blocks|key|5373382|text|您没有在代码中声明任何"d“，但您在console.log中使用了它|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5373383|console.log($("#"%2Bd));|code-block|syntax|javascript|5373384|但它应该是：|5373385|console.log($("#"%2Bid));|5373386|你错过了i。|5373387|entityMap^0|I|B|0|0|0|0|4|1|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|R|$]]

You didn't declare any "d" in your code but you use this in <code>console.log</code>

<pre><code>console.log($("#"+d));
</code></pre>

but it should be:

<pre><code>console.log($("#"+id));
</code></pre>

you missed the <code>i</code>.

blocks|key|1217515|text|这一行：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1217516|var+session+=+$(server_response).html();|code-block|syntax|javascript|1217517|这说不通。如果服务器成功回显ID，直接使用server_response即可。|offset|length|style|CODE|1217518|++success:+function(server_response)+{
++++if+(id+==+server_response)+{+//+<==+Here
++++++console.log($("#"+%2B+id));++//+<==+Also+fixed+apparent+typo+on+this+line,
+++++++++++++++++++++++++++++++++//+++++but+that's+not+the+reason+for+the
+++++++++++++++++++++++++++++++++//+++++error+you're+getting
++++}+else+{
++++++console.log("You+shall+not+pass!");
++++}
++},|1217519|$(server_response)要求jQuery使用server_response作为超文本标记语言和内置的DOM元素，或者作为一个CSS选择器。“未识别的表达式”表明它看起来不像超文本标记语言，因此jQuery尝试将其用作选择器，但它不是有效的选择器。|1217520|1217521|在一个应该是注释的回答中，你说你已经更新了(大部分)上面的代码，但它仍然不起作用，并且你向我们展示了这段PHP代码：|1217522|while+($idval+=+$reponse->fetch())+{
++++if+($idval){
++++++++echo+$idval['user'];
++++}
++++else{
++++++++echo+"nope";
++++}
}|1217523|如果if+(id+==+server_response)不工作，这就告诉我们id不是中与server_response完全匹配的。PHP脚本出现这种情况的一个常见原因是，在输出响应的代码之前或之后无意中包含了空格，通常是在某个地方换行，通常是在末尾。|BOLD|1217524|我们可以通过server_response.trim()在现代浏览器上裁剪掉这些功能，或者通过$.trim(server_response)使用jQuery的$.trim来支持更老的浏览器|1217525|++success:+function(server_response)+{
++++if+(id+==+$.trim(server_response))+{+//+<==+Here
++++++console.log($("#"+%2B+id));
++++}+else+{
++++++console.log("You+shall+not+pass!");
++++}
++},|1217526|entityMap^0|0|0|L|F|0|0|0|I|S|F|0|0|0|0|2|Q|12|2|18|F|16|M|0|6|M|1B|N|27|6|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|16|8|@$I|17|J|18|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|1A|8|@$I|1B|J|1C|K|L]|$I|1D|J|1E|K|L]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|1F|8|@]|9|@]|A|$]]|$1|R|3|S|5|6|7|1G|8|@]|9|@]|A|$]]|$1|T|3|U|5|D|7|1H|8|@]|9|@]|A|$E|F]]|$1|V|3|W|5|6|7|1I|8|@$I|1J|J|1K|K|L]|$I|1L|J|1M|K|L]|$I|1N|J|1O|K|L]|$I|1P|J|1Q|K|X]]|9|@]|A|$]]|$1|Y|3|Z|5|6|7|1R|8|@$I|1S|J|1T|K|L]|$I|1U|J|1V|K|L]|$I|1W|J|1X|K|L]]|9|@]|A|$]]|$1|10|3|11|5|D|7|1Y|8|@]|9|@]|A|$E|F]]|$1|12|3|-4|5|6|7|1Z|8|@]|9|@]|A|$]]]|13|$]]

This line:

<pre><code>var session = $(server_response).html();
</code></pre>

doesn't make sense. If the server echos back the ID on success, just use <code>server_response</code> directly.

