blocks|key|5847771|text|您可以将其保存在数组中，然后再访问这些值。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5847772|+$sql="SELECT+*+FROM+categories";
+$query+=+mysqli_query($con,+$sql);
+$cat+=+array();
+while($row+=+mysqli_fetch_assoc($query))+{+
+++++++$cat[]=$row['cat_name']
+}|code-block|syntax|javascript|5847773|现在：|5847774|foreach+($cat+as+$category)+{
+++++$cate_gory+=+explode(","+,+$category);
+++++foreach+($cate_gory+as+$categories)+{
+++++++++++++++++echo+$categories+.+"<br>";
+++++}
}|5847775|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<p>You can save it in array then later access the values.</p>

<pre><code> $sql="SELECT * FROM categories";
 $query = mysqli_query($con, $sql);
 $cat = array();
 while($row = mysqli_fetch_assoc($query)) { 
       $cat[]=$row['cat_name']
 }
</code></pre>

<p>Now:</p>

<pre><code>foreach ($cat as $category) {
     $cate_gory = explode("," , $category);
     foreach ($cate_gory as $categories) {
                 echo $categories . "&lt;br&gt;";
     }
}
</code></pre>


blocks|key|2062901|text|使用$rows+($query作为foreach+)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2062902|或|2062903|用于($i=0；$i+<+count($query)；$i%2B%2B)|2062904|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

<p>Use foreach ($query as $rows)</p>

<p>or </p>

<p>Use for ($i=0; $i &lt; count($query); $i++)</p>


blocks|key|4379607|text|也许你也可以试试这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4379608|$sql="SELECT+*+FROM+categories";
$query+=+mysqli_query($con,+$sql);
+while($row+=+mysqli_fetch_assoc($query))
+{+
++++$row['cat_name'];
+++$cat=explode(",",$row['cat_name']);
+++foreach($cat+as+$catss)+
++{
++++$cat+=+trim($catss);
++++$categories+.=+"<category>"+.+$cat+.+"</category>\n";
+++}
}|code-block|syntax|javascript|4379609|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>Probably You can try this also</p>

<pre><code>$sql="SELECT * FROM categories";
$query = mysqli_query($con, $sql);
 while($row = mysqli_fetch_assoc($query))
 { 
    $row['cat_name'];
   $cat=explode(",",$row['cat_name']);
   foreach($cat as $catss) 
  {
    $cat = trim($catss);
    $categories .= "&lt;category&gt;" . $cat . "&lt;/category&gt;\n";
   }
}
</code></pre>


blocks|key|5847849|text|你可以尝试这种方式，也许你希望动态菜单是这样的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5847850|+$sql="SELECT+*+FROM+categories";
+++++$query+=+mysqli_query($con,+$sql);
+++++$menu+=+'';
+++++$menu+.=+'<ul>';
+++++while($row+=+mysqli_fetch_assoc($query))
+++++{+
+++++++$menu+.=+'<li>'+.+$row['cat_name']+.+'</li>';
+++++}
+++++$menu+.=+'</ul>';
+++++echo+$menu;|code-block|syntax|javascript|5847851|当您从表中获取数据时，您可以使用字段名直接打印该值。如果您想进一步使用它，您必须添加一个数组，如下所示：|5847852|$cat[]+=+$row['cat_name'];|5847853|然后，您可以使用for或while以这种方式使用此值：|5847854|foreach+($cat+as+$value)+{
+++echo+$value;
}|5847855|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

<p>You can try this way may be you wish like this for dynamic menu:  </p>

<pre><code> $sql="SELECT * FROM categories";
     $query = mysqli_query($con, $sql);
     $menu = '';
     $menu .= '&lt;ul&gt;';
     while($row = mysqli_fetch_assoc($query))
     { 
       $menu .= '&lt;li&gt;' . $row['cat_name'] . '&lt;/li&gt;';
     }
     $menu .= '&lt;/ul&gt;';
     echo $menu;
</code></pre>

<p>When you are fetching data from table then you can directly print that value using field name. if you want to further use that so, you have to add in one array like: </p>

<pre><code>$cat[] = $row['cat_name'];
</code></pre>

<p>then you can use this value in that manner using for or while:</p>

<pre><code>foreach ($cat as $value) {
   echo $value;
}
</code></pre>


blocks|key|2063021|text|Foreach循环|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2063022|foreach($cats+as+$cat)
{
++++echo+$cat;
}|code-block|syntax|javascript|2063023|基本For循环|2063024|for+($i=0;+$i<count($cats);+$i%2B%2B)+
{
++++echo+$cats[$i];
}|2063025|简单的用例|2063026|<?php

