有没有可能以某种方式配置捆绑包来生成也用于视网膜显示的图像,如@2x?
或者有人能给我一个如何处理视网膜的建议?
谢谢
发布于 2017-02-15 21:46:29
根据nahakiole的this comment,有两种解决方案:
您可以使用图片元素,该元素提供了为一个图像声明多个源的语法。http://w3c.github.io/html/semantics-embedded-content.html#the-picture-element
我们尝试过的另一种方法是,如果你能保证图像存在,使用retina.js的修改版本,将_retina添加到过滤器名称,并检查是否存在具有该名称的图像。
nahakiole的Modified version of retina.js
/*-----------------------------------------------------------------------------------*/
/* RETINA.JS
/*-----------------------------------------------------------------------------------*/
(function () {
var regex = /(media\/cache\/filter_[A-Z]+)/i //Added this
function t(e) {
this.path = e;
var t = this.path.split("."),
n = t.slice(0, t.length - 1).join("."),
r = t[t.length - 1];
this.at_2x_path = (n + '.' + r).replace(regex, '$1_retina') //Changed that
}
function n(e) {
this.el = e, this.path = new t(this.el.getAttribute("src"));
var n = this;
this.path.check_2x_variant(function (e) {
e && n.swap()
})
}
var e = typeof exports == "undefined" ? window : exports;
e.RetinaImagePath = t, t.confirmed_paths = [], t.prototype.is_external = function () {
return !!this.path.match(/^https?\:/i) && !this.path.match("//" + document.domain)
}, t.prototype.check_2x_variant = function (e) {
var n, r = this;
if (this.is_external()) return e(!1);
if (this.at_2x_path in t.confirmed_paths) return e(!0);
n = new XMLHttpRequest, n.open("HEAD", this.at_2x_path), n.onreadystatechange = function () {
return n.readyState != 4 ? e(!1) : n.status >= 200 && n.status <= 399 ? (t.confirmed_paths.push(r.at_2x_path), e(!0)) : e(!1)
}, n.send()
}, e.RetinaImage = n, n.prototype.swap = function (e) {
function n() {
t.el.complete ? (t.el.setAttribute("width", t.el.offsetWidth), t.el.setAttribute("height", t.el.offsetHeight), t.el.setAttribute("src", e)) : setTimeout(n, 5)
}
typeof e == "undefined" && (e = this.path.at_2x_path);
var t = this;
n()
}, e.devicePixelRatio > 1 && (window.onload = function () {
var e = document.getElementsByTagName("img"),
t = [],
r, i;
for (r = 0; r < e.length; r++) i = e[r], t.push(new n(i))
})
})();
https://stackoverflow.com/questions/42250029
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