问无法覆盖可分页的Spring数据- Spring Neo4j

EN

我需要覆盖spring data提供的Pageable类，然后覆盖SimpleNeo4jRepository提供的findAll方法。

但是在这样做的时候，我在服务器启动Caused by: java.lang.IllegalArgumentException: Paging query needs to have a Pageable parameter! Offending method public abstract com.app.backend.repository.pagination.AppPage com.app.backend.repository.BaseRepository.findAll(com.app.backend.repository.pagination.AppPageRequest) at org.springframework.util.Assert.isTrue(Assert.java:116) ~[spring-core-5.0.8.RELEASE.jar:5.0.8.RELEASE] at org.springframework.data.repository.query.QueryMethod.<init>(QueryMethod.java:99) ~[spring-data-commons-2.0.9.RELEASE.jar:2.0.9.RELEASE] at org.springframework.data.neo4j.repository.query.GraphQueryMethod.<init>(GraphQueryMethod.java:41) ~[spring-data-neo4j-5.0.9.RELEASE.jar:5.0.9.RELEASE] at org.springframework.data.neo4j.repository.query.GraphQueryLookupStrategy.resolveQuery(GraphQueryLookupStrategy.java:49) ~[spring-data-neo4j-5.0.9.RELEASE.jar:5.0.9.RELEASE]时收到一个错误

以下是代码

public class AppPageRequest extends PageRequest implements Pageable {

  private AppPageRequest(int page, int size, Sort sort) {
    super(page - 1, size, sort);
  }

  public static AppPageRequest of(int page, int size) {
    return of(page, size, Sort.unsorted());
  }

  public static AppPageRequest of(int page, int size, Sort sort) {
    return new AppPageRequest(page, size, sort);
  }
}

@NoRepositoryBean
public interface BaseRepository<T, ID extends Serializable> extends Neo4jRepository<T, ID> {

  Page<T> findAll(AppPageRequest appPageRequest);
}

@NoRepositoryBean
public class BaseRepositoryImpl<T, ID extends Serializable> extends SimpleNeo4jRepository<T, ID> implements BaseRepository<T, ID> {

  public BaseRepositoryImpl(Class<T> domainClass, Session session) {
    super(domainClass, session);
  }

  public Page<T> findAll(AppPageRequest appPageRequest) {
    return super.findAll(appPageRequest);
  }
}