简单单元测试-解析无效输入以抛出错误C# Visual Studio
简单单元测试-解析无效输入以抛出错误C# Visual Studio
提问于 2017-05-05 11:13:12
我有一个非常基本的方法，可以将两个双精度值相除。对于单元测试，我希望包含一个无效的输入(字符串)来抛出错误消息或异常。解析值或测试失败(预期)的最简单方法是什么？
CalculatorClass.cs
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace Calculator
{
public class CalculatorClass
{
//METHODS
public double Divide(double num1, double num2)
{
double result = num1 / num2;
return result;
}
}
}UnitTest1.cs
using System;
using Calculator; //ADD REFERENCE
using Microsoft.VisualStudio.TestTools.UnitTesting;
namespace CalcMethodTest
{
//AreEqual
//AreNotEqual
//AreNotSame
//AreSame
//Equals
//Fail
//Inconclusive
//IsFalse
//IsInstanceOfType
//IsNotNull
//IsNull
//IsTrue
//ReplaceNullChars
[TestClass]
public class UnitTest1
{
[TestMethod]
public void _1_3_Test_Divide_Input_Seven_2_Output_Error()
{
//ARRANGE
CalculatorClass calcObj = new CalculatorClass();
string expectedOutput = "Error - Invalid Input";
//ACT
//----HERE WRONG DATA TYPE FOR TESTING----
double result = calcObj.Divide("Seven", 2);
//ASSERT
Assert.AreEqual(expectedOutput, result);
}
}
}Stack Overflow用户
发布于 2017-05-05 12:01:53
这似乎起作用了：
[TestMethod]
public void _1_3_Test_Divide_Input_Seven_2_Output_Error()
{
//ARRANGE
CalculatorClass calcObj = new CalculatorClass();
string expectedOutput = "Error - Invalid Input";
//ACT
//----CHANGED TO STRING. THEN CAST BACK TO DOUBLE INSIDE METHOD----
string result = calcObj.Divide("Seven", "2");
//ASSERT
Assert.AreEqual(expectedOutput, result);
}方法：
public string Divide(string num1, string num2)
{
string resultMsg = "";
try
{
double num1Dbl = double.Parse(num1);
double num2Dbl = double.Parse(num2);
double result = num1Dbl / num2Dbl;
resultMsg = result.ToString();
return resultMsg;
}
catch (FormatException error)
{
resultMsg = "Error - Invalid Input";
return resultMsg;
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/43795909
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