blocks|key|5857723|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5857724|var+list+=+[
++"john@yahoo.com",+"rami@gmail.com",
++"josh@yahoo.com",+"bale@gmail.com"
];
obj+=+{};
list.map(x+=>+x.split('@')[1]).forEach(x+=>+obj[x]+=+[])
list.forEach(email+=>+obj[email.split('@')[1]].push(email))
console.log(obj)
/*
{
++"yahoo.com":+[
"john@yahoo.com",
"josh@yahoo.com"
++],
++"gmail.com":+[
"rami@gmail.com",
"bale@gmail.com"
++]
}
*/|code-block|syntax|javascript|5857725|5857726|解释：创建了一个空的对象obj。然后，我在list上迭代，并通过list.map(x+=>+x.split('@')[1])检索了所有的域。|offset|length|style|BOLD|CODE|5857727|有了域之后，我将对象设置为具有结构{+'yahoo.com':+[],+'gmail.com':+[]+}|5857728|然后我再次迭代列表，如果域包含相应的部分，则添加电子邮件，给出结果对象。|5857729|编辑：也可以这样单次迭代完成：|5857730|5857731|var+list+=+[
++"john@yahoo.com",+"rami@gmail.com",
++"josh@yahoo.com",+"bale@gmail.com"
]
obj+=+{}
list.forEach(email+=>+{
++let+domain+=+email.split('@')[1]
++if+(!obj[domain])+obj[domain]+=+[]
++if+(obj[domain].indexOf(email)+<+0)+obj[domain].push(email)
})
console.log(obj)|5857732|5857733|在这里，我迭代列表，提取域，如果不存在，使用[]设置密钥，然后将电子邮件推送到该列表中。它还确保不会推送重复的电子邮件。|5857734|entityMap^0|0|0|0|0|2|C|3|L|4|W|U|0|H|10|0|0|0|2|0|0|0|0|M|2|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|15|8|@$J|16|K|17|L|M]|$J|18|K|19|L|N]|$J|1A|K|1B|L|N]|$J|1C|K|1D|L|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|1E|8|@$J|1F|K|1G|L|N]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1H|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|1I|8|@$J|1J|K|1K|L|M]]|9|@]|A|$]]|$1|U|3|4|5|6|7|1L|8|@]|9|@]|A|$]]|$1|V|3|W|5|D|7|1M|8|@]|9|@]|A|$E|F]]|$1|X|3|4|5|6|7|1N|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|6|7|1O|8|@$J|1P|K|1Q|L|N]]|9|@]|A|$]]|$1|10|3|-4|5|6|7|1R|8|@]|9|@]|A|$]]]|11|$]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var list = [
  "john@yahoo.com", "rami@gmail.com",
  "josh@yahoo.com", "bale@gmail.com"
];
obj = {};
list.map(x =&gt; x.split('@')[1]).forEach(x =&gt; obj[x] = [])
list.forEach(email =&gt; obj[email.split('@')[1]].push(email))
console.log(obj)
/*
{
  "yahoo.com": [
"john@yahoo.com",
"josh@yahoo.com"
  ],
  "gmail.com": [
"rami@gmail.com",
"bale@gmail.com"
  ]
}
*/</code></pre>
</div>
</div>
</p>

<p><strong>Explanation</strong>:
Created a blank object <code>obj</code>. Then I iterated on <code>list</code> and retrieved all the domains by <code>list.map(x =&gt; x.split('@')[1])</code>. </p>

<p>With domains in hand, I setup-ed the object to have the structure <code>{ 'yahoo.com': [], 'gmail.com': [] }</code></p>

<p>Then I iterated on list again and added the email if domain contained the corresponding part, giving resultant object.</p>

<p><strong>Edit</strong>:
It can also be done in single iteration this way:</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var list = [
  "john@yahoo.com", "rami@gmail.com",
  "josh@yahoo.com", "bale@gmail.com"
]
obj = {}
list.forEach(email =&gt; {
  let domain = email.split('@')[1]
  if (!obj[domain]) obj[domain] = []
  if (obj[domain].indexOf(email) &lt; 0) obj[domain].push(email)
})
console.log(obj)</code></pre>
</div>
</div>
</p>

<p>Here, I'm iterating on list, extracting the domain, setting up the key with <code>[]</code> if it doens't exist and then pushing the email into that. It also makes sure that no duplicate emails are pushed.</p>


blocks|key|4389420|text|如果在object中找到键，则可以简单地推送数组中的值，否则添加数组|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4389421|​|4389422|var+list+=+[
++"john@yahoo.com",+"rami@gmail.com",
++"josh@yahoo.com",+"bale@gmail.com"
];

(function()+{
++var+obj1+=+{};
++for+(var+a+=+0;+a+<+list.length;++a%2B%2B)+{
++++var+str+=+list[a].split("@");
++++if(obj1[str[1]])+{
++++++++obj1[str[1]].push(list[a])
++++}+else+{
++++++++obj1[str[1]]+=+[list[a]];+//arr.push(str[0])];
++++}
++};
++console.log(obj1);
})();|code-block|syntax|javascript|4389423|<script+src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>|4389424|4389425|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|K|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|M|$]]

<p>You can simply push the values in the array if the key is found in object otherwise add the array </p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var list = [
  "john@yahoo.com", "rami@gmail.com",
  "josh@yahoo.com", "bale@gmail.com"
];

