blocks|key|3703813|text|for+(j=0;+j<=num;+j%2B%2B)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3703814|这是错误的。它应该是：|unstyled|3703815|for+(j+=+0;+j+<+num;+j%2B%2B)|3703816|为什么？假设num为5。在此行之前，您将even初始化为5。even的索引将为0、1、2、3、4。|offset|length|style|CODE|3703817|现在，使用j<=num，您正在尝试访问索引5，该索引不存在，因此出现了异常。|3703818|3703819|args[j]=+Integer.toString(num);|3703820|此行将引发另一个异常。我假设您只从命令行传递了一个参数，即args[0]。这意味着args数组的大小为1，您不能向其添加更多元素。|3703821|此外，向args数组添加/修改元素也不是一种好的做法。您应该为此创建一个新的数组。|3703822|entityMap^0|0|0|0|6|3|K|4|U|4|0|5|6|0|0|0|T|7|15|4|0|4|4|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|11|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|12|8|@$K|13|L|14|M|N]|$K|15|L|16|M|N]|$K|17|L|18|M|N]]|9|@]|A|$]]|$1|O|3|P|5|F|7|19|8|@$K|1A|L|1B|M|N]]|9|@]|A|$]]|$1|Q|3|-4|5|F|7|1C|8|@]|9|@]|A|$]]|$1|R|3|S|5|6|7|1D|8|@]|9|@]|A|$B|C]]|$1|T|3|U|5|F|7|1E|8|@$K|1F|L|1G|M|N]|$K|1H|L|1I|M|N]]|9|@]|A|$]]|$1|V|3|W|5|F|7|1J|8|@$K|1K|L|1L|M|N]]|9|@]|A|$]]|$1|X|3|-4|5|F|7|1M|8|@]|9|@]|A|$]]]|Y|$]]

<pre><code>for (j=0; j&lt;=num; j++)
</code></pre>

This is wrong. It should be:

<pre><code>for (j = 0; j &lt; num; j++)
</code></pre>

Why? Assume <code>num</code> is 5. Before this line you initialized <code>even</code> to 5. The indices of <code>even</code> would be 0, 1, 2, 3, 4. 

Now, with <code>j&lt;=num</code>, you are trying to access the index 5, which does not exist and hence the exception.

<hr>

<pre><code>args[j]= Integer.toString(num);
</code></pre>

This line will raise another exception. I am assuming you're only passing one parameter from the command line which is <code>args[0]</code>. This means the <code>args</code> array is of size 1 and you cannot add more elements to it.

Also, it is not a good practice to add/modify elements to the <code>args</code> array. You should create a new array for this.

blocks|key|562628|text|通过避免使用Integer.toString和String.join传递参数，请找到简单得多的代码版本。简单的整型Arraylist和添加元素将会起到作用。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|562629|package+com.umapathy.java.learning.programs;
import+java.util.ArrayList;
import+java.util.List;
public+class+EvenSum+
{
++++public+static+void+main(String[]+args)
{+++
++++int+num+=+20;+//Initialize+the+user-defined+value+for+the+loop+execution
++++int+sum+=+0+;+//Initialize+the+Sum+Value+as+0
++++List<Integer>+evenlist+=+new+ArrayList<Integer>();+//Define+an+integer+
++++Array+list
++++for+(int+i=2;+i<=num;+i%2B%2B)+//Begin+the+loop+from+the+value+of+2+
++++{
++++++if(i%252==0)+//Logic+to+find+whether+a+given+number+is+Even+Number+or+not
++++++{
++++++sum+=+sum+%2B+i;++//+If+the+logic+returns+true,+Calculate+the+Sum+Value+
++++++evenlist.add(i);+//+Add+the+Integer+to+the+previous+defined+Integer+
+++++++++++++++++++++++//+Arraylist+by+calling+add+method
+++++++}++++++++
++++}
++++System.out.println(evenlist);+//+Print+the+Output+outside+the+loops
++++System.out.println(sum);
+++++}
++}|code-block|syntax|javascript|562630|生成的输出如下：--|562631|[2,+4,+6,+8,+10,+12,+14,+16,+18,+20]+110|562632|entityMap^0|6|G|N|B|1L|9|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|P|$]]

Please find the much simpler version of the Code by avoiding the <code>Integer.toString</code> and <code>String.join</code> to pass on the Arguments. Simple Integer <code>Arraylist</code> and adding the elements to will do the Trick.
<pre><code>package com.umapathy.java.learning.programs;
import java.util.ArrayList;
import java.util.List;
public class EvenSum 
{
 public static void main(String[] args)
{ 
 int num = 20; //Initialize the user-defined value for the loop execution
 int sum = 0 ; //Initialize the Sum Value as 0
 List&lt;Integer&gt; evenlist = new ArrayList&lt;Integer&gt;(); //Define an integer 
 Array list
 for (int i=2; i&lt;=num; i++) //Begin the loop from the value of 2 
 {
 if(i%2==0) //Logic to find whether