blocks|key|4746431|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4746432|import+random

nums+=+set()
while+len(nums)+<+4:+#+change+4+to+appropriate+number
++++nums.add(random.randint(0,+1000000))|code-block|syntax|javascript|4746433|例如：|4746434|>>>+nums
set([10928,+906930,+617690,+786206])|4746435|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Try this:

<pre><code>import random

nums = set()
while len(nums) &lt; 4: # change 4 to appropriate number
 nums.add(random.randint(0, 1000000))
</code></pre>

For example:

<pre><code>&gt;&gt;&gt; nums
set([10928, 906930, 617690, 786206])
</code></pre>

blocks|key|3278349|text|是的，为了让生活变得简单，让我们使用一个简单的例子。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3278350|#lets+import+random,+to+generate+random+stuff
import+random
#create+a+result+string
result+=+''
nums+=+[1,2,3,4,5,6,7,8,9,0]
for+i+in+range(6):
++++result+%2B=+str(random.choice(nums))

print(result)|code-block|syntax|javascript|3278351|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

yes, to make life easy lets use an easy example.

<pre><code>#lets import random, to generate random stuff
import random
#create a result string
result = ''
nums = [1,2,3,4,5,6,7,8,9,0]
for i in range(6):
 result += str(random.choice(nums))

print(result)
</code></pre>

blocks|key|962457|text|UUID用于生成通用唯一标识符，它具有特定的结构，并不是您想要的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|962458|您可以按如下方式使用random模块|offset|length|style|CODE|962459|import+random
id+=+''.join(str(random.randint(0,10))+for+x+in+range(6))
print(id)|code-block|syntax|javascript|962460|这是做什么的？|962461|962462|randint生成一个介于0和10+(包括0和10)之间的随机数，即0-9+digits|unordered-list-item|962463|str调用for+x+in+range(6)生成6个随机数字将数字转换为|962464|从数字形成单个字符串|962465|entityMap^0|0|A|6|0|0|0|0|0|7|0|0|3|5|H|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@$D|10|E|11|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|13|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]|$1|P|3|Q|5|R|7|15|8|@$D|16|E|17|F|G]]|9|@]|A|$]]|$1|S|3|T|5|R|7|18|8|@$D|19|E|1A|F|G]|$D|1B|E|1C|F|G]]|9|@]|A|$]]|$1|U|3|V|5|6|7|1D|8|@]|9|@]|A|$]]|$1|W|3|-4|5|6|7|1E|8|@]|9|@]|A|$]]]|X|$]]

UUID is for generating Universally Unique Identifiers, which have a particular structure and won't be what you're after.

You can use the <code>random</code> module as follows

<pre class="lang-py prettyprint-override"><code>import random
id = ''.join(str(random.randint(0,10)) for x in range(6))
print(id)
</code></pre>

What does this do?

<ul>
<li><code>randint</code> generates a random number between 0 inclusive and 10 exclusive, i.e. 0-9</li>
<li>calling this with <code>for x in range(6)</code> generates six random digits</li>
<li><code>str</code> converts the digits to strings</li>
<li><code>''.join</code> forms a single string from the digits</li>
</ul>

blocks|key|4746569|text|您可以使用标准python库中的random|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4746570|random.randint(a，b)|4746571|返回一个随机整数N，使得a+<=+N+<=+b。|4746572|https://docs.python.org/3/library/random.html#random.randint|4746573|In+[1]:+from+random+import+randint+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

In+[2]:+randint(1_000,+999_999)++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Out[2]:+587848

In+[3]:+randint(1_000,+999_999)++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Out[3]:+316441|code-block|syntax|javascript|4746574|entityMap|0|LINK|mutability|MUTABLE|url^0|G|6|0|0|0|0|1O|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|10|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|11|8|@]|D|@]|E|$]]|$1|J|3|K|5|6|7|12|8|@]|D|@$9|13|A|14|1|15]]|E|$]]|$1|L|3|M|5|N|7|16|8|@]|D|@]|E|$O|P]]|$1|Q|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|K]]]]

You can use <code>random</code> from standard python library

random.randint(a, b) 
Return a random integer N such that a &lt;= N &lt;= b. 

<a href="https://docs.python.org/3/library/random.html#random.randint" rel="nofollow noreferrer">https://docs.python.org/3/library/random.html#random.randint</a>

<pre><code>In [1]: from random import randint 

In [2]: randint(1_000, 999_999) 
Out[2]: 587848

In [3]: randint(1_000, 999_999) 
Out[3]: 316441
</code></pre>

blocks|key|4746603|text|要通过指定令牌的长度来生成N个随机数或令牌，这将是一个简单而可行的解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4746604|import+random

#num[]:+by+the+combination+of+this,+a+random+number+or+token+will+be+generated.
nums+=+[1,2,3,4,5,6,7,8,9,0]+

#all+the+tokens+or+random+number+will+be+stored+in+a+set+called+tokens.
#here,+we+are+using+a+set,+because+the+set+will+never+contain+duplicate+values.
tokens+=+set()

result=''+#to+store+temporaray+values

while+len(tokens)+<+10000:+#+change+10000+to+the+appropriate+number+to+define+the+numbers+of+the+random+numbers+you+want+to+generate.
++++#change+6+to+appropiate+number+to+defined+the+length+of+the+random+number.++
++++for+i+in+range(6):
++++++++result%2B=str(random.choice(nums))
++++++++tokens.add(result)
++++++++result=''


print(tokens)
#print(len(tokens))
#print(type(tokens))|code-block|syntax|javascript|4746605|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To generate N number of a random number or token by specifying a length of Token this will be an easy and feasible solution.

<pre><code>import random

#num[]: by the combination of this, a random number or token will be generated.
nums = [1,2,3,4,5,6,7,8,9,0] 

#all the tokens or random number will be stored in a set called tokens.
#here, we are using a set, because the set will never contain duplicate values.
tokens = set()

result='' #to store temporaray values

while len(tokens) &lt; 10000: # change 10000 to the appropriate number to define the numbers of the random numbers you want to generate.
 #change 6 to appropiate number to defined the length of the random number. 
 for i in range(6):
 result+=str(random.choice(nums))
 tokens.add(result)
 result=''


print(tokens)
#print(len(tokens))
#print(type(tokens))
</code></pre>

blocks|key|3278425|text|如果您想使用uuid生成数字，那么您可以编写如下代码|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3278426|digit+=+5+++#+digits+in+number+

import+uuid
for+i+in+range(6):
++print(uuid.uuid4().int[:digit])|code-block|syntax|javascript|3278427|或|3278428|from+uuid+import+uuid4
result+=+[+uuid4().int[:5]+for++i+in+range(6)+]|3278429|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

if you want to use uuid to generate number then you can code something like this 

<pre><code>digit = 5 # digits in number 

import uuid
for i in range(6):
 print(uuid.uuid4().int[:digit])
</code></pre>

Or 

<pre><code>from uuid import uuid4
result = [ uuid4().int[:5] for i in range(6) ]
</code></pre>

I am trying to generate 4-6 unique numbers in python but when I do <code>uuid.uuuid4()</code>, it generates something like <code>23dfsFe823FKKS023e343431</code>. Is there a way I can achieve this, generate 4-6 unique numbers like 19391 or 193201. 

NB: Beginner with python

How to generate 4-6 unique numbers

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我试图在python中生成4-6个唯一的数字，但当我执行uuid.uuuid4()时，它会生成类似于23dfsFe823FKKS023e343431的东西。有没有办法可以做到这一点，生成4-6个唯一的数字，如19391或193201。注: python初学者

问如何生成4-6个唯一的数字
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回答 6

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