blocks|key|477559|text|两种方式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|477560|首先：|477561|+<script>
++++++document.write('<?php+echo+include_once+"./change/ud1.php";?>');
+++</script>|code-block|syntax|javascript|477562|第二：|477563|<script+type="text/javascript"+src="./change/ud1.php"></script>|477564|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Two ways : 

First: 

<pre><code> &lt;script&gt;
 document.write('&lt;?php echo include_once "./change/ud1.php";?&gt;');
 &lt;/script&gt;
</code></pre>

Second: 

<pre><code>&lt;script type="text/javascript" src="./change/ud1.php"&gt;&lt;/script&gt;
</code></pre>

blocks|key|4259115|text|尝试此|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|4259116|$("#output1").load("change/ud1.php");|code-block|syntax|javascript|4259117|entityMap^0|0|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Try this 

<pre><code>$("#output1").load("change/ud1.php");
</code></pre>

blocks|key|4259152|text|你不能在.js文件中运行php。据我所知，您需要从js文件中获取php文件的内容。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4259153|这是一个基本的实现。|4259154|var+xhr+=+new+XMLHttpRequest();

xhr.onload+=+function+()+{
++++outputEl.innerHTML+=+this.response;
};

xhr.open('GET',+'./change/ud1.php',+true);+//+you+may+need+to+correct+the+url+to+be+relative+to+the+js+file
xhr.send();|code-block|syntax|javascript|4259155|使用jquery可能更简单、更健壮，在这种情况下(一旦包含了jquery库)，您可以使用如下所示的内容|4259156|$(outputEl).load("change/ud1.php");|4259157|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You can't run php inside a .js file. As I understand it, you're going to need to fetch the content of the php file from your js file.

Here's a bare-bones implementation.

<pre><code>var xhr = new XMLHttpRequest();

xhr.onload = function () {
 outputEl.innerHTML = this.response;
};

xhr.open('GET', './change/ud1.php', true); // you may need to correct the url to be relative to the js file
xhr.send();
</code></pre>

It might be easier and more robust to use jquery, in which case (once you've included the jquery library) you can just use something like this

<pre><code>$(outputEl).load("change/ud1.php");
</code></pre>

blocks|key|477663|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|477664|php是一种服务器端语言。|unordered-list-item|477665|JavaScript是客户端语言。|477666|477667|所以php只能在你的服务器上执行，而JavaScript只能在用户的浏览器上执行。|offset|length|style|BOLD|477668|php代码不可能在JavaScript+(浏览器)中运行。所以你需要像这样使用ajax。|477669|var+xhttp+=+new+XMLHttpRequest();

xhttp.onreadystatechange+=+function()+{
++++if+(this.readyState+==+4+&&+this.status+==+200)+{
++++++++//+server+sent+data+successfully+in+this.responseText+variable
++++++++document.getElementById("output1").innerHTML+=+this.responseText;
++++}
};

//Request+data+from+a+server
xhttp.open("GET",+"path/to/php/include-script.php",+true);
xhttp.send();|code-block|syntax|javascript|477670|了解有关ajax+here的更多信息。|477671|entityMap|0|LINK|mutability|MUTABLE|url|https://www.w3schools.com/xml/ajax_intro.asp^0|0|0|0|0|2|B|0|0|0|9|4|0|0^^$0|@$1|2|3|-4|4|5|6|13|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|14|7|@]|8|@]|9|$]]|$1|D|3|E|4|C|6|15|7|@]|8|@]|9|$]]|$1|F|3|-4|4|5|6|16|7|@]|8|@]|9|$]]|$1|G|3|H|4|5|6|17|7|@$I|18|J|19|K|L]]|8|@]|9|$]]|$1|M|3|N|4|5|6|1A|7|@]|8|@]|9|$]]|$1|O|3|P|4|Q|6|1B|7|@]|8|@]|9|$R|S]]|$1|T|3|U|4|5|6|1C|7|@]|8|@$I|1D|J|1E|1|1F]]|9|$]]|$1|V|3|-4|4|5|6|1G|7|@]|8|@]|9|$]]]|W|$X|$4|Y|Z|10|9|$11|12]]]]

<ul>
<li>php is a server-side language. </li>
<li>JavaScript is client side language.</li>
</ul>

so php can only execute on your server and JavaScript executes on user's browser.

there is no way in which php code going to run in JavaScript (browser). so you need to use ajax like this.

<pre><code>var xhttp = new XMLHttpRequest();

xhttp.onreadystatechange = function() {
 if (this.readyState == 4 &amp;&amp; this.status == 200) {
 // server sent data successfully in this.responseText variable
 document.getElementById("output1").innerHTML = this.responseText;
 }
};

//Request data from a server
xhttp.open("GET", "path/to/php/include-script.php", true);
xhttp.send();
</code></pre>

Learn more about ajax <a href="https://www.w3schools.com/xml/ajax_intro.asp" rel="nofollow noreferrer">here</a>.

blocks|key|477686|text|只需使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|477687|<script+type="text/javascript"+src="filename.php"></script>|code-block|syntax|javascript|477688|还要在php文件的顶部传递这个头文件(“Content-type:+text/javascript")；。|477689|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Simply Use 

<pre><code>&lt;script type="text/javascript" src="filename.php"&gt;&lt;/script&gt;
</code></pre>

Also pass this header("Content-type: text/javascript"); on top of the php file.

blocks|key|2793522|text|在这种情况下不需要使用javascript|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2793523|你可以在你想要的地方直接使用响应|2793524|<div+id="outputEl"><?php+include+"./change/ud1.php";?></div>|code-block|syntax|javascript|2793525|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

