blocks|key|2443395|text|这是一个使用您的代码的完整的工作示例。这是否显示了您所指的行为？确实有乌龟在互相追逐。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2443396|to+setup
++clear-all
++create-turtles+100+[+setxy+random-xcor+random-ycor+]
++reset-ticks
end

to+go
++let+rad+5
++ask+turtles
++[+let+target-patch+max-one-of+patches+in-radius+rad+[count+turtles-here]
++++if+count+turtles-on+target-patch+>=+count+turtles-here++++++++++++++;+comment+1
++++[+if+count+turtles-on+patches+in-radius+rad+>+count+turtles-here++++;+comment+2
++++++[+face+target-patch
++++++++forward+1
++++++]
++++]
++]
++tick
end|code-block|syntax|javascript|2443397|如果是这样的话，看看我评论的这两行。|2443398|注释1：>=意味着，即使海龟已经在最高计数的补丁上，这个条件也会得到满足，因为count+turtles-here将等于最高计数补丁(该补丁)上的海龟计数。|offset|length|style|CODE|2443399|注释2:这条线意味着只要在半径内的任何一个斑块上都有海龟，而不是在询问海龟的特定斑块上，那么海龟就会向前移动。|2443400|如果你只想让乌龟在不是最大数量补丁的情况下移动，可以尝试这样做：|2443401|to+setup
++clear-all
++create-turtles+100+[+setxy+random-xcor+random-ycor+]
++reset-ticks
end

to+go
++let+rad+5
++ask+turtles
++[+let+target-patch+max-one-of+patches+in-radius+rad+[count+turtles-here]
++++if+count+turtles-on+target-patch+>+count+turtles-here
++++[+face+target-patch
++++++forward+1
++++]
++]
++tick
end|2443402|我去掉了注释1行中的=，并完全删除了第二个条件，所以现在如果当前补丁中的海龟比它们发现的补丁更少(严格地说，不是<=)，这些海龟就会移动。|2443403|entityMap^0|0|0|0|13|I|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|11|8|@$K|12|L|13|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|14|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|15|8|@]|9|@]|A|$]]|$1|S|3|T|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|U|3|V|5|6|7|17|8|@]|9|@]|A|$]]|$1|W|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|X|$]]

This is a complete working example that uses your code. Is this displaying the behaviour you mean? It does have turtles chasing each other.

<pre><code>to setup
 clear-all
 create-turtles 100 [ setxy random-xcor random-ycor ]
 reset-ticks
end

to go
 let rad 5
 ask turtles
 [ let target-patch max-one-of patches in-radius rad [count turtles-here]
 if count turtles-on target-patch &gt;= count turtles-here ; comment 1
 [ if count turtles-on patches in-radius rad &gt; count turtles-here ; comment 2
 [ face target-patch
 forward 1
 ]
 ]
 ]
 tick
end
</code></pre>

If so, have a look at the two lines I have comments on.

Comment 1: The >= means that, even if the turtles are already on the highest count patch, this condition will be satisfied because <code>count turtles-here</code> will be equal to the count of the turtles on the highest count patch (this patch).

Comment 2: This line means that as long as there are any turtles on any patch within the radius but not on the particular patch where the asking turtle is located, then the turtle will move forward.

If you want to only have turtles move if not on a maximum count patch, try this instead:

<pre><code>to setup
 clear-all
 create-turtles 100 [ setxy random-xcor random-ycor ]
 reset-ticks
end

to go
 let rad 5
 ask turtles
 [ let target-patch max-one-of patches in-radius rad [count turtles-here]
 if count turtles-on target-patch &gt; count turtles-here
 [ face target-patch
 forward 1
 ]
 ]
 tick
end
</code></pre>

I took out the = in the comment 1 line and removed the second condition entirely so now the turtles move if their current patch has fewer (strictly, not &lt;=) turtles than the patch they've spotted.

blocks|key|2313037|text|我同意之前的帖子，但有一些额外的信息。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2313038|如果您想在每次迭代中完全移动到目标面片，而不是只向目标面片移动一步，在上面的答案中，您可以替换产生一步运动的代码。|offset|length|style|BOLD|2313039|[+face+target-patch
++forward+1
]|code-block|syntax|javascript|2313040|使用|2313041|+[+
++++move-to+target-patch
+]|2313042|我通过实验证实，这两种移动方法的结果将产生相似但略有不同的结果。|2313043|entityMap^0|0|X|O|0|0|0|2|0|0|0|W|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@$D|W|E|X|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|Y|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|Z|8|@$D|10|E|11|F|G]]|9|@]|A|$]]|$1|O|3|P|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|13|8|@$D|14|E|15|F|G]]|9|@]|A|$]]|$1|S|3|-4|5|6|7|16|8|@]|9|@]|A|$]]]|T|$]]

I agree with the previous post, but have some additional information.

If you want to move entirely to the target patch on each iteration, instead of moving just one step towards the target patch, in the above answer you could replace the code which produces one step of motion

<pre><code>[ face target-patch
 forward 1
]
</code></pre>

with

<pre><code> [ 
 move-to target-patch
 ]
</code></pre>

I confirmed by experimentation that the results of the two methods of moving will produce similar but somewhat different results.

I want to compare the patches in a certain radius regarding the amount of a certain class of agents on them. The agents should move to the patch where the most agents (in this case humans) are. If they are already on the patch with the most humans then they must not move. I coded it and the humans group but most of them don't stay and run around in lines (one behind the other). Would be great if anyone of you could have a quick look at my code. Thanks

<pre><code>if Strategy = "Gathering-Simple" [

 if ((count(humans-on max-one-of patches in-radius rad [count(humans-here)] )) ) &gt;= count(humans-here) [
 if count(humans-on patches in-radius rad) - count(humans-here) &gt; 0 [


 face max-one-of patches in-radius rad [count(humans-here)]
 fd 1
 ]]
 ]
</code></pre>

Comparing patches

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

我想要比较特定半径内的补丁，关于它们上的特定类别的代理的数量。代理应该移动到大多数代理(在本例中是人类)所在的补丁。如果它们已经在人类最多的补丁上，那么它们就不能移动。我对它和人类组进行了编码，但他们中的大多数人都不会留下来，也不会排成一行(一排接一排)。如果你们中的任何人能快速浏览一下我的代码，那就太好了。谢谢if ...

问比较补丁
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问比较补丁EN