blocks|key|3283135|text|使用下面的代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3283136|>>>+import+re
>>>+txt
'Dated:+February+4,+2011+THE+REAL+COMPANY,+INC'

>>>+re.findall('([A-Z][A-Z]%2B)',+txt)
['THE',+'REAL',+'COMPANY',+'INC']|code-block|syntax|javascript|3283137|另一种方法是@davedwards建议的：|3283138|>>>+re.findall('[A-Z\s]{3,}.*',+txt)
['+THE+REAL+COMPANY,+INC']|3283139|说明：|offset|length|style|BOLD|3283140|3283141|+A-Z\s{3，}.*匹配以下列表中存在的单个字符A-Z\s{3，}+{3，}量词-匹配3到无限次，尽可能多，按需返回(贪婪)+A-Z+A-Z+A(索引65)和Z(索引90)+(区分大小写)范围内的单个字符\s匹配任何空白字符(等于\r\n\t\f\v+)量词匹配任何字符(行终止符除外)*+.*+-匹配0到无限次，尽可能多次，根据需要返回(贪婪)量词|blockquote|3283142|3283143|entityMap^0|0|0|0|0|0|3|0|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Z|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|11|8|@$M|12|N|13|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|14|8|@]|9|@]|A|$]]|$1|R|3|S|5|T|7|15|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|16|8|@]|9|@]|A|$]]|$1|V|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|W|$]]

what about using:

<pre><code>&gt;&gt;&gt; import re
&gt;&gt;&gt; txt
'Dated: February 4, 2011 THE REAL COMPANY, INC'

&gt;&gt;&gt; re.findall('([A-Z][A-Z]+)', txt)
['THE', 'REAL', 'COMPANY', 'INC']
</code></pre>

Another way around is as follows as suggested by @davedwards:

<pre><code>&gt;&gt;&gt; re.findall('[A-Z\s]{3,}.*', txt)
[' THE REAL COMPANY, INC']
</code></pre>

Explanation:

<blockquote>
<pre><code>[A-Z\s]{3,}.*

Match a single character present in the list below [A-Z\s]{3,}

{3,} Quantifier — Matches between 3 and unlimited times, as many times as possible, giving back as needed (greedy)

A-Z a single character in the range between A (index 65) and Z (index 90) (case sensitive)

\s matches any whitespace character (equal to [\r\n\t\f\v ])

.* matches any character (except for line terminators)

* Quantifier — Matches between zero and unlimited times, as many times as possible, giving back as needed (greedy)
</code></pre>
</blockquote>

blocks|key|3283162|text|你可以使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3283163|%5EDated:.*?\s([A-Z+,]{3,})|code-block|syntax|javascript|3283164|并利用第一个捕获组，请参见。|3283165|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You could use

<pre><code>^Dated:.*?\s([A-Z ,]{3,})
</code></pre>

And make use of the first capturing group, see <a href="https://regex101.com/r/Qr3CMh/1/" rel="nofollow noreferrer">a demo on regex101.com</a>.

