我有两个选择,我需要在第一个填完后再填第二个。因此,实际情况如下所示:
1)将#main_container dropdown设置为2) 2)触发ajax调用,并根据#main_container的值获取子级dropdown的内容(在本例中为2) 3)在窗体上显示子dropdown 2) 3)之后,将child dropdown 2的值设置为400,这样最终结果应为Bag黄色,同时显示Bag Green
main_container的逻辑被放在onchange事件中,它只获取并显示dropdowns。它没有设置它的值。据我所知,我可以在这里使用$.deferred,但我不知道如何在onchange事件之外等待promise。
任何想法都是受欢迎的。谢谢。
$(document).ready(function(){
    $('#main_container').val(2);
    $('#main_container').trigger('change');// onchange event is triggered, waiting for child_2 dropdown
    $('#child_2').val(400);//setting child_2 value here (done immediately)
});
$('#main_container').change(function() {
  $('.child').hide();    
  if($(this).val() == 1){
      $('#child_1').show(700); // AJAX call here in real       
    }else if($(this).val() == 2){
      $('#child_2').show(700); // AJAX call here in real
   }else{
      $('#child_3').show(700); // AJAX call here in real
   }
});div {
  padding: 5px 10px;
}
div.child {
  display: none
}
select {
  width: 200px;
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<div class="option">
  <select name="container" id="main_container" data-parent="true" data-parent_id="10">
  <option value="">--- Select a container---</option>
		<option value="1">Box</option>
		<option value="2">Bag</option>
		<option value="3">Pallet</option>
	</select>
</div>
<div class="child option" id="child_1" style="display:none;">
  <select name="box color">
		<option value="100">Red</option>
		<option value="200">Blue</option>
	</select>
</div>
<div class="child option" id="child_2" style="display:none;">
  <select name="bag color">
		<option value="300">Green</option>
		<option value="400">Yellow</option>
	</select>
</div>
<div class="child option" id="child_3" style="display:none;">
  <select name="pallet color">
		<option value="500">Black</option>
		<option value="600">Yellow</option>
	</select>
</div>
发布于 2019-06-05 17:55:35
我已经更新了代码并找到了解决方案,如下所示:
    <!DOCTYPE html>
<html>
<head>
    <title></title>
</head>
<body>
    <style type="text/css">
        div {
            padding: 5px 10px;
        }
        div.child {
            display: none
        }
        select {
            width: 200px;
        }
    </style>
    <div id="main_div">
        <div class="option">
            <select name="container" id="main_container">
                <option value="">--- Select a container---</option>
                <option value="1">Box</option>
                <option value="2">Bag</option>
                <option value="3">Pallet</option>
            </select>
        </div>
    </div>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
    <script type="text/javascript">
        var child_2_div = '<div class="child option" id="child_2" style="display:block;">'+
                                '<select name="bag color" id="child_2_select">'+
                                    '<option value="300">Green</option>'+
                                    '<option value="400">Yellow</option>'+
                                '</select>'+
                            '</div>'; 
        var timerId, dfd;
        function appender(){
            console.log('appender called');
            $('#main_div').append(child_2_div);
            clearInterval(timerId);
            dfd.resolve();
            console.log('logging dfd1');
            console.log(dfd);
        }
        $(document).ready(function(){
            $('#main_container').val(2);
            $('#main_container').trigger('change');// onchange event is triggered, waiting for child_2 dropdown
            $.when(dfd).then(function(){
                console.log('logging dfd2');
                console.log(dfd);
                $('#child_2_select').val(400);
            }); //setting child_2 value here (done immediately)
        });
        $('#main_container').change(function() {
            $('.child').hide(); 
            $('#child_2').remove();
            if($(this).val() == 2){
                dfd = $.Deferred();
                timerId = setInterval(appender, 1000);
            }else{
                $('#child_3').show(700); // AJAX call here in real
            }
        });
    </script>
</body>
</html>https://stackoverflow.com/questions/56444628
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