我的应用程序在谷歌地图上显示了车辆的跟踪历史。我们每隔2分钟从我们的移动应用程序中接收位置,并将其存储在DB中。之后,我们在地图上显示路线(使用JS API,Directions Service)。
{
origin: 'Chicago, IL',
destination: 'Los Angeles, CA',
waypoints: [
...
],
provideRouteAlternatives: false,
travelMode: 'DRIVING',
unitSystem: google.maps.UnitSystem.IMPERIAL
}但是,有时位置可能只有3-5米不准确。作为一个例子,可以在迎面而来的交通线路上显示一些位置。因此,谷歌创建了绕过几个街区等的路线。

那么问题是:有没有可能忽略这些不准确的点,只是“迫使”谷歌在一个方向上创建路线?
谢谢!
发布于 2017-07-20 21:04:13
我有个主意。它看起来很有效,至少对于我在类似情况下选择的路点是这样的。
我将两条腿(=两个路点之间的路线段)放在一个for循环中。对于每一段,我计算/读取“沿路线的距离”,并将其除以飞行路径距离。这个比率应该是1左右,如果它比1大得多,那就是有问题了。我将阈值设置为2.0,您可能应该降低它(猜测一个介于1和2之间的值)。
当找到这样一个因子时,我删除该路点(好吧,我创建了一个新的数组"newWaypoints“,没有此项),然后再次开始,这将在2秒的setTimeout之后生成一条红色路由。
这个函数是递归的,我不知道应该删除多个点会发生什么。也许它会不止一次地尝试。
<style>
#map {height: 400px;}
</style>
<div id="map"></div>
<div id="log"></div>
<input type="button" value="click" onclick="calc()">
<script>
var directionsDisplay;
var directionsService;
var map;
var maxFactor = 2.0; // FEEL FREE TO GUESTIMATE ANOTHER VALUE
function initMap() {
var start = new google.maps.LatLng(50.96622130043278,3.8518730520809185);
var mapOptions = {
zoom:7,
center: start
}
map = new google.maps.Map(document.getElementById('map'), mapOptions);
directionsService = new google.maps.DirectionsService();
}
function calcRoute(start, end, waypoints, color) {
directionsDisplay = new google.maps.DirectionsRenderer({ map: map, polylineOptions: {strokeColor: color} });
var request = {
origin: start,
destination: end,
waypoints: waypoints,
provideRouteAlternatives: false,
travelMode: 'DRIVING',
unitSystem: google.maps.UnitSystem.IMPERIAL
};
directionsService.route(request, function(result, status) {
if (status == 'OK') {
var newWaypoints = [];
directionsDisplay.setDirections(result);
var legs = result.routes[0].legs;
var problemIndex = -1;
for(var i in legs) {
var routeSegment = legs[i].distance.value;
var origin = legs[i].start_location;
var destination = legs[i].end_location;
var flightpathDistance = google.maps.geometry.spherical.computeDistanceBetween(origin, destination);
var factor = (routeSegment / flightpathDistance);
if(factor > maxFactor && problemIndex == -1) {
// too long
problemIndex = i;
document.getElementById('log').innerHTML += 'factor ' + factor.toFixed(2) + ' - segment looks too long. romove waypoint ' + i + ' (0 based)<br/>';
}
else if(factor > maxFactor && problemIndex == i -1) {
if(i<legs.length - 1) { // skip the destination; this is not a waypoint
newWaypoints.push(waypoints[i]);
}
document.getElementById('log').innerHTML += 'factor ' + factor.toFixed(2) + ' - segment also too long, but the problem is probably the previous segment<br/>';
}
else {
if(i<legs.length - 1) { // skip the destination; this is not a waypoint
newWaypoints.push(waypoints[i]);
}
document.getElementById('log').innerHTML += 'factor ' + factor.toFixed(2) + '<br/>';
}
}
document.getElementById('log').innerHTML += '<hr/>';
if(problemIndex > -1) {
setTimeout(function() {
calcRoute(start, end, newWaypoints, 'red');
}, 2000);
}
}
});
}
function calc() {
calcRoute(
'50.95487921891042,3.879781222422025',
'51.002379049703315,3.757394492495223',
[
{location: '50.96622130043278,3.8518730520809185', stopover: true},
{location: '50.9725522849737,3.8379914402503345', stopover: true},
{location: '50.97957292616706,3.8236401199901593', stopover: true}, // This is the problem point, on the opposite side of the road
{location: '50.98570531465853,3.81125807762146', stopover: true},
{location: '50.98941308813775,3.8019619700935436', stopover: true}
],
"blue"
);
}
</script>
<script async defer src="https://maps.googleapis.com/maps/api/js?callback=initMap&libraries=geometry"></script>https://stackoverflow.com/questions/45210058
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