blocks|key|5607847|text|您可以通过搜索可能带有"."的字母来搜索月、日和年|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5607848|import+re,+datetime
months+=+{b:a+for+a,+b+in+enumerate(['Jan.',+'Feb.',+'March',+'April',+'May',+'June',+'July',+'Aug.',+'Sept.',+'Oct.',+'Nov.',+'Dec.'],+1)}
def+convert_date(d:str)+->+str:
++month,+day,+year+=+d.split()
++return+datetime.datetime(int(year),+months[month],+int(day))

data+=+['Date+first+available+at+Amazon.ca:+Nov.+23+2017',+'Date+first+available+at+Amazon.ca:+March+27+2017',+'Date+first+available+at+Amazon.ca:+March+6+2018']
new_data+=+[re.findall('[a-zA-Z]%2B\.*\s\d%2B\s\d%2B$',+i)+for+i+in+data]
final_results+=+[convert_date(i[0])+for+i+in+new_data+if+i]|code-block|syntax|javascript|5607849|输出：|5607850|[datetime.datetime(2017,+11,+23,+0,+0),+datetime.datetime(2017,+3,+27,+0,+0),+datetime.datetime(2018,+3,+6,+0,+0)]|5607851|5607852|计时：|5607853|import+time
def+timeit(f):
++_t1+=+time.time()
++_+=+f()
++print(f'{f.__name__}:+completed+in+{time.time()-_t1}')

@timeit
def+ajax1234():
++new_data+=+[re.findall('[a-zA-Z]%2B\.*\s\d%2B\s\d%2B$',+i)+for+i+in+data]

@timeit
def+anthony():
++t+=+[re.findall('(Jan.%7CFeb.%7CMarch%7CApril%7CMay%7CJune%7CJuly%7CAug.%7CSept.%7COct.%7CNov.%7CDec.)[\d\s]%2B',+i)+for+i+in+data]|5607854|5607855|ajax1234:+completed+in+4.982948303222656e-05
anthony:+completed+in+3.314018249511719e-05|5607856|entityMap^0|B|3|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|14|8|@]|D|@]|E|$]]|$1|P|3|Q|5|6|7|15|8|@]|D|@]|E|$]]|$1|R|3|S|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|T|3|L|5|6|7|17|8|@]|D|@]|E|$]]|$1|U|3|V|5|H|7|18|8|@]|D|@]|E|$I|J]]|$1|W|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|X|$]]

You can search for the month, day, and year by searching for letters with a possible <code>"."</code>:

<pre><code>import re, datetime
months = {b:a for a, b in enumerate(['Jan.', 'Feb.', 'March', 'April', 'May', 'June', 'July', 'Aug.', 'Sept.', 'Oct.', 'Nov.', 'Dec.'], 1)}
def convert_date(d:str) -&gt; str:
 month, day, year = d.split()
 return datetime.datetime(int(year), months[month], int(day))

data = ['Date first available at Amazon.ca: Nov. 23 2017', 'Date first available at Amazon.ca: March 27 2017', 'Date first available at Amazon.ca: March 6 2018']
new_data = [re.findall('[a-zA-Z]+\.*\s\d+\s\d+$', i) for i in data]
final_results = [convert_date(i[0]) for i in new_data if i]
</code></pre>

Output:

<pre><code>[datetime.datetime(2017, 11, 23, 0, 0), datetime.datetime(2017, 3, 27, 0, 0), datetime.datetime(2018, 3, 6, 0, 0)]
</code></pre>

<hr>

Timings:

<pre><code>import time
def timeit(f):
 _t1 = time.time()
 _ = f()
 print(f'{f.__name__}: completed in {time.time()-_t1}')

@timeit
def ajax1234():
 new_data = [re.findall('[a-zA-Z]+\.*\s\d+\s\d+$', i) for i in data]

@timeit
def anthony():
 t = [re.findall('(Jan.|Feb.|March|April|May|June|July|Aug.|Sept.|Oct.|Nov.|Dec.)[\d\s]+', i) for i in data]
</code></pre>

Output:

