使用MapStruct将2个字符串字段映射到OffsetDateTime
使用MapStruct将2个字符串字段映射到OffsetDateTime
提问于 2020-01-07 01:44:47
我有下面的DTO，其中有2个字段，必须转换为OffsetDateTime：
@Data
public class AppointmentDTO {
private String id;
@NotNull
private String startTime;
@NotNull
private String endTime;
@NotNull
private String timeZoneStart;
@NotNull
private String timeZoneEnd;
// other fields
} 至
@Data
@Document
@NoArgsConstructor
@AllArgsConstructor
public class Appointment {
@Id
private String id;
private String timeZoneStart;
private String timeZoneEnd;
private OffsetDateTime startTime;
private OffsetDateTime endTime;
private OffsetDateTime createdTime;
// other fields
}为了进行转换，我需要DTO的timeZone字段加上一个DateTimeFormatter。所以，我的尝试是：
@Component
@Mapper(componentModel = "spring")
public interface IAppointmentMapper {
@Mapping(target = "createdTime", ignore = true)
Appointment convertAppointmentDTOToAppointment(AppointmentDTO dto, @Context OffsetDateTimeMapper offsetDateTimeMapper);
}public class OffsetDateTimeMapper {
private String startTime;
private String endTime;
private String timeZoneStart;
private String timeZoneEnd;
private final DateTimeFormatter dateTimeFormatter;
public OffsetDateTimeMapper(DateTimeFormatter dateTimeFormatter) {
this.dateTimeFormatter = dateTimeFormatter;
}
@BeforeMapping
public void beforeStartTimeMapping(AppointmentDTO dto) {
this.startTime = dto.getStartTime();
this.timeZoneStart = dto.getTimeZoneStart();
}
@BeforeMapping
public void beforeEndTimeMapping(AppointmentDTO dto) {
this.endTime = dto.getEndTime();
this.timeZoneEnd = dto.getTimeZoneEnd();
}
@AfterMapping
public void startTimeMap(@MappingTarget Appointment appointment) {
LocalDateTime localDateTime = LocalDateTime.parse(startTime, dateTimeFormatter);
ZonedDateTime zonedDateTime = localDateTime.atZone(ZoneId.of(timeZoneStart));
appointment.setStartTime(zonedDateTime.toOffsetDateTime());
}
@AfterMapping
public void endTimeMap(@MappingTarget Appointment appointment) {
LocalDateTime localDateTime = LocalDateTime.parse(endTime, dateTimeFormatter);
ZonedDateTime zonedDateTime = localDateTime.atZone(ZoneId.of(timeZoneEnd));
appointment.setEndTime(zonedDateTime.toOffsetDateTime());
}
}然而，当我构建时，我得到了以下错误：Error:(22,17) java: Can't map property "java.lang.String startTime" to "java.time.OffsetDateTime startTime". Consider to declare/implement a mapping method: "java.time.OffsetDateTime map(java.lang.String value)".如果我把一个default map()方法放在接口上，我没有得到这个错误，但是我没有正确的所需的@Context。
/*default OffsetDateTime map(String value) {
LocalDateTime localDateTime = LocalDateTime.parse(value);
ZonedDateTime zonedDateTime = localDateTime.atZone(ZoneOffset.UTC);
return zonedDateTime.toOffsetDateTime();
}*/回答 1
Stack Overflow用户
回答已采纳
发布于 2020-01-15 03:03:30
你的方法很有趣。为了正常工作，您必须显式地忽略您不希望MapStruct自动映射的属性。
在这种情况下，添加：
@Mapping(target = "startTime", ignore = true)
@Mapping(target = "endTime", ignore = true)但是，在您的示例中，我会尝试使用Mapping method selection based on qualifiers，并使用源参数作为源。
所以就像这样：
@Component
@Mapper(componentModel = "spring")
public interface IAppointmentMapper {
@Mapping(target = "createdTime", ignore = true)
@Mapping(target = "startTime", source = "dto", qualifiedByName = "startTime")
@Mapping(target = "endTime", source = "dto", qualifiedByName = "endTime")
Appointment convertAppointmentDTOToAppointment(AppointmentDTO dto, @Context DateTimeFormatter dateTimeFormatter);
@Named("startTime")
default OffsetDateTime mapStartTime(AppointmentDTO dto, @Context DateTimeFormatter dateTimeFormatter) {
LocalDateTime localDateTime = LocalDateTime.parse(dto.getStartTime(), dateTimeFormatter);
ZonedDateTime zonedDateTime = localDateTime.atZone(ZoneId.of(dto. getTimeZoneStart()));
return zonedDateTime.toOffsetDateTime()
}
@Named("endTime")
default OffsetDateTime mapEndTime(AppointmentDTO dto, @Context DateTimeFormatter dateTimeFormatter) {
LocalDateTime localDateTime = LocalDateTime.parse(dto.getEndTime(), dateTimeFormatter);
ZonedDateTime zonedDateTime = localDateTime.atZone(ZoneId.of(dto. getTimeZoneEnd()));
return zonedDateTime.toOffsetDateTime()
}
}注：@Named为org.mapstruct.Named。
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原文链接：
https://stackoverflow.com/questions/59616631
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