blocks|key|2109297|text|下面的代码将只查找(sectione+2)节计数。试着关注并让我知道这是否有帮助。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2109298|awk+'/sectione+3/{a=""}/sectione+2/{a=1;next}+!/#/+&&+a{count%2B%2B}+END{print+count}'+++Input_file|code-block|syntax|javascript|2109299|EDIT1:现在也在同一个平台上增加了一个解决方案。|offset|length|style|BOLD|2109300|awk+'/sectione+2/,/sectione+3/{count=$0!~/#/?%2B%2Bcount:count}+END{print+count}'+++Input_file|2109301|entityMap^0|0|0|0|6|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Following code will only look for (sectione 2) section count. Try following and let me know if this helps.

<pre><code>awk '/sectione 3/{a=""}/sectione 2/{a=1;next} !/#/ &amp;&amp; a{count++} END{print count}' Input_file
</code></pre>

EDIT1: Adding one more solution on same too now.

<pre><code>awk '/sectione 2/,/sectione 3/{count=$0!~/#/?++count:count} END{print count}' Input_file
</code></pre>

blocks|key|4426253|text|另一种方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4426254|sed+-n+'/#+sectione+2/,/#+sectione+3/{/%5E#/d;//!p;}'+file+%7C+wc+-l|code-block|syntax|javascript|4426255|/#+sectione+2/,/#+sectione+3/选择第2节和第3节之间的线|offset|length|style|CODE|4426256|/%5E#/d删除以#开头的行|4426257|//!p打印其余部分..|4426258|entityMap^0|0|0|0|T|0|0|5|0|0|4|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@$I|Y|J|Z|K|L]]|9|@]|A|$]]|$1|O|3|P|5|6|7|10|8|@$I|11|J|12|K|L]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|R|$]]

One more way:

<pre><code>sed -n '/# sectione 2/,/# sectione 3/{/^#/d;//!p;}' file | wc -l
</code></pre>

<code>/# sectione 2/,/# sectione 3/</code> Selecting the lines between the section 2 and section 3

<code>/^#/d</code> deleting the lines starting with #

<code>//!p</code> printing the rest..

blocks|key|4426280|text|sed+-n+'/sectione+2/,/sectione+3/{/%5E#/!p}'+test.txt+%7C+wc+-l|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4426281|在第2节和第3节间处理数据，在行首匹配#，然后用!p打印不符合此模式的任何行。|unstyled|4426282|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>sed -n '/sectione 2/,/sectione 3/{/^#/!p}' test.txt | wc -l
</code></pre>

Process the data between sectione 2 and sectione 3 pattern matching for # at the start of the line and then printing any lines that don't meet this pattern with !p.

blocks|key|1651489|text|您可以使用以下awk命令：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1651490|awk+'/sectione/{f=$3==2?1:0}f&&!/%5E#/{c%2B%2B}END{print+c}'+file|code-block|syntax|javascript|1651491|多行版本中的解释：|1651492|2.awk：|1651493|/sectione/+{
++++#+Set+f(ound)+to+1+(true)+if+the+number+between+'sectione'+is+a+2
++++#+otherwise+0+(false)
++++f=$3==2?1:0
}

#+If+f(ound)+is+true+(1)+and+the+line+starts+not+with+a+#
#+count+it
f&&!/%5E#/{
++++c%2B%2B
}

#+At+the+end+of+input+print+the+c(ount)
END{
++++print+c
}|1651494|entityMap^0|7|3|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|X|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

You can use the following <code>awk</code> command:

<pre><code>awk '/sectione/{f=$3==2?1:0}f&amp;&amp;!/^#/{c++}END{print c}' file
</code></pre>

Explanation in a multiline version:

section2.awk:

<pre><code>/sectione/ {
 # Set f(ound) to 1 (true) if the number between 'sectione' is a 2
 # otherwise 0 (false)
 f=$3==2?1:0
}

# If f(ound) is true (1) and the line starts not with a #
# count it
f&amp;&amp;!/^#/{
 c++
}

# At the end of input print the c(ount)
END{
 print c
}
</code></pre>

I'm searching for ideas to have a script doing the following:

I have a textual file eg. <code>test.txt</code> with the similar text in it:

<pre><code>#
# sectione 1
#
several
text
lines 
and so on
#
# sectione 2
#
more text
and more
#
and more
# ...
#
# sectione 3
#
more
more
more 
#
# sectione 4
#
...
...
</code></pre>

I need a possibility to count only the lines in sectione 2 and exclude lines starting with #

In my above example the script should show me a counter with "3" at the end
eg.

<pre><code># counter_script.sh test.txt 
# 3
</code></pre>

Is this possibility and how can i do it?
I'm using Debian Linux with bash shell.

Script for counting lines in sections excluding #

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在寻找可以让脚本执行以下操作的想法：我有一个文本文件，例如。包含类似文本的test.txt：## sectione 1#severaltextlines and so on## sectione 2#more textand more#and more# ...## sectione 3#moremoremore ...

问用于计算除#之外的部分中的行数的脚本
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问用于计算除#之外的部分中的行数的脚本EN