blocks|key|4145246|text|请使用以下代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4145247|$resultArray+=+array(
++++0+=>+current($newDates)+%2B+current($cleanNums)
);

print_r($resultArray);|code-block|syntax|javascript|4145248|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Please use this code:

<pre><code>$resultArray = array(
 0 =&gt; current($newDates) + current($cleanNums)
);

print_r($resultArray);
</code></pre>

blocks|key|4145272|text|http://php.net/manual/en/function.array-merge.php中的array_merge就是这样做的。不正确输出的原因在于您定义变量的方式，例如|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4145273|$cleanNums[]+=+array(...)|4145274|将导致嵌套数组：|4145275|array(1)+{
++[0]=>
++array(5)+{
+++...
++}
}|code-block|syntax|javascript|4145276|要避免这种情况，请更改赋值的方式：|4145277|$cleanNums+=+array(...)|4145278|或者如何将其作为array_merge参数提供：|4145279|$weeklyValues+=+array_merge($newDates[0],$cleanNums[0]);|4145280|当然，同样的情况也需要应用于$newDates。|4145281|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.array-merge.php^0|1F|B|0|1D|0|0|0|P|0|0|0|0|0|8|B|0|0|E|9|0^^$0|@$1|2|3|4|5|6|7|16|8|@$9|17|A|18|B|C]]|D|@$9|19|A|1A|1|1B]]|E|$]]|$1|F|3|G|5|6|7|1C|8|@$9|1D|A|1E|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|1F|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|1G|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|1H|8|@]|D|@]|E|$]]|$1|Q|3|R|5|L|7|1I|8|@]|D|@]|E|$M|N]]|$1|S|3|T|5|6|7|1J|8|@$9|1K|A|1L|B|C]]|D|@]|E|$]]|$1|U|3|V|5|L|7|1M|8|@]|D|@]|E|$M|N]]|$1|W|3|X|5|6|7|1N|8|@$9|1O|A|1P|B|C]]|D|@]|E|$]]|$1|Y|3|-4|5|6|7|1Q|8|@]|D|@]|E|$]]]|Z|$10|$5|11|12|13|E|$14|15]]]]

the <code>array_merge</code> is the way to do it <a href="http://php.net/manual/en/function.array-merge.php" rel="nofollow noreferrer">http://php.net/manual/en/function.array-merge.php</a>. The reason for incorrect output is in the way you define variables e.g. 

<code>$cleanNums[] = array(...)</code>

Will result in nested array:

<pre><code>array(1) {
 [0]=&gt;
 array(5) {
 ...
 }
}
</code></pre>

To avoid it either change the way of the assignment:

<pre><code>$cleanNums = array(...)
</code></pre>

Or the way how you provide it as <code>array_merge</code> parameters:

<pre><code>$weeklyValues = array_merge($newDates[0],$cleanNums[0]);
</code></pre>

The same needs to be applied for <code>$newDates</code> of course.

blocks|key|1516222|text|我假设$cleanNums和$newDates是多维数组，会得到更多的[]值；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1516223|$weeklyValues+=+array();

foreach($cleanNums+as+$array)
{
++++$weeklyValues+=+array_merge($weeklyValues,$array);
}

foreach($newDates+as+$array)
{
++++$weeklyValues+=+array_merge($weeklyValues,$array);
}

print_r($weeklyValues);|code-block|syntax|javascript|1516224|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I'm assuming $cleanNums and $newDates are multidimensional arrays and will get more [] values;

<pre><code>$weeklyValues = array();

foreach($cleanNums as $array)
{
 $weeklyValues = array_merge($weeklyValues,$array);
}

foreach($newDates as $array)
{
 $weeklyValues = array_merge($weeklyValues,$array);
}

print_r($weeklyValues);
</code></pre>

blocks|key|5613739|text|$count+=+count($newDates);
$mergedArray+=+array();
for($i=0;+$i+<+$count;+$i%2B%2B){
+++//assuming+both+arrays+have+equal+number+of+records
+++$mergedArray[]+=+current($newDates[$i])+%2B+current($cleanNums[$i]);
}
var_dump($mergedArray);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|5613740|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$count = count($newDates);
$mergedArray = array();
for($i=0; $i &lt; $count; $i++){
 //assuming both arrays have equal number of records
 $mergedArray[] = current($newDates[$i]) + current($cleanNums[$i]);
}
var_dump($mergedArray);
</code></pre>

I have two arrays and I would like to join them. Both arrays are a product of a foreach loop. The first one being:

<pre><code>$cleanNums[] = array(
 '01'=&gt;$numbers[1],
 '02'=&gt;$numbers[2],
 '03'=&gt;$numbers[3],
 '04'=&gt;$numbers[4],
 '05'=&gt;$numbers[5],
 );
</code></pre>

and the second one being:

<pre><code>$newDates[] = array(
 'day'=&gt;$cleanDate[1],
 'month'=&gt;$cleanDate[2],
 'year'=&gt;$cleanDate[3],
 'draw'=&gt;$cleanDate[6],
 );
</code></pre>

Using array_merge <code>$weeklyValues = array_merge($newDates,$cleanNums);</code> I'm getting:

<pre><code>Array
(
 [0] =&gt; Array
 (
 [day] =&gt; 1st
 [month] =&gt; March
 [year] =&gt; 2017
 [draw] =&gt; 660
 )

 [1] =&gt; Array
 (
 [01] =&gt; 3
 [02] =&gt; 23
 [03] =&gt; 40
 [04] =&gt; 20
 [05] =&gt; 28
 )
)
</code></pre>

I would like my output to read as follows:

<pre><code>Array
(
 [0] =&gt; Array
 (
 [day] =&gt; 1st
 [month] =&gt; March
 [year] =&gt; 2017
 [draw] =&gt; 660
 [01] =&gt; 3
 [02] =&gt; 23
 [03] =&gt; 40
 [04] =&gt; 20
 [05] =&gt; 28
 )
)
</code></pre>

PHP join two multidimensional arrays

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有两个数组，我想加入它们。这两个数组都是foreach循环的产物。第一个是：$cleanNums[] = array(    '01'=>$numbers[1],    '02'=>$numbers[2],    '03'=>$numbers[3],    '04'=>$numbers[4],    '05'=>$n...

问PHP连接两个多维数组
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