blocks|key|875548|text|如果myString中有任何字母与myString中的所有字母匹配，则返回True。也可以反过来做，如果myString中有任何字母不匹配，则返回False|type|unstyled|depth|inlineStyleRanges|entityRanges|data|875549|def+findLetters(myList,+myString):
++++for+letter+in+myString:
++++++++if+letter+not+in+myList:
++++++++++++return+False
++++return+True|code-block|syntax|javascript|875550|或者使用内置函数all|offset|length|875551|def+findLetters(myList,+myString):
++return+all(letter+in+myList+for+letter+in+myString)|875552|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/2/library/functions.html#all^0|0|0|8|3|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@$I|X|J|Y|1|Z]]|A|$]]|$1|K|3|L|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

you are returning True if any letter match in myString, not all letter in myString.
You could do the other way around, if any letter not match in myString, return False

<pre><code>def findLetters(myList, myString):
 for letter in myString:
 if letter not in myList:
 return False
 return True
</code></pre>

OR use builtin function <a href="https://docs.python.org/2/library/functions.html#all" rel="nofollow noreferrer">all</a>

<pre><code>def findLetters(myList, myString):
 return all(letter in myList for letter in myString)
</code></pre>

blocks|key|875579|text|您可以使用lambda映射所有字母，这将为my_string中的所有字母创建一个布尔值列表。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|875580|如果l列表中的所有值都为True，则函数all返回true。|875581|def+find_letters(my_list,+my_string):+
++++l+=+map(lambda+x:+x+in+my_list,+my_string)
++++return+all(l)

print(find_letters(['a',+'b',+'c'],+'cab'))|code-block|syntax|javascript|875582|entityMap^0|L|9|0|2|1|C|4|K|3|P|4|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]|$9|W|A|X|B|C]|$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|10|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|N|$]]

You can map all letters using a lambda which creates a list of boolean values for all letters in <code>my_string</code>.

The function <code>all</code> returns <code>true</code> if all values in the <code>l</code> list ar <code>True</code>.

<pre><code>def find_letters(my_list, my_string): 
 l = map(lambda x: x in my_list, my_string)
 return all(l)

print(find_letters(['a', 'b', 'c'], 'cab'))
</code></pre>

blocks|key|965448|text|这是一个基本的解决方案，它更接近于你已经开始的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|965449|def+findLetters(myList,+myString):
++++found_all+=+False
++++for+s+in+myString:++++++++#+check+each+letter+in+the+string
++++++++if+s+in+myList:+++++++#+see+if+it+is+in+the+list
++++++++++++found_all+=+True++#+keep+going+if+found
++++++++else:
++++++++++++found_all+=+False+#+otherwise+set+`found`+to+False+
++++++++++++break+++++++++++++#+and+break+out+of+the+loop

++++return+found_all++++++++++#+return+the+result

result+=+findLetters(['a',+'l',+'i',+'s',+'t'],+'mlist')

#+'m'+is+not+in+the+list
print+result+#+False+

#+all+letters+in+the+string+are+in+the+list;+
#+ignores+any+extra+characters+in+the+list+that+are+not+in+the+string
result+=+findLetters(['a',+'l',+'i',+'s',+'t',+'p'],+'alist')

print+result+#+True+|code-block|syntax|javascript|965450|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here's a basic solution that's closer to what you've started:

<pre><code>def findLetters(myList, myString):
 found_all = False
 for s in myString: # check each letter in the string
 if s in myList: # see if it is in the list
 found_all = True # keep going if found
 else:
 found_all = False # otherwise set `found` to False 
 break # and break out of the loop

 return found_all # return the result

result = findLetters(['a', 'l', 'i', 's', 't'], 'mlist')

# 'm' is not in the list
print result # False 

# all letters in the string are in the list; 
# ignores any extra characters in the list that are not in the string
result = findLetters(['a', 'l', 'i', 's', 't', 'p'], 'alist')

print result # True 
</code></pre>

I have a problem that states: Write a function that takes, as an argument, a list and a string,and returns a Boolean based on whether or not all of the letters in the string appear somewhere in the list. Here is what I have so far. 

<pre><code>def findLetters(myList, myString):
 for letter in myString:
 if letter in myList:
 return True
 return False
</code></pre>

Finding a letter in a list

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个问题:编写一个函数，该函数以列表和字符串作为参数，并根据字符串中的所有字母是否出现在列表中的某个位置返回一个布尔值。这是我到目前为止所拥有的。def findLetters(myList, myString):    for letter in myString:        if letter in myL...

问在列表中查找字母
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问在列表中查找字母EN