问安排作业以2秒的倍数运行，即2、4、8、16、32秒

EN

delay = 2
repeat
 TriggerOnceAfter(delay)
 delay <- delay * 2
 WaitUntilTriggered()
until (finished)

import java.util.concurrent.CountDownLatch;
import java.util.concurrent.TimeUnit;

public class Tasker {

    private int numberOfRuns; //how many times job executed 
    private int timeBetweenRuns;//seconds

    Tasker(int numberOfRuns){

        this.numberOfRuns = numberOfRuns;
        timeBetweenRuns = 2;
        execute();
    }


    private void execute() {

        for (int counter = 0; counter < numberOfRuns ; counter++) {
            CountDownLatch latch = new CountDownLatch(1);
            Job job = new Job(latch, timeBetweenRuns);
            job.run();

            try {
                latch.await();
                TimeUnit.SECONDS.sleep(timeBetweenRuns);
            } catch (InterruptedException ex) {
                ex.printStackTrace();
            }
            timeBetweenRuns *=2;
        }
    }

    public static void main(String[] args){

        new Tasker(5);
    }
}

class Job implements Runnable {

    private int seconds;
    private CountDownLatch latch ;

    Job(CountDownLatch latch , int seconds){
        this.latch = latch;
        this.seconds = seconds;
    }

    @Override
    public void run() {

        System.out.println("Job runs "+ seconds +" after previous one");
        latch.countDown();
    }
}