(function() {
  var obj1 = {};
  for (var a = 0; a &lt; list.length;  a++) {
    var str = list[a].split("@");
    if(obj1[str[1]]) {
        obj1[str[1]].push(list[a])
    } else {
        obj1[str[1]] = [list[a]]; //arr.push(str[0])];
    }
  };
  console.log(obj1);
})();</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"&gt;&lt;/script&gt;</code></pre>
</div>
</div>
</p>


blocks|key|1638380|text|您的代码几乎是正确的，只有一个小错误，更改您的行：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1638381|Object.values(obj1[str[1]]).push(str[0])|code-block|syntax|javascript|1638382|至|1638383|obj1[str[1]].push(list[a]);|1638384|它工作得很好。|1638385|​|1638386|var+list+=+[
++"john@yahoo.com",+"rami@gmail.com",
++"josh@yahoo.com",+"bale@gmail.com"
];

(function()+{
++var+obj1+=+{};
++for+(var+a+=+0,+b+=+list.length;+b+>+a;+a%2B%2B)+{
++++var+str+=+list[a].split("@");
++++var+arr+=+[];
++++arr.push(str[0]);
++++if+(!(str[1]+in+obj1))+{
++++++obj1[str[1]]+=+[];+//arr.push(str[0])];
++++}

++++obj1[str[1]].push(list[a]);

++};
++console.log(obj1);
})();|1638387|<script+src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>|1638388|1638389|entityMap^0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|W|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|X|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Z|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|10|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|S|3|N|5|6|7|13|8|@]|9|@]|A|$]]|$1|T|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|U|$]]

<p>Your code is almost correct, there is just a minor bug, change your line:</p>

<pre><code>Object.values(obj1[str[1]]).push(str[0])
</code></pre>

<p>To</p>

<pre><code>obj1[str[1]].push(list[a]);
</code></pre>

<p>And it works fine.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var list = [
  "john@yahoo.com", "rami@gmail.com",
  "josh@yahoo.com", "bale@gmail.com"
];

(function() {
  var obj1 = {};
  for (var a = 0, b = list.length; b &gt; a; a++) {
    var str = list[a].split("@");
    var arr = [];
    arr.push(str[0]);
    if (!(str[1] in obj1)) {
      obj1[str[1]] = []; //arr.push(str[0])];
    }

    obj1[str[1]].push(list[a]);

  };
  console.log(obj1);
})();</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"&gt;&lt;/script&gt;</code></pre>
</div>
</div>
</p>


blocks|key|1638398|text|Array.prototype.reduce通常用于将array数据转换为object格式。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1638399|请看下面的实际示例|1638400|​|1638401|//+Emails.
const+emailAddresses+=+["bale@gmail.com",+"john@yahoo.com",+"rami@gmail.com","josh@yahoo.com"]

//+Group+By+Domain.
const+groupByDomain+=+addresses+=>+addresses.reduce((acc,+email)+=>+{
++const+[prefix,+domain]+=+email.split(/@/)
++const+exists+=+acc[domain]
++if+(exists)+acc[domain].push(email)
++else+acc[domain]+=+[email]
++return+acc
},+{})

//+Output.
const+output+=+groupByDomain(emailAddresses)

//+Proof.
console.log(output)|code-block|syntax|javascript|1638402|1638403|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce^0|0|M|R|5|11|6|0|M|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@$9|14|A|15|1|16]]|E|$]]|$1|F|3|G|5|6|7|17|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|18|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|19|8|@]|D|@]|E|$M|N]]|$1|O|3|I|5|6|7|1A|8|@]|D|@]|E|$]]|$1|P|3|-4|5|6|7|1B|8|@]|D|@]|E|$]]]|Q|$R|$5|S|T|U|E|$V|W]]]]

<p><a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce" rel="nofollow noreferrer"><code>Array.prototype.reduce</code></a> is typically used to translate <code>array</code> data to <code>object</code> form. </p>

<p>See below for a practical example </p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="true">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>// Emails.
const emailAddresses = ["bale@gmail.com", "john@yahoo.com", "rami@gmail.com","josh@yahoo.com"]

// Group By Domain.
const groupByDomain = addresses =&gt; addresses.reduce((acc, email) =&gt; {
  const [prefix, domain] = email.split(/@/)
  const exists = acc[domain]
  if (exists) acc[domain].push(email)
  else acc[domain] = [email]
  return acc
}, {})

// Output.
const output = groupByDomain(emailAddresses)

// Proof.
console.log(output)</code></pre>
</div>
</div>
</p>


<p>I am trying to convert an array(with email addresses) in to object.
How to insert values in value array for one key?</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var list = [
  "john@yahoo.com", "rami@gmail.com",
  "josh@yahoo.com", "bale@gmail.com"
];

(function() {
  var obj1 = {};
  for (var a = 0, b = list.length; b &gt; a; a++) {
    var str = list[a].split("@");
    var arr = [];
    arr.push(str[0]);
    if (!(str[1] in obj1)) {
      obj1[str[1]] = []; //arr.push(str[0])];
    }

    Object.values(obj1[str[1]]).push(str[0])

  };
  console.log(obj1);
})();</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"&gt;&lt;/script&gt;</code></pre>
</div>
</div>

expected output</p>

<pre><code>    {
    "gmail.com" : ["a","b","c"],
    "yahoo.com" : ["de","e","f"]
    }
</code></pre>

<p>I also want to add like </p>

<pre><code>    {
    "gmail.com" : [3],//1+1+1
    "yahoo.com" : [4]//1+1+1+1
    }
</code></pre>


insert values in array format for key in object in JavaScript

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在尝试将一个数组(带有电子邮件地址)转换为object。如何在一个key的值数组中插入值？​var list = [  "john@yahoo.com", "rami@gmail.com",  "josh@yahoo.com", "bale@gmail.com"];(function() {  var obj1 =...

问为JavaScript中对象中的键插入数组格式的值
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问为JavaScript中对象中的键插入数组格式的值EN