No Need to use javascript in this case

you can use response directly where you want

<pre><code>&lt;div id="outputEl"&gt;&lt;?php include "./change/ud1.php";?&gt;&lt;/div&gt;
</code></pre>

blocks|key|833271|text|这也是可行的。把这段代码放到你的.php里，你可以把脚本放到你的.php里|type|unstyled|depth|inlineStyleRanges|entityRanges|data|833272|<script+type="text/javascript">
+++outputEl.innerHTML+=+"<?php+include+'./change/ud1.php';?>";
</script>|code-block|syntax|javascript|833273|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

this will work also. put this code in your .php, you can put script in your .php

<pre><code>&lt;script type="text/javascript"&gt;
 outputEl.innerHTML = "&lt;?php include './change/ud1.php';?&gt;";
&lt;/script&gt;
</code></pre>

blocks|key|4259279|text|这不是正确的方法。您应该将html传入一个php变量，然后将该PHP变量用于JavaScript。如果你使用的是MVC，那就很简单了。我在没有使用MVC的情况下发布了答案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4259280|$html+=+file_get_contents('path/to/YOUR/FILE.php');|code-block|syntax|javascript|4259281|在Javascript中|4259282|var+html+=+'<?php+echo+$html;+?>';|4259283|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

This is not right approach. You should take html into a php variable and then use that PHP variable into JavaScript. If you are using MVC then its quite easy. I posted answer without using MVC :

<pre><code>$html = file_get_contents('path/to/YOUR/FILE.php');
</code></pre>

In Javascript

<pre><code>var html = '&lt;?php echo $html; ?&gt;';
</code></pre>

blocks|key|477771|text|您还可以使用jquery将php文件的内容加载到指定的html元素中。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|477772|+$.get("path/to/yourfile.php",+function(data,+status){++
++++outputEl.innerHTML+=+data;
});|code-block|syntax|javascript|477773|entityMap^0|6|6|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You can also use <code>jquery</code> to load the content of the php file in your specified html element.

<pre><code> $.get("path/to/yourfile.php", function(data, status){ 
 outputEl.innerHTML = data;
});
</code></pre>

blocks|key|4259315|text|将单引号改为双引号，然后尝试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4259316|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

make single quotes to double quotes and try

blocks|key|477858|text|PHP代码在服务器上呈现，使用Javascript时，您在客户端，如果您不在服务器上，则无法呈现PHP。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|477859|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

The PHP code is rendered on the server, with Javascript you are on the client and you can not render PHP if you are not on the server.

blocks|key|4259417|text|您不能这样做，因为PHP代码在JavaScript之前呈现。有许多替代方法可以做到这一点：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|4259418|如果outputEl是div元素的ID：|4259419|1-没有jQuery/JavaScript|4259420|<div+id="outputEl"><?php+include+"./change/ud1.php";?></div>|code-block|syntax|javascript|4259421|2-使用jQuery加载函数|4259422|$("#outputEl").load('./change/ud1.php');|4259423|3-使用JavaScript函数|4259424|window.onload+=+function()+{
++if+(XMLHttpRequest)
++++var+x+=+new+XMLHttpRequest();
++else
++++var+x+=+new+ActiveXObject("Microsoft.XMLHTTP");
++x.open("GET",+"./change/ud1.php",+true);
++x.send();
++x.onreadystatechange+=+function()+{
++++if+(x.readyState+==+4)+{
++++++if+(x.status+==+200)
++++++++outputEl.innerHTML+=+x.responseText;
++++++else
++++++++outputEl.innerHTML+=+"Error+loading+document";
++++}
++}
}|4259425|entityMap^0|9|3|F|A|0|2|8|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|16|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|17|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|18|8|@]|D|@]|E|$]]|$1|Q|3|R|5|L|7|19|8|@]|D|@]|E|$M|N]]|$1|S|3|T|5|6|7|1A|8|@]|D|@]|E|$]]|$1|U|3|V|5|L|7|1B|8|@]|D|@]|E|$M|N]]|$1|W|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|X|$]]

You can't do this because PHP code render before JavaScript. There are many alternative ways to do this:

if outputEl is a ID of a div element:

1- Without jQuery/JavaScript

<pre><code>&lt;div id="outputEl"&gt;&lt;?php include "./change/ud1.php";?&gt;&lt;/div&gt;
</code></pre>

2- Use jQuery load function

<pre><code>$("#outputEl").load('./change/ud1.php');
</code></pre>

3- With JavaScript function

<pre><code>window.onload = function() {
 if (XMLHttpRequest)
 var x = new XMLHttpRequest();
 else
 var x = new ActiveXObject("Microsoft.XMLHTTP");
 x.open("GET", "./change/ud1.php", true);
 x.send();
 x.onreadystatechange = function() {
 if (x.readyState == 4) {
 if (x.status == 200)
 outputEl.innerHTML = x.responseText;
 else
 outputEl.innerHTML = "Error loading document";
 }
 }
}
</code></pre>

I've JavaScript and I want to run a include script in the JavaScript . I tried the following statement:

<pre><code>outputEl.innerHTML = '&lt;?php include "./change/ud1.php";?&gt;';
</code></pre>

When I run the script I get no response.

Does someone know why I didn't get any response and how I can fix it?

I tried to replace the PHP include with an html iframe. That worked but that is not the best solution for me.

PHP include in JavaScript is not working

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我已经包含了JavaScript，并且我想在JavaScript中运行一个包含脚本。我尝试了以下语句：outputEl.innerHTML = '<?php include "./change/ud1.php";?>';当我运行脚本时，我没有得到任何响应。有没有人知道为什么我没有得到任何回应，以及我如何修复它？我尝试用...

问JavaScript中包含的PHP不起作用。
EN

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问JavaScript中包含的PHP不起作用。EN