Yii1是否有任何原生方法来获取构建了变量的原始SQL?
我尝试使用CDbExpression和CommandBuilder在一些子查询的基础上构建一个复杂查询。我得到的结果是:
SELECT * FROM `news` `t` WHERE id IN (:ycp0, :ycp1, :ycp2, :ycp3, :ycp4) LIMIT 5条件内容的转储:
CDbCriteria Object (
[select] => *
[condition] => id IN (:ycp0, :ycp1, :ycp2, :ycp3, :ycp4)
...
[params] => Array(
[:ycp0] => CDbExpression Object(
[expression] => SELECT id FROM `news` `t` WHERE (rubric=:rb1) AND (:im2 & `im`=:im2) LIMIT 1
[params] => Array(
[:rb1] => 1
[:im2] => 2
)
)
...
)
)我预计编译后的查询字符串如下:
SELECT * FROM .. WHERE id IN(
(SELECT id FROM .. WHERE .. ORDER BY .. LIMIT 1),
(SELECT id FROM .. WHERE .. ORDER BY .. LIMIT 1)
) ORDER BY .. LIMIT 5这就是我在代码中做的事情
$criteria = new CDbCriteria( ... );
$sql = $this->commandBuilder->createFindCommand($tableName, $criteria)->getText();
$queries[] = new CDbExpression($sql, $criteria->params);然后,我尝试将子查询组合为一个复杂的查询
$criteria = new CDbCriteria( ... );
$criteria->addInCondition('id', $queries);最后,我尝试以SQL-query的形式获得结果
$sql = $this->commandBuilder->createFindCommand($tableName, $criteria)->getText();发布于 2018-02-15 08:53:45
您可以在数据库配置中使用enableParamLogging (布尔值)。您可以对其进行设置,以便有条件地使用它--确保不在生产中使用它。
'db' => [
'connectionString' => 'mysql:host=' . $dbhost . ';port=' . $dbport . ';dbname=' . $dbname,
'emulatePrepare' => true,
'username' => $db_user,
'password' => $db_pass,
'schemaCachingDuration' => 3600,
'charset' => 'utf8',
'enableProfiling' => $db_profile,
'enableParamLogging' => $db_params,
],然后,如果希望在浏览器中查看所有输出,则可以将'class'=>'CWebLogRoute'添加到log路由。docs
发布于 2019-08-13 23:06:48
我认为您应该这样做:$criteria = ...; $command = $builder->createFindCommand($schema->getTable('name_of_table'), $criteria); $results = $command->text;
发布于 2020-10-06 13:31:14
您将获得带有params的SQL,如下所示
$sql = $this->commandBuilder->createFindCommand($tableName, $criteria)->getText();然后获取用引号括起来的参数:
$params = array_map(function($param) { return '"' . $param . '"'; }, $criteria->params);最后,替换成对的:
echo strtr($sql, $params);https://stackoverflow.com/questions/48793621
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