有一个关于“如何在Neo4j中为节点动态添加标签”的问题。有没有一种动态改变实体类型的方法?
举个例子:
@NodeEntity
public class User {
@Properties(prefix = "custom")
private Map userProperties;
}我从https://neo4j.com/blog/spring-data-neo4j-5-0-release/中看到,我可以创建动态属性。我也可以在运行时使用动态类型吗?我希望在需要时将"User“类型动态更改为"Consumer"/"Admin"/"Producer”。实体类型不是详尽的。
提前感谢!:)
发布于 2018-05-17 10:30:42
除了来自类和接口的主类型之外,Set<String>上还有一个存储/管理的@Labels注释。
发布于 2018-09-10 18:23:04
@Labels机制非常棒,对于许多用例来说,我认为这是最好的解决方案。
如果你想让另一个类从你的存储库中返回,那么确实需要做更多的工作。
我是在一个与音乐相关的项目中这样做的。我有Artist (不是抽象的,对于任何我不知道它是不是乐队的地方都是完全可用的)和Band和SoloArtist,它们是从Artist扩展而来的,还有其他的标签:
@NodeEntity
public class Artist {}
@NodeEntity
public class Band extends Artist{}在自定义存储库扩展中,我所知道的是:
interface ArtistRepository<T extends Artist> extends Repository<T, Long>, ArtistRepositoryExt {
Optional<T> findOneByName(String name);
// Specifying the relationships is necessary here because the generic queries won't recognize that
// Band has a relationship to country that _should_ be loaded with default depth of 1.
@Query("MATCH (n:Artist) WITH n MATCH p=(n)-[*0..1]-(m) RETURN p ORDER BY n.name")
List<T> findAllOrderedByName();
@Query("MATCH (n:Artist) WHERE id(n) = $id WITH n MATCH p=(n)-[*0..1]-(m) RETURN p")
Optional<T> findById(@Param("id") Long id);
<S extends T> S save(S artist);
}
interface ArtistRepositoryExt {
Band markAsBand(Artist artist);
SoloArtist markAsSoloArtist(Artist artist);
}
class ArtistRepositoryExtImpl implements ArtistRepositoryExt {
private static final String CYPHER_MARK_AS_BAND = String.format(
"MATCH (n) WHERE id(n) = $id\n" +
"OPTIONAL MATCH (n) - [f:BORN_IN] -> (:Country)\n" +
"REMOVE n:%s SET n:%s\n" +
"DELETE f",
SoloArtist.class.getSimpleName(),
Band.class.getSimpleName());
private static final String CYPHER_MARK_AS_SOLO_ARTIST = String.format(
"MATCH (n) WHERE id(n) = $id\n" +
"OPTIONAL MATCH (n) - [f:FOUNDED_IN] -> (:Country)\n" +
"REMOVE n:%s SET n:%s\n" +
"DELETE f",
Band.class.getSimpleName(),
SoloArtist.class.getSimpleName());
private final Session session;
public ArtistRepositoryExtImpl(Session session) {
this.session = session;
}
@Override
public Band markAsBand(Artist artist) {
session.query(CYPHER_MARK_AS_BAND, Map.of("id", artist.getId()));
// Needs to clear the mapping context at this point because this shared session
// will know the node only as class Artist in this transaction otherwise.
session.clear();
return session.load(Band.class, artist.getId());
}
@Override
public SoloArtist markAsSoloArtist(Artist artist) {
session.query(CYPHER_MARK_AS_SOLO_ARTIST, Map.of("id", artist.getId()));
// See above
session.clear();
return session.load(SoloArtist.class, artist.getId());
}
}虽然这很好用,但我将在更深层次的嵌套类场景中获得工作的想法。而且,如果你想以多态的方式使用存储库,你必须像我一样重新声明派生查找器方法。
我也有专门的存储库。
如果这个问题仍然与你相关,请让我知道你是否也适用。你可以在这里找到整个项目:
https://stackoverflow.com/questions/50332747
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