包含分支的代码
包含分支的代码
提问于 2017-09-24 18:22:07
def which_prize():
return "Congratulations! You have won a [prize name]!"
if Points ==0 or Points ==50:
print("Congratulations! You have won a [wooden rabbit]!")
elif Points ==0 or Points ==150:
print("Congratulations! You have won a [no prize]!")
elif Points==151 or Points ==180:
print("Congratulations! You have won a [wafer-thin mint]!")
elif Points ==181 or Points ==200:
print("Congratulations! You have won a [penguin]!")
else:
print("Oh dear, no prize this time.")which_prize()的输入将是点数(一个整数)。函数which_prize()应该返回文本“恭喜！您赢得了一个奖的名字！”如果他们获奖了，包括奖品名称和文字“哦天哪，这次没有奖品。”如果没有奖品。像往常一样，测试您的函数以检查它是否正常运行。
IndentationError: unindent does not match any outer indentation level.
回答 1
Stack Overflow用户
发布于 2017-09-24 20:34:17
你可能把制表符和空格混在一起了。尝试取消缩进您的代码，并仅用制表符(或空格)再次缩进。
PS:你期望你的代码如何运行:函数在return语句之后结束。
尝试：
def which_prize():
if Points and Points <=50:
return("Congratulations! You have won a [wooden rabbit]!")
elif Points <= 150:
return "Congratulations! You have won a [no prize]!")
elif Points <= 180:
return "Congratulations! You have won a [wafer-thin mint]!")
elif Points > 180:
return "Congratulations! You have won a [penguin]!")
else:
return "Oh dear, no prize this time."页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/46389009
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