正如评论中所指出的,对于像这样的列表,this相关问题的大多数答案(如果不是所有答案)都会失败:
ls = [1,2,[3,4]]此外,列表可以嵌套得更深。如何部分展平到用户给定的级别(默认情况下展平到无穷大)
ls2 = [1,[2,3],[4,[5,6]]]ls2的所需输出
展平到级别1:
[1,2,3,4,[5,6]]展平到级别2(或更高)
[1,2,3,4,5,6]发布于 2019-03-02 00:49:04
您可以递归地执行此操作:
def flatten(l, level=None):
if level == 0:
return l
flattened = []
for item in l:
if isinstance(item, list):
flattened.extend(flatten(item, level-1 if level is not None else None))
else:
flattened.append(item)
return flattened
ls2 = [1,[2,3],[4,[5,6]]]
print(flatten(ls2, level=1))
# [1, 2, 3, 4, [5, 6]]
print(flatten(ls2, level=2))
# [1, 2, 3, 4, 5, 6]
print(flatten(ls2))
# [1, 2, 3, 4, 5, 6]发布于 2019-03-02 01:01:24
一种方法就是这样做
ls2 = [1,[2,3],[4,[5,6]]]
def make_list_of_list(a):
return [[i]if not isinstance(i, list) else i for i in a]
def flatten(l):
return [item for sublist in make_list_of_list(l) for item in sublist]
flatten(ls2) will result in [1, 2, 3, 4, [5, 6]]
flatten(flatten(ls2)) will result in [1, 2, 3, 4, 5, 6]https://stackoverflow.com/questions/54948803
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