blocks|key|1271780|text|变量'pres‘在第二个循环的第17行被重置(它将遍历索引0-3并覆盖之前的4个主席)。为了快速解决问题，可以同时尝试第17行的names[pres+%2B+4]+=+input()和第6行的names+=+[""]+*+8|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1271781|entityMap^0|1S|P|2M|G|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

The variable 'pres' gets reset in the second loop at line 17 (it will loop over indices 0-3 and overwrite the previous 4 presidents). For a quick fix maybe try both <code>names[pres + 4] = input()</code> at line 17 and <code>names = [""] * 8</code> at line 6

blocks|key|5628599|text|for+pres+in+range(president):
++++print('Enter+the+name+of+a+president',sep='',end='')
++++names[pres]+=+input()
++++names.sort()
++++print(names)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|5628600|您不需要在每次添加新总裁时都执行names.sort()。如果你想添加4个总裁，那就添加它。排序是最后一步，对吧？|unstyled|offset|length|style|CODE|5628601|在第二个循环中，使用相同的索引添加另一个总裁。这将改变你列表中的元素，你仍然只有4个总裁，不会更多。我的建议是使用|5628602|new_president+=+input()
names.append(new_president)|5628603|而不是|5628604|names[pres]+=+input()|5628605|下面是我的完整代码：|5628606|def+create_presidents(no_presidents=4):
++++presidents+=+[]
++++for+_+in+range(no_presidents):
++++++++presidents.append(input("Enter+a+name:+"))
++++#+More+presidents
++++for+_+in+range(no_presidents):
++++++++presidents.append(input("Enter+another+name:+"))
++++presidents.sort()
++++return+presidents

def+print_presidents(presidents):
++++for+president+in+presidents:
++++++++print(president)

if+__name__+==+"__main__":
++++no_presidents+=+4
++++presidents+=+create_presidents(no_presidents)
++++print_presidents(presidents)+++|5628607|entityMap^0|0|G|C|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|Z|8|@$G|10|H|11|I|J]]|9|@]|A|$]]|$1|K|3|L|5|F|7|12|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|13|8|@]|9|@]|A|$B|C]]|$1|O|3|P|5|F|7|14|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|15|8|@]|9|@]|A|$B|C]]|$1|S|3|T|5|F|7|16|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|17|8|@]|9|@]|A|$B|C]]|$1|W|3|-4|5|F|7|18|8|@]|9|@]|A|$]]]|X|$]]

<pre><code>for pres in range(president):
 print('Enter the name of a president',sep='',end='')
 names[pres] = input()
 names.sort()
 print(names)
</code></pre>

You don't need to do <code>names.sort()</code> every time you add a new president to it. If you want to add 4 presidents, then add it. Sorting is the last step, right?

In your second loop, you use the same index to add another president. This will change your elements in your list and you will still have 4 presidents, no more. My suggestion is to use 

<pre><code>new_president = input()
names.append(new_president)
</code></pre>

instead of

<pre><code>names[pres] = input()
</code></pre>

Here is my full code:

<pre><code>def create_presidents(no_presidents=4):
 presidents = []
 for _ in range(no_presidents):
 presidents.append(input("Enter a name: "))
 # More presidents
 for _ in range(no_presidents):
 presidents.append(input("Enter another name: "))
 presidents.sort()
 return presidents

def print_presidents(presidents):
 for president in presidents:
 print(president)

if __name__ == "__main__":
 no_presidents = 4
 presidents = create_presidents(no_presidents)
 print_presidents(presidents) 
</code></pre>

blocks|key|1271824|text|我甚至比我刚开始的时候更困惑：Huy+vo，我认为默认情况下，4个总统的名字应该在列表中，然后用户激励并添加4个其他的人到该列表中，然后它应该显示该列表。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1271825|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

im even more confused than when i started now :(. Huy vo, i think 4 presidents names are supposed to be in the list by default then the user insputs and adds 4 others to that list then its supposed to display the list.

I am writing a program that contains a list holding the names of four USA presidents. Use any presidents you wish. Then, run a loop that adds four more presidents to the list. Call another function with the list as its sole argument. This second function should sort the list and then loop through the list to print each president's name on its own line. I have some code done but it only prints the list of the first set of names. I can't figure out how to get the names sorted and print all the names entered in the list. 

Here is my code: 

<pre><code>president = 4

def main():

 names = [0] * president

 for pres in range(president):
 print('Enter the name of a president',sep='',end='')
 names[pres] = input()
 names.sort()
 print(names)


 for pres in range(president):
 print('Enter the name of another president',sep='',end='')
 names[pres] = input()


def names(name_list):
 name_list.sort()
 return name_list
</code></pre>

Print a list of names with function a sole argument

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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问使用函数作为唯一参数打印名称列表
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