我正在尝试使用python 3.6.1将RTF转换为XML/xhtml。
Python代码:https://github.com/brendonh/pyth/blob/master/examples/reading/rtf15.py
import sys
import os.path
from pyth.plugins.rtf15.reader import Rtf15Reader
from pyth.plugins.xhtml.writer import XHTMLWriter
if len(sys.argv) > 1:
filename = sys.argv[1]
else:
filename = os.path.normpath(os.path.join(os.path.dirname(__file__),'../../tests/rtfs/sample.rtf'))
doc = Rtf15Reader.read(open(filename, "rb"))
print(XHTMLWriter.write(doc, pretty=True).read())错误:
Traceback (most recent call last):
File "C:\xx\file1.py", line 14, in <module>
from pyth.plugins.rtf15.reader import Rtf15Reader
File "C:\Python 3.6.1\lib\site-packages\pyth\plugins\rtf15\reader.py", line 594
match = re.match(ur'HYPERLINK "(.*)"', destination)
^
SyntaxError: invalid syntax我可以知道如何解决语法问题吗?
谢谢。
发布于 2017-08-01 16:47:14
请查看链接:
https://pypi.python.org/pypi/pyth/0.6.0
pyth包只适用于Python2.x,不适用于Python3.x版本。
PS:在您的示例代码中,
print XHTMLWriter.write(doc, pretty=True).read()是Python 2.x版本,而不是Python 3.x版本。请查收。
https://stackoverflow.com/questions/45432742
复制相似问题