<pre><code>ajax1234: completed in 4.982948303222656e-05
anthony: completed in 3.314018249511719e-05
</code></pre>

blocks|key|1361133|text|您可以尝试这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1361134|import+re
dlist+=+[
"Date+first+available+at+Amazon.ca:+Nov.+23+2017",
"Date+first+available+at+Amazon.ca:+March+27+2017",
"Date+first+available+at+Amazon.ca:+March+6+2018"]
print([re.search(r"(?<=\:+)[a-zA-Z]%2B\.*[0-9+]%2B"+,+each).group(0)+for+each+in+dlist])|code-block|syntax|javascript|1361135|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can try this:

<pre><code>import re
dlist = [
"Date first available at Amazon.ca: Nov. 23 2017",
"Date first available at Amazon.ca: March 27 2017",
"Date first available at Amazon.ca: March 6 2018"]
print([re.search(r"(?&lt;=\: )[a-zA-Z]+\.*[0-9 ]+" , each).group(0) for each in dlist])
</code></pre>

blocks|key|5607862|text|所以这是我的完整解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5607863|first_available+=+ff.find_elements(By.XPATH,+'//li[contains(.,+"Date+first+available")]')
regex_first_available+=+re.compile(r'(Jan%7CFeb%7CMarch%7CApril%7CMay%7CJune%7CJuly%7CAug%7CSept%7COct%7CNov%7CDec)[\d\s]%2B')

if+len(first_available)+>+0:
++++first_available+=+regex_first_available.search(first_available[0].text).group(0)
else:
++++first_available+=+ff.find_element(By.XPATH,+'//td[text()="Date+First+Available"]/following-sibling::td[1]').text.replace('.',+'')

try:
++++first_available+=+datetime.datetime.strptime(first_available,+'%25b+%25d+%25Y').strftime('%25Y-%25m-%25d')
except+ValueError:
++++first_available+=+datetime.datetime.strptime(first_available,+'%25B+%25d+%25Y').strftime('%25Y-%25m-%25d')|code-block|syntax|javascript|5607864|如果有人改进了这种方法，我会选择您的解决方案作为答案。|5607865|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

So here is my solution in full.

<pre><code>first_available = ff.find_elements(By.XPATH, '//li[contains(., "Date first available")]')
regex_first_available = re.compile(r'(Jan|Feb|March|April|May|June|July|Aug|Sept|Oct|Nov|Dec)[\d\s]+')

if len(first_available) &gt; 0:
 first_available = regex_first_available.search(first_available[0].text).group(0)
else:
 first_available = ff.find_element(By.XPATH, '//td[text()="Date First Available"]/following-sibling::td[1]').text.replace('.', '')

try:
 first_available = datetime.datetime.strptime(first_available, '%b %d %Y').strftime('%Y-%m-%d')
except ValueError:
 first_available = datetime.datetime.strptime(first_available, '%B %d %Y').strftime('%Y-%m-%d')
</code></pre>

If somebody improves this approach, I'll select your solution as the answer instead.

I'm scraping strings from HTML elements that contain dates. What I'm looking to do is extract the dates with a regular expression and then convert them to a different format using the <code>datetime</code> module. The strings follow the following format:

<pre><code>Date first available at Amazon.ca: Nov. 23 2017
Date first available at Amazon.ca: March 27 2017
Date first available at Amazon.ca: March 6 2018
</code></pre>

The tricky thing about this is that only the months with long names are abbreviated.

<pre><code>Jan.
Feb.
March
April
May
June
July
Aug.
Sept.
Oct.
Nov.
Dec.
</code></pre>

My first idea was to select everything but <code>Date first available at Amazon.ca:</code>, but clearly this is a bit more difficult to do than I had first imagined.

My next idea was something like <code>r'^(J|F|M|A|S|O|De)'</code>, but this obviously won't work since the months aren't located at the beginning of the string.

Now I'm stuck for ideas.

Obviously something like the following regular expression will work, but it seems overly verbose.

<code>r'(Jan.|Feb.|March|April|May|June|July|Aug.|Sept.|Oct.|Nov.|Dec.)[\d\s]+'</code>

Datetime and RegEx Dates

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我从包含日期的HTML元素中抓取字符串。我要做的是使用正则表达式提取日期，然后使用datetime模块将它们转换为不同的格式。字符串遵循以下格式：Date first available at Amazon.ca: Nov. 23 2017Date first available at Amazon.ca: March...

问Datetime和RegEx日期
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