比较两个不同格式的列表
比较两个不同格式的列表
提问于 2019-11-22 04:23:29
我有两份清单：
influx = [u'mphhos-fnwp-010101-2',
u'mphhos-fnwp-010101-1',
u'mphhos-fnwp-010101-7',
u'mphhos-fnwp-010101-10',
u'mphhos-fnwp-010101-9',
u'mphhos-fnwp-010101-4',
u'mphhos-fnwp-010101-3',
u'mphhos-fnwp-010101-8',
u'mphhos-fnwp-010101-6',
u'mphhos-fnwp-010101-5',
u'mphhos-fnwp-010101-11']
etcd =[u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-4',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-9',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-1',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-10',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-3',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-6',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-7',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-8',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-11',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-2',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-5']Etcd是父级列表，我想将influx与Etcd进行比较。
1.)我想要获取列表中不存在的所有元素并返回它们。
2.)如何通过省略/xymon/fnwp/mphhos/将etcd列表转换为涌入列表格式
上面的任何一个问题都会给出我的解决方案。
我尝试了很多方法，但我没有得到我的解决方案，因为它们是不同的格式。
我将通过执行set(etcd)-set(influx)得到我的答案，但由于它们的格式不同，所以我将获得列表中的所有项目。
回答 3
Stack Overflow用户
发布于 2019-11-22 04:56:50
str.rsplit
[x for x in etcd if x.rsplit('/', 1)[1] not in influx]Per rafaelc的建议
infx = set(influx)
[x for x in etcd if x.rsplit('/', 1)[1] not in infx]Stack Overflow用户
发布于 2019-11-22 04:29:17
一个简单的解决方案是删除前缀
for i, char in enumerate(etcd):
char = char.replace('/xymon/fnwp/mphhos/', '')
etcd[i] = char然后你可以使用set()找出不同之处。
Stack Overflow用户
发布于 2019-11-22 04:32:06
influx = [u'mphhos-fnwp-010101-2',
u'mphhos-fnwp-010101-1',
u'mphhos-fnwp-010101-7',
u'mphhos-fnwp-010101-10',
u'mphhos-fnwp-010101-9',
u'mphhos-fnwp-010101-4',
u'mphhos-fnwp-010101-3',
u'mphhos-fnwp-010101-8',
u'mphhos-fnwp-010101-6',
u'mphhos-fnwp-010101-5',
u'mphhos-fnwp-010101-11']
etcd =[u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-4',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-9',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-1',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-10',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-3',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-6',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-7',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-8',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-11',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-2',
u'/xymon/fnwp/mphhos/mphhos-fnwp-010101-5']
etcd = [x.replace('/xymon/fnwp/mphhos/', '') for x in etcd]
# or using regex
# etcd = [re.sub('/xymon/fnwp/mphhos/', '', x) for x in etcd]
diff = set(etcd) - set(influx)
print(diff)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/58983156
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