我想在Docker容器内的MariaDB数据库中添加一个表。
考虑文件tree
$ tree
├── Dockerfile
└── sql
└── test.sql使用Dockerfile
FROM mariadb:latest
COPY sql/test.sql /docker-entrypoint-initdb.d/
ENV MYSQL_ROOT_PASSWORD test123
ENV MYSQL_DATABASE testDB
ENV MYSQL_USER toto
ENV MYSQL_PASSWORD test123
RUN apt-get update && apt-get -y install vim
EXPOSE 3306
CMD ["mysqld"]和sql文件
$ cat sql/test.sql
CREATE TABLE IF NOT EXISTS test (
id int NOT NULL AUTO_INCREMENT,
name varchar(32) NOT NULL,
PRIMARY KEY (id)
);
INSERT INTO test (name) VALUES
('Toto'),
('Jack'),
('Titi');我使用build --tag=mariadbtest .来构建映像,并使用
docker run --name mariadb -ti -d -p 3307:3306 mariatest当我登录时
mysql --host=0.0.0.0 --port=3307 mysql -u root -p我找不到测试台了。如何向数据库添加表?
发布于 2019-10-30 00:44:11
我已经测试了您的用例,到目前为止,我能够用.sql文件填充MariaDB:
除了为了更快地测试它而做的一些小改动之外,请注意,当您运行容器时,您绑定了错误的端口,在您的问题中,您输入了-p 3307:3306,而它必须是-p 3306:3306
文件树:
├── Dockerfile
└── test.sqlDockerfile:
FROM mariadb:latest
COPY test.sql /docker-entrypoint-initdb.d/
ENV MYSQL_ROOT_PASSWORD admin
ENV MYSQL_DATABASE test
ENV MYSQL_USER admin
ENV MYSQL_PASSWORD admin
EXPOSE 3306test.sql:
CREATE TABLE IF NOT EXISTS test (
id int NOT NULL AUTO_INCREMENT,
name varchar(32) NOT NULL,
PRIMARY KEY (id)
);
INSERT INTO test (name) VALUES
('Toto'),
('Jack'),
('Titi');构建镜像:
docker build -t "mariadb" .运行容器:
docker run --name mariadb -d -p 3306:3306 mariadb在我的例子中,分配的docker ip是172.17.0.2,因此我连接到DB:
mysql -h 172.17.0.2 -P 3306 --protocol=TCP --user=admin --password=admin然后告诉MySQL要使用哪个数据库:
mysql> USE test
Reading table information for completion of table and column names You can turn off this feature to get a quicker startup with -A
Database changed检查'test‘表是否存在:
mysql> show tables like "test";
+-----------------------+
| Tables_in_test (test) |
+-----------------------+
| test |
+-----------------------+
1 row in set (0.00 sec)并从表中选择所有内容:
mysql> SELECT * FROM test;
+----+------+
| id | name |
+----+------+
| 1 | Toto |
| 2 | Jack |
| 3 | Titi |
+----+------+
3 rows in set (0.01 sec)发布于 2018-09-30 07:59:12
不是让Docker初始化,而是在第一次连接后执行以下操作:
CREATE DATABASE testDB; -- (or was it mariadbtest??)
USE testDB; -- (same as above)
CREATE TABLE ...https://stackoverflow.com/questions/52074643
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