$cats+=+'Stack+overflow+PHP+questions';
$cats+=+explode('+',$cats);
$html+=+'<ul>';
foreach($cats+as+$cat)
{
++++$html+.=+'<li>'+.+$cat+.+'</li>';
}
$html+.=+'</ul>';
echo+$html;

?>|2063027|你的代码|2063028|在这种情况下，您正在使用的while循环将迭代从sql语句返回的所有值，因此不需要增加更多的复杂性。我将去掉字段名中的逗号，并以这种方式回显html。|2063029|$sql="SELECT+*+FROM+categories";
$query+=+mysqli_query($con,+$sql);
$html+=+'<ul>';
while($row+=+mysqli_fetch_assoc($query))+{+
++++$html+.=+'<li>'+.+$row['cat_name']+.+'</li>';
}
$html+.=+'</ul>';
echo+$html;

?>|2063030|entityMap^0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|12|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|T|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

<h1>Foreach Loop</h1>

<pre><code>foreach($cats as $cat)
{
    echo $cat;
}
</code></pre>

<h1>Basic For Loop</h1>

<pre><code>for ($i=0; $i&lt;count($cats); $i++) 
{
    echo $cats[$i];
}
</code></pre>

<h1>Simple Use Case</h1>

<pre><code>&lt;?php

$cats = 'Stack overflow PHP questions';
$cats = explode(' ',$cats);
$html = '&lt;ul&gt;';
foreach($cats as $cat)
{
    $html .= '&lt;li&gt;' . $cat . '&lt;/li&gt;';
}
$html .= '&lt;/ul&gt;';
echo $html;

?&gt;
</code></pre>

<h1>Your Code</h1>

<p>In this case the while loop you are using will iterate over all the values returned from the sql statement, so there is no need to add more complexity. I would remove the commas from the field names and echo out the html this way.
    

<pre><code>$sql="SELECT * FROM categories";
$query = mysqli_query($con, $sql);
$html = '&lt;ul&gt;';
while($row = mysqli_fetch_assoc($query)) { 
    $html .= '&lt;li&gt;' . $row['cat_name'] . '&lt;/li&gt;';
}
$html .= '&lt;/ul&gt;';
echo $html;

?&gt;
</code></pre>


blocks|key|5847944|text|echo+'<ul>';

foreach+($cat+as+$val)+{
++++echo+"<li>{$val}</li>";
}

echo+'</ul>';|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|5847945|而不是index。此外，这应该比for循环更快，更具可读性。|unstyled|offset|length|style|CODE|5847946|entityMap^0|0|3|5|G|3|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|S|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>echo '&lt;ul&gt;';

foreach ($cat as $val) {
    echo "&lt;li&gt;{$val}&lt;/li&gt;";
}

echo '&lt;/ul&gt;';
</code></pre>

<p>Instead of the <code>index</code>. Also this should be faster and readable than <code>for</code> loop.</p>


<p>So I am creating a dynamic menu. Where I have stored the main categories of the menu in a separate table and subcategories in another table.
They are stored in this way</p>

<pre><code>Categories Table
          id         cat_name
           1         HOME,
           2         PRODUCTS,
           3         SOLUTIONS,
           4         NEWS &amp; GALLERY,
           5         DOWNLOADS,
           6         CONTACT   
</code></pre>

<p>Right Now I am running a query </p>

<pre><code>$sql="SELECT * FROM categories";
$query = mysqli_query($con, $sql);
while($row = mysqli_fetch_assoc($query)) { 
$row['cat_name'];
$cat=explode(",",$row['cat_name']);
}
</code></pre>

<p>Then wherever needed I am printing the values like this </p>

<pre><code>&lt;?php echo $cat[0]; .. echo $cat[1]; //and so on ?&gt;
</code></pre>

<p>It looks like <a href="https://i.stack.imgur.com/eKHI6.png" rel="nofollow noreferrer">this</a> right now. And it is supposed to look like<a href="https://i.stack.imgur.com/Pbcf4.png" rel="nofollow noreferrer">this</a>
But the problem with this solution is that I have to define the index of the array to print it.</p>

<p>I am developing the admin panel for this one and I want that if the admin adds a new menu item then it should automatically fetch it and display it. 
But with this solution it is not possible.
I am thinking of iterating the values with a for loop but cannot get it right.</p>


Iterating values fetched from mysqli

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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所以我创建了一个动态菜单。我将菜单的主要类别存储在一个单独的表中，而子类别存储在另一个表中。它们是以这种方式存储的Categories Table          id         cat_name           1         HOME,           2         PRODUCTS,  ...

问迭代从mysqli获取的值
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问迭代从mysqli获取的值EN