blocks|key|162509|text|尝试使用以下正则表达式(使用)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|162510|@(?!author%7CAutowired%7COverride%7Cparam%7CSuppressWarnings).*|code-block|syntax|javascript|162511|请参阅|162512|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Try using the following regex (using <a href="http://www.regular-expressions.info/lookaround.html" rel="noreferrer">negative look-ahead</a>) :

<pre><code>@(?!author|Autowired|Override|param|SuppressWarnings).*
</code></pre>

see <a href="https://regex101.com/r/8OGr9F/1" rel="noreferrer">regex demo / explanation</a>

blocks|key|5022794|text|你可以使用负向先行：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5022795|@(?!author%7CAutowired%7COverride%7Cparam%7CSuppressWarnings)\S%2B|code-block|syntax|javascript|5022796|基本上，它查找后跟该单词列表的@为而不是，然后匹配其后的任何非空格字符。|offset|length|style|CODE|BOLD|5022797|entityMap^0|0|0|F|1|H|3|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Q|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|R|8|@$I|S|J|T|K|L]|$I|U|J|V|K|M]]|9|@]|A|$]]|$1|N|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|O|$]]

You can use a negative lookahead:

<pre><code>@(?!author|Autowired|Override|param|SuppressWarnings)\S+
</code></pre>

Basically, it looks for a <code>@</code> that is not followed by that list of words, and then it matches any non-whitespace characters after that.

blocks|key|2908345|text|要反转脚本，如果您实际上正在尝试获取文本文件并删除关键字列表中的内容，您可能希望找到使用以下语法的关键字：@(author%7CAutoWired%7COverride%7Cparam%7CSuppressWarnings)\b。终端\b只是为了避免@authority或其他不可能发生的情况而采取的预防措施。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2908346|entityMap^0|1H|1H|31|2|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

To flip the script, if you're actually trying to take the text file and remove things that are in your list of keywords, you'll probably want to find those using syntax more like this: <code>@(author|AutoWired|Override|param|SuppressWarnings)\b</code>. The terminal <code>\b</code> is just a precaution to avoid @authority or other unlikelihoods.

blocks|key|2908362|text|正则表达式中的方括号用于字符类。当您将一组字符放在方括号中时，这与列出的字符之一的one+character匹配。所以|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|2908363|[author]|code-block|syntax|javascript|2908364|匹配一个字符(如果它是a、h、o、r、t或u+)。它不查找单词author。将%5E放在前面还会查找一个不在列表中的字符：|CODE|2908365|[%5Eauthor]|2908366|匹配一个字符，只要它不是a、h、o、r、t或u。|2908367|但这里的关键是[]不能用于匹配单词或其他序列。在您的示例中，|2908368|@[%5E(author)(Autowired)(Override)(param)(SuppressWarnings)].*|2908369|方括号中的部分匹配一个字符，该字符不是(、a、u或方括号中出现的任何其他字符(其中许多字符出现多次，但这不会影响任何内容)。|2908370|entityMap^0|15|D|0|0|B|1|D|1|F|1|H|1|J|1|L|1|V|6|13|1|0|0|C|1|E|1|G|1|I|1|K|1|M|1|0|7|2|0|0|J|1|L|1|N|1|0^^$0|@$1|2|3|4|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@$9|14|A|15|B|M]|$9|16|A|17|B|M]|$9|18|A|19|B|M]|$9|1A|A|1B|B|M]|$9|1C|A|1D|B|M]|$9|1E|A|1F|B|M]|$9|1G|A|1H|B|M]|$9|1I|A|1J|B|M]]|D|@]|E|$]]|$1|N|3|O|5|H|7|1K|8|@]|D|@]|E|$I|J]]|$1|P|3|Q|5|6|7|1L|8|@$9|1M|A|1N|B|M]|$9|1O|A|1P|B|M]|$9|1Q|A|1R|B|M]|$9|1S|A|1T|B|M]|$9|1U|A|1V|B|M]|$9|1W|A|1X|B|M]]|D|@]|E|$]]|$1|R|3|S|5|6|7|1Y|8|@$9|1Z|A|20|B|M]]|D|@]|E|$]]|$1|T|3|U|5|H|7|21|8|@]|D|@]|E|$I|J]]|$1|V|3|W|5|6|7|22|8|@$9|23|A|24|B|M]|$9|25|A|26|B|M]|$9|27|A|28|B|M]]|D|@]|E|$]]|$1|X|3|-4|5|6|7|29|8|@]|D|@]|E|$]]]|Y|$]]

Square brackets in regexes are used for character classes. When you put a list of characters in square brackets, this matches one character that is one of the ones listed. So

<pre><code>[author]
</code></pre>

matches one character, if it's <code>a</code>, <code>h</code>, <code>o</code>, <code>r</code>, <code>t</code>, or <code>u</code>. It does not look for the word <code>author</code>. Putting <code>^</code> in front also looks for one character that isn't in the list:

<pre><code>[^author]
</code></pre>

matches one character as long as it's not <code>a</code>, <code>h</code>, <code>o</code>, <code>r</code>, <code>t</code>, or <code>u</code>.

But the key thing here is that <code>[]</code> cannot be used to match words or other sequences. In your example,

<pre><code>@[^(author)(Autowired)(Override)(param)(SuppressWarnings)].*
</code></pre>

the part in square brackets matches one character that is not <code>(</code>, <code>a</code>, <code>u</code>, or any of the other characters that appear in the square brackets (many of those characters appear multiple times, but that doesn't affect anything).

I am looking for a regex expression that will exclude the below words from a huge text file/files.

<pre><code>@author
@Autowired
@Override
@param
@SuppressWarnings
</code></pre>

I have tried with this but does not work as expected.

<pre><code>@[^(author)(Autowired)(Override)(param)(SuppressWarnings)].*
</code></pre>

Regex does not contain certain words

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在寻找一个正则表达式，将排除一个巨大的文本文件/文件中的以下单词。@author@Autowired@Override@param@SuppressWarnings我已经尝试过了，但没有像预期的那样工作。@[^(author)(Autowired)(Override)(param)(SuppressWarnings...

问正则表达式不包含某些单词
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问正则表达式不包含某些单词EN