以函数为参数的Case类
以函数为参数的Case类
提问于 2017-05-29 00:12:12
我定义了3个案例类，如下所示：
case class Func1(inputA: HashMap[String, String], mapFn: (String, String) => List[(String, Int)], redFn: (String, List[Int]) => (String, Int))
case class Func2(inputB: HashMap[String, String], mapFn: (String, String) => List[(String, String)], redFn: (String, List[String]) => (String, List[String]))
case class Func3(inputC: HashMap[String, String], mapFn: (String, String) => List[(String, String)], redFn: (String, List[String]) => (String, Int)) 在receive方法中，我有与上面匹配的相应案例：
case Func1(inputA, mapFn, redFn) => // Do something
case Func2(inputB, mapFn, redFn) => // Do something
case Func3(inputC, mapFn, redFn) => // Do something是否可以用一个通用的case类替换这3个case类？
我尝试了以下几种方法：
我将case类定义如下：
case class Func[K, V, X, Y, U](input: HashMap[K, V], mapFn: (K, V) => List[(X, Y)], redFun: (X, List[Y]) => (X, U))然后，在MyActor类的接收方法中，我有：
case Func[K, V, X, Y, U](input: HashMap[K, V], mapFn: (K, V) => List[(X, Y)], redFun: (X, List[Y]) => (X, U)) => //code here编译错误如下所示。第一个错误指示错误位于mapFn: (K,V) => List[(X,Y)]中的=>
')' expected but '=>' found.
[error] case MapIt[K, V, X, Y, U](input: HashMap[K, V], mapFn: (K,V) => List[(X, Y)], redFun: (X, List[Y]) => (X, U)) =>第二个错误表明问题出在"mapFn：(K，V) => List(X，Y)“的最后一个方括号中(逗号之前)。
'=>' expected but ']' found.
[error] case Func[K, V, X, Y, U](input: HashMap[K, V], mapFn: (K, V) => List[(X, Y)], redFun: (X, List[Y]) => (X, U)) =>Stack Overflow用户
发布于 2017-05-29 15:54:23
如果这有帮助，请告诉我。
case class FuncG[K, V, X, Y, U](input: HashMap[K, V], mapFn: (K, V) => List[(X, Y)], redFun: (X, List[Y]) => (X, U))
val firstParam: HashMap[String, String] = HashMap("test key" -> "test value")
def mapfn1(a1:String, a2:String):List[(String, Int)] = List(("val1",4))
def mapfn2(a1:String, a2:String):List[(String, String)] = List(("val2","val3"))
def redfn1(r1:String, r2:List[Int]):(String, Int) = ("val4",56)
def redfn2(r1:String, r2:List[String]):(String, List[String]) = ("val4",List("val5"))
def redfn3(r1:String, r2:List[String]):(String, Int) = ("val6",34)
val pattern1 = FuncG(firstParam,mapfn1,redfn1)
val pattern2 = FuncG(firstParam,mapfn2,redfn2)
val pattern3 = FuncG(firstParam,mapfn2,redfn3)
def doMatch(pattern:Any) = {
pattern match {
case FuncG(inputA, mapFn, redFun) => println("Found")
}
}
doMatch(pattern1)
doMatch(pattern2)
doMatch(pattern3)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/44229419
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