blocks|key|1703241|text|您的正则表达式[A-Z\s]{3,}.*INC匹配大写字符或空白字符3次或更多次，然后是0%2B，再乘以任何字符，然后是将匹配的INC：THE+REAL+COMPANY,+INC|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1703242|您还可以做的是匹配日期:从字符串的开头开始，然后是类似日期的格式，然后捕获组中后面的内容。您的值将在第一个捕获组中：|1703243|%5EDated:\s%2B\S%2B\s%2B\d{1,2},\s%2B\d{4}\s%2B(.*)$|1703244|说明|BOLD|1703245|1703246|%5EDated:\s%2B匹配日期:依次为空格character|unordered-list-item|1703247|\S%2B\s%2B匹配日期为1%2B，空格为非空格字符，后跟1%2B为空格字符，在此case|1703248|\d{1,2},匹配中为2月1-2次digit|1703249|\s%2B\d{4}\s%2B匹配character|1703250|(.*)为空格字符(4位)，然后为1%2B为空格character|1703251|(.*)组中的空格character|1703252|$捕获时间0%2B任何字符串的末尾|1703253|1703254|Regex+demo|1703255|entityMap|0|LINK|mutability|MUTABLE|url|https://regex101.com/r/vl0Yys/1^0|7|G|1U|L|0|0|0|14|0|0|2|0|0|0|A|0|0|6|0|0|8|0|0|B|0|0|4|0|0|4|0|0|1|0|0|0|A|0|0^^$0|@$1|2|3|4|5|6|7|1D|8|@$9|1E|A|1F|B|C]|$9|1G|A|1H|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1I|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|1J|8|@$9|1K|A|1L|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|1M|8|@$9|1N|A|1O|B|L]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|1P|8|@]|D|@]|E|$]]|$1|N|3|O|5|P|7|1Q|8|@$9|1R|A|1S|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|P|7|1T|8|@$9|1U|A|1V|B|C]]|D|@]|E|$]]|$1|S|3|T|5|P|7|1W|8|@$9|1X|A|1Y|B|C]]|D|@]|E|$]]|$1|U|3|V|5|P|7|1Z|8|@$9|20|A|21|B|C]]|D|@]|E|$]]|$1|W|3|X|5|P|7|22|8|@$9|23|A|24|B|C]]|D|@]|E|$]]|$1|Y|3|Z|5|P|7|25|8|@$9|26|A|27|B|C]]|D|@]|E|$]]|$1|10|3|11|5|P|7|28|8|@$9|29|A|2A|B|C]]|D|@]|E|$]]|$1|12|3|-4|5|6|7|2B|8|@]|D|@]|E|$]]|$1|13|3|14|5|6|7|2C|8|@]|D|@$9|2D|A|2E|1|2F]]|E|$]]|$1|15|3|-4|5|6|7|2G|8|@]|D|@]|E|$]]]|16|$17|$5|18|19|1A|E|$1B|1C]]]]

Your regex <code>[A-Z\s]{3,}.*INC</code> matches 3 or more times an uppercase character or a whitespace character followed by 0+ times any character and then INC which will match: <code>THE REAL COMPANY, INC</code>

What you could also do is match Dated: from the start of the string followed by a date like format and then capture what comes after in a group. Your value will be in the first capturing group:

<code>^Dated:\s+\S+\s+\d{1,2},\s+\d{4}\s+(.*)$</code>

Explanation

<ul>
<li><code>^Dated:\s+</code> Match dated: followed by 1+ times a whitespace character</li>
<li><code>\S+\s+</code> Match 1+ times not a whitespace character followed by 1+ times a whitespace character whic will match February in this case</li>
<li><code>\d{1,2},</code> Match 1-2 times a digit</li>
<li><code>\s+\d{4}\s+</code> match 1+ times a whitespace character, 4 digits, followed by 1+ times a whitespace character</li>
<li><code>(.*)</code> Capture in a group 0+ times any character</li>
<li><code>$</code> Assert the end of the string</li>
</ul>

<a href="https://regex101.com/r/vl0Yys/1" rel="nofollow noreferrer">Regex demo</a>

I am using python regex to read documents.

I have the following line in many documents:

<pre><code>Dated: February 4, 2011 THE REAL COMPANY, INC
</code></pre>

I can use python text search to easily find the lines that have "dated," but I want to pull THE REAL COMPANY, INC from the text without getting the "February 4, 2011" text.

I have tried the following:

<pre><code>[A-Z\s]{3,}.*INC
</code></pre>

My understanding of this regex is it should get me all capital letters and spaces before LLP, but instead it pulls the full line. 

This suggests to me I'm fundamentally missing something about how regex works with capital letters. Is there an easy and obvious explanation I'm missing?

Regex: Separating All Caps from Numbers

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在使用python regex来读取文档。我在很多文档中都有下面这一行：Dated: February 4, 2011 THE REAL COMPANY, INC我可以使用python文本搜索来轻松地找到带有“日期”的行，但我想从文本中提取真正的公司，公司，而不是获得“2011年2月4日”文本。我尝试过以下几种方法...

问正则表达式:从数字中分离所有大写
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