我想用typoscript复制这个...
<ul class="nav nav-pills nav-stacked">
<li role="presentation"><p class="footer-header"><span class="footer-header-span">Company</span></p></li>
<li role="presentation"><a href="/home/">Home</a></li>
<li role="presentation"><a href="/impressum/">Impressum</a></li>
<li role="presentation"><a href="/terms-of-use/">Terms of Use</a></li>
</ul>
..。其中'Company‘是一个系统文件夹...
Company [Sys Folder][10]
|_Home [Link]
|_Impressum [Link]
|_Terms of Use [Link]
..。下面给我呈现了这些链接
lib.footerlinks = HMENU
lib.footerlinks {
special = directory
special.value = 10
1 = TMENU
1 {
wrap = <ul class="nav nav-pills nav-stacked">|</ul>
NO = 1
NO {
ATagBeforeWrap = 1
ATagTitle.field = title
allWrap = <li role="presentation">|</li>
}
CUR = 1
CUR.ATagParams = class="active"
CUR.allWrap = <li role="presentation">|</li>
}
}
..。所以我得到了这个:
<ul class="nav nav-pills nav-stacked">
<li role="presentation"><a href="/home/">Home</a></li>
<li role="presentation"><a href="/impressum/">Impressum</a></li>
<li role="presentation"><a href="/terms-of-use/">Terms of Use</a></li>
</ul>
但是,如何添加sysfolder作为第一个li以及周围的其他元素呢?
发布于 2017-10-13 17:27:43
也许你可以使用"entryLevel“属性来解决这个问题,但是你需要两个菜单级别。尝试如下所示:
lib.footerlinks = HMENU
lib.footerlinks {
special = directory
special.value = 10
entryLevel = -1
1 = TMENU
1 {
wrap = <ul class="nav nav-pills nav-stacked">|</ul>
NO = 1
NO {
ATagBeforeWrap = 1
ATagTitle.field = title
allWrap = <li role="presentation">|</li>
}
CUR = 1
CUR.ATagParams = class="active"
CUR.allWrap = <li role="presentation">|</li>
}
2 < .1
2 {
wrap >
}
}
https://stackoverflow.com/questions/46725705
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