意外响应代码400？
意外响应代码400？
提问于 2017-02-16 13:46:17
我正在使用Volley库，并有意外响应代码400的问题。我试图从用户名和密码登录，但面对com.android.volley.ServerError.How，这可以解决吗？
登录类
public class Login extends AppCompatActivity implements View.OnClickListener {
EditText userName, Password;
Button login;
public static final String LOGIN_URL = "http://192.168.0.106:84/Token";
public static final String KEY_USERNAME = "UserName";
public static final String KEY_PASSWORD = "Password";
String username, password;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
userName = (EditText) findViewById(R.id.login_name);
Password = (EditText) findViewById(R.id.login_password);
userName.setHint(Html.fromHtml("<font color='#008b8b' style='italic'>Username</font>"));
Password.setHint(Html.fromHtml("<font color='#008b8b'>Password</font>"));
login = (Button) findViewById(R.id.login);
login.setOnClickListener(this);
}
private void UserLogin() {
username = userName.getText().toString().trim();
password = Password.getText().toString().trim();
StringRequest stringRequest = new StringRequest(com.android.volley.Request.Method.POST, LOGIN_URL,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
if (response.trim().equals("success")) {
openProfile();
} else {
Toast.makeText(Login.this, response, Toast.LENGTH_LONG).show();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(Login.this, error.toString(), Toast.LENGTH_LONG).show();
}
}) {
@Override
public Map<String, String> getHeaders() throws AuthFailureError {
HashMap<String, String> params = new HashMap<String, String>();
params.put("Content-Type", "application/x-www-form-urlencoded");
params.put("Charset", "UTF-8");
return params;
}
@Override
public Map<String, String> getParams() throws AuthFailureError {
HashMap<String, String> map = new HashMap<String, String>();
map.put(KEY_USERNAME, username);
map.put(KEY_PASSWORD, password);
return map;
}
};
RequestQueue requestQueue = Volley.newRequestQueue(this);
requestQueue.add(stringRequest);
}
private void openProfile() {
Intent intent = new Intent(this, Home.class);
intent.putExtra(KEY_USERNAME, username);
startActivity(intent);
}
@Override
public void onClick(View v) {
UserLogin();
}
public String getBodyContentType() {
return "application/xml";
}
}如何解决这个问题？
删除标题后，我得到了这个。
回答 1
Stack Overflow用户
发布于 2017-02-16 18:48:38
尝试使用POST方法编写此代码
final String URL = Vcruit.getInstance().GET_LOGIN;
// Post params to be sent to the server
HashMap<String, String> params = new HashMap<String, String>();
params.put("apikey", xxx.getInstance().API_KEY);
params.put("userName", Username);
params.put("password", Password);
JsonObjectRequest req = new JsonObjectRequest(URL, new JSONObject(params),
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
VolleyLog.v("Response:%n %s", response.toString(4));
JSONObject jObj = new JSONObject(response.toString());
JSONArray results = jObj.getJSONArray("data");
for (int i = 0; i < results.length(); i++) {
JSONObject cat = results.getJSONObject(i);
String status = cat.getString("status");
String errormsg = cat.getString("ErrorMsg");
if (status.equals("Success")) {
} else {
}
}
} catch (JSONException e) {
e.printStackTrace();
}
loader.setVisibility(View.GONE);
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.e("Error: ", error.getMessage());
}
});
xxx.getInstance().addToRequestQueue(req);
}https://www.simplifiedcoding.net/android-studio-volley-tutorial-to-create-a-login-application/
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/42265922
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