CELL_TYPE_STRING无法解析或不是字段
CELL_TYPE_STRING无法解析或不是字段
提问于 2018-09-26 17:31:59
堆栈跟踪
Exception in thread "main" java.lang.Error: Unresolved compilation problems:
CELL_TYPE_STRING cannot be resolved or is not a field
CELL_TYPE_NUMERIC cannot be resolved or is not a field
CELL_TYPE_BOOLEAN cannot be resolved or is not a field
at len.a.main(a.java:30)代码
package len;
import java.io.FileInputStream;
import java.util.ArrayList;
import java.util.Iterator;
import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.Row;
import org.apache.poi.ss.usermodel.Sheet;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
public class a {
public static void main(String[] args) throws Exception{
ArrayList data =new ArrayList();
FileInputStream f =new FileInputStream("E:\\leadsuite.xlsx");
XSSFWorkbook wb=new XSSFWorkbook(f);
Sheet s=wb.getSheet("test steps");
Iterator itr=s.iterator();
while(itr.hasNext())
{
Row r=(Row) itr.next();
Iterator cellitr=r.cellIterator();
while(cellitr.hasNext())
{
Cell celldata=(Cell) cellitr.next();
switch(celldata.getCellType())
{
case Cell.CELL_TYPE_STRING:
data.add(celldata.getStringCellValue());
break;
case Cell.CELL_TYPE_NUMERIC:
data.add(celldata.getNumericCellValue());
break;
case Cell.CELL_TYPE_BOOLEAN:
data.add(celldata.getBooleanCellValue());
break;
}
}
}
}
}回答 5
Stack Overflow用户
发布于 2018-09-26 20:06:30
enum是STRING、NUMERIC和BOOLEAN，丢弃CELL_TYPE_，它们是CellType enum的一部分
switch(celldata.getCellType()) {
case CellType.STRING:
data.add(celldata.getStringCellValue());
break;
case CellType.NUMERIC:
data.add(celldata.getNumericCellValue());
break;
case CellType.BOOLEAN:
data.add(celldata.getBooleanCellValue());
break;
}Stack Overflow用户
发布于 2019-03-30 19:05:07
如果您使用的是更新版本的Apache POI poi-4.0.1，则Cell.getCellType()将返回CellType枚举而不是整数，因此您的开关应如下所示：
now in CELL_TYPE_NUMERIC now now just NUMERIC remove CELL_TYPE_
while(cellitr.hasNext())
{
Cell celldata=(Cell) cellitr.next();
switch(celldata.getCellType())
{
case STRING:
data.add(celldata.getStringCellValue());
break;
case NUMERIC:
data.add(celldata.getNumericCellValue());
break;
case BOOLEAN:
data.add(celldata.getBooleanCellValue());
break;
}Stack Overflow用户
发布于 2019-07-23 23:25:17
试试这段代码。它起作用了..。您只需了解poi api版本，并关注poi api的新变化即可。
import java.io.FileInputStream;
import java.util.ArrayList;
import java.util.Iterator;
import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.Row;
import org.apache.poi.xssf.usermodel.XSSFSheet;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
public class A {
public static void main(String[] args) throws Exception{
ArrayList data = new ArrayList();
FileInputStream file = new FileInputStream("F://LeadSuite.xlsx");
XSSFWorkbook book = new XSSFWorkbook(file);
XSSFSheet s = book.getSheet("TestSteps");
Iterator itr = s.iterator();
while (itr.hasNext()) {
Row rowitr = (Row) itr.next();
Iterator cellitr = rowitr.cellIterator();
while(cellitr.hasNext()) {
Cell celldata = (Cell) cellitr.next();
switch(celldata.getCellType()) {
case STRING:
data.add(celldata.getStringCellValue());
break;
case NUMERIC:
data.add(celldata.getNumericCellValue());
break;
case BOOLEAN:
data.add(celldata.getBooleanCellValue());
break;
}
}
}
for (int i=0;i<data.size();i++) {
if(data.get(i).equals("Sharan")) {
System.out.println(data.get(i));
System.out.println(data.get(i+1));
System.out.println(data.get(i+2));
System.out.println(data.get(i+3));
}
if(data.get(i).equals("Kiran")) {
System.out.println(data.get(i));
System.out.println(data.get(i+1));
System.out.println(data.get(i+2));
System.out.println(data.get(i+3));
}
if(data.get(i).equals("Jhade")) {
System.out.println(data.get(i));
System.out.println(data.get(i+1));
System.out.println(data.get(i+2));
System.out.println(data.get(i+3));
}
}
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/52514468
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