<pre><code> success: function(server_response) {
 if (id == server_response) { // &lt;== Here
 console.log($("#" + id)); // &lt;== Also fixed apparent typo on this line,
 // but that's not the reason for the
 // error you're getting
 } else {
 console.log("You shall not pass!");
 }
 },
</code></pre>

<code>$(server_response)</code> asks jQuery to use <code>server_response</code> either as HTML and built DOM elements or as a CSS selector. "Unrecognized expression" suggests that it doesn't look like HTML and so jQuery tries to use it as a selector, but it's not a valid selector.

<hr>

In an answer that should have been a comment, you said you've updated the code to (mostly) the above but it's still not working, and you've shown us this PHP code:

<pre><code>while ($idval = $reponse-&gt;fetch()) {
 if ($idval){
 echo $idval['user'];
 }
 else{
 echo "nope";
 }
}
</code></pre>

If <code>if (id == server_response)</code> isn't working, that tells us that <code>id</code> isn't an exact match for <code>server_response</code>. A common cause for that with PHP scripts is that you're inadvertently including whitespace before or after the code where you output your response, usually newlines somewhere, often at the end.

We can trim those off on modern browsers via <code>server_response.trim()</code> or to support older browsers, using jQuery's <code>$.trim</code> via <code>$.trim(server_response)</code>:

<pre><code> success: function(server_response) {
 if (id == $.trim(server_response)) { // &lt;== Here
 console.log($("#" + id));
 } else {
 console.log("You shall not pass!");
 }
 },
</code></pre>

blocks|key|5319098|text|我不知道你为什么要这么做var+session+=+$(server_response).html();|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5319099|您可以只使用'server_response‘。无需使用$+sign。|5319100|另外，请将console.log($("#"+%2B+d));的语法更正为console.log($("#"+%2B+id));，因为我没有看到您定义了d+anywhere。|5319101|希望这能对你有所帮助。|5319102|entityMap^0|C|14|0|S|1|0|5|O|Z|P|20|1|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|T|8|@$9|U|A|V|B|C]|$9|W|A|X|B|C]|$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|10|8|@]|D|@]|E|$]]|$1|L|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|M|$]]

I don't know why you did this <code>var session = $(server_response).html();</code>

you can just use 'server_response'. no need to use <code>$</code> sign.

Also please correct the syntax of <code>console.log($("#" + d));</code> to <code>console.log($("#" + id));</code> 
as i don't see that you have defined <code>d</code> anywhere.

hope this will help you.

I don't know why the console return me this uncaught syntax ...
Help me plz !

<pre><code>$(document).ready(function() {
 $("#idval").change(function() {

 var id = $(this).val();

 $.ajax({
 url: 'verif.php',
 type: 'GET',
 data: 'user=' + id,

 success: function(server_response) {
 var session = $(server_response).html();

 if (id == session) {
 console.log($("#" + d));
 } else {
 console.log("You shall not pass!");
 }

 },
 error: function(server_response, statut, error) {
 console.log("Can't be linked !");
 }
 });
 });
});
</code></pre>

When the user enter an <code>id</code>, the server check if the <code>id</code> is on the database. If it is, the server return the <code>id</code> in the console if it isn't, the server should return "string", but it return the uncaught ....

Ajax Uncaught Syntax error, unrecognized expression:

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

教程

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云智能顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

聚焦“写作效率、视觉美观与运行性能”三方面进行全面升级，为您提供更高效、稳定的创作环境

社区富文本&Markdown编辑器全新改版上线，欢迎大家体验!

诚挚邀请您参与本次调研，分享您的真实使用感受与建议。您的反馈至关重要，感谢您的支持与参与！

社区新版编辑器体验调研

我不知道为什么控制台返回给我这个未捕获的语法...请帮帮我！$(document).ready(function() {  $("#idval").change(function() {    var id = $(this).val();    $.ajax({      url: 'verif.php',     ...

问Ajax未捕获语法错误，无法识别的表达式：
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问Ajax未捕获语法错误，无法识别的表达式：EN