如果我在定义函数的行之前的一行上调用函数，为什么我的代码可以正常工作？
如果我在定义函数的行之前的一行上调用函数，为什么我的代码可以正常工作？
提问于 2018-01-05 08:12:58
我正在为学校做一个小项目。我尝试调用一个我已经定义的函数。它起作用了，但问题是，我在第40行调用了函数，函数定义在第56行。为什么它起作用了？是不是因为整个编译器和解释器的问题？
我在脚本模式下使用PyCharm。
def game_intro():
print "------------------ First Hero ------------------"
global n1
n1 = raw_input("Please Type a Name for Your Hero: ")
while not valid_name(n1):
print "------------------ First Hero ------------------"
n1 = raw_input("Please Type a Name for Your Hero: ")
print "------------------ Second Hero ------------------"
global n2
n2 = raw_input("Please Type a Name for Your Hero: ")
while not valid_name(n2):
print "------------------ Second Hero ------------------"
n2 = raw_input("Please Type a Name for Your Hero: ")
while not no_repeat(n2):
n2 = raw_input("Please Type a Name for Your Hero: ")
def valid_name(n):
if n == " ": # TO AVOID THE PLAYER GIVING A NAME AS SPACE
print "Your name can't be empty"
return False
elif n == "":
return False
return True
def no_repeat(m): # TO MAKE SURE THE PLAYERS WON'T TAKE THE SAME NAME
if m == n1:
print m + " Already Assigned, Please Type a Different Name."
return False
return TrueStack Overflow用户
发布于 2018-01-05 09:30:55
你似乎忘记了在你的函数中缩进代码。
您还应该添加一个if __name__ == '__main__'行，以便可以像运行脚本一样运行您的代码：
python test.py
尝试以下代码：
test.py
def game_intro():
print "------------------ First Hero ------------------"
global n1
n1 = raw_input("Please Type a Name for Your Hero: ")
while not valid_name(n1):
print "------------------ First Hero ------------------"
n1 = raw_input("Please Type a Name for Your Hero: ")
print "------------------ Second Hero ------------------"
global n2
n2 = raw_input("Please Type a Name for Your Hero: ")
while not valid_name(n2):
print "------------------ Second Hero ------------------"
n2 = raw_input("Please Type a Name for Your Hero: ")
while not no_repeat(n2):
n2 = raw_input("Please Type a Name for Your Hero: ")
def valid_name(n):
if n == " ": # TO AVOID THE PLAYER GIVING A NAME AS SPACE
print "Your name can't be empty"
return False
elif n == "":
return False
return True
def no_repeat(m): # TO MAKE SURE THE PLAYERS WON'T TAKE THE SAME NAME
if m == n1:
print m + " Already Assigned, Please Type a Different Name."
return False
return True
if __name__ == '__main__':
game_intro()页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/48105436
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