使用xpath从xml获取子节点值
使用xpath从xml获取子节点值
提问于 2018-06-27 17:46:04
<Demo_Test>
<Step ID="1">
<ACTION>Point</ACTION>
<CLASS_ID>dfsfsdf</CLASS_ID>
</Step>
<Step ID="2">
<ACTION>Point</ACTION>
<CLASS_ID>Avkddd</CLASS_ID>
</Step>
<Step ID="3">
<ACTION>Point</ACTION>
<CLASS_ID>afsasfa</CLASS_ID>
</Step>
<Step ID="4">
<ACTION>SubAction</ACTION>
<CLASS_ID>afsasfa</CLASS_ID>
</Step>
</Demo_Test>我想修改"CLASS_ID“的值，"Action”节点的值是"Point“，这是我在下面写的代码，但不起作用
string l_xPath = "//Step/ACTION["Point"]";
XmlNodeList l_nodeList = l_doc.SelectNodes(l_xPath);回答 4
Stack Overflow用户
发布于 2018-06-27 18:06:49
我使用xml linq将结果放入字典中
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Text.RegularExpressions;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = @"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
Dictionary<int, string> dict = doc.Descendants("Step")
.Where(x => (string)x.Element("ACTION") == "Point")
.GroupBy(x => (int)x.Attribute("ID"), y => (string)y.Element("CLASS_ID"))
.ToDictionary(x => x.Key, y => y.FirstOrDefault());
}
}
}Stack Overflow用户
发布于 2018-06-27 18:09:42
您可以使用以下命令：
var l_nodeList = l_doc.SelectNodes("//Step[ACTION='Point']");
foreach (XmlNode item in l_nodeList)
{
Console.WriteLine(item.SelectSingleNode("CLASS_ID").InnerText);
}但我更喜欢jdweng的答案
Stack Overflow用户
发布于 2018-06-27 18:10:23
首先，您需要一个如下所示的对象：
using System;
using System.Xml.Serialization;
using System.Collections.Generic;
namespace Xml2CSharp
{
[XmlRoot(ElementName="Step")]
public class Step {
[XmlElement(ElementName="ACTION")]
public string ACTION { get; set; }
[XmlElement(ElementName="CLASS_ID")]
public string CLASS_ID { get; set; }
[XmlAttribute(AttributeName="ID")]
public string ID { get; set; }
}
[XmlRoot(ElementName="Demo_Test")]
public class Demo_Test {
[XmlElement(ElementName="Step")]
public List<Step> Step { get; set; }
}
}然后，您可以使用此方法对xml进行反序列化：
public static T XmlDeserializer<T>(string xmlString)
{
var instance = default(T);
var xmlSerializer = new XmlSerializer(typeof(T));
using (var stringreader = new StringReader(xmlString))
instance = (T)xmlSerializer.Deserialize(stringreader);
return instance;
}然后像这样使用它：
var result = XmlDeserializer<Demo_Test >("your xml string here");
var l_nodeList =result.Step[0].CLASS_ID;页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51059554
复制相关文章
相似问题
腾讯云开发者
