering Training:Intermediate ","jxbh":"46000092161002","zpcj":"90","resource_id":"11895237815","xnd":"2016-2017","xq":"1","kch":"46000092","kcmc":"移动信息工程实训(中级)","kclb":"11","xf":"3.0","xs":"72.0","zzcj":"90","jd":"4.0","sftg":"1","xh":"14353379","njzypm":"304\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"},{"jxbpm":"74\/128","bzw":"00","cjzt":"2","cjlcId":"12825792491","kcywmc":"Database Systems Lab","jxbh":"46000085161003","jsxm":"桑应朋","khfs":"03","zpcj":"94","resource_id":"12825792491","xnd":"2016-2017","xq":"1","kch":"46000085","kcmc":"数据库系统实验","kclb":"21","xf":"1.0","xs":"36.0","zzcj":"94","jd":"4.4","sftg":"1","xh":"14353379","njzypm":"157\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"},{"jxbpm":"20\/167","bzw":"00","cjzt":"2","cjlcId":"12825622928","kcywmc":"Database Systems","jxbh":"46000084161001","jsxm":"桑应朋","khfs":"01","zpcj":"87","resource_id":"12825622928","xnd":"2016-2017","xq":"1","kch":"46000084","kcmc":"数据库系统","kclb":"21","xf":"2.0","xs":"36.0","zzcj":"87","jd":"3.7","sftg":"1","xh":"14353379","njzypm":"34\/403","class":"class com.neusoft.education.sysu.xscj.xscjcx.model.KccjModel"}]}}}}}Here是指向w3学校的JSON参考的链接。
Here是一个JSON格式化/验证器。
发布于 2017-01-17 13:33:54
如果你不想使用第三方库,你可以使用正则表达式自己清理数据(例如。向剩余属性添加双引号):
import re
import json
text = # the input string
p = re.compile(r'({|,)([^{}:"]+):')
text = p.sub(r'\1"\2":', '{' + text)
obj = json.loads(text)https://stackoverflow.com/questions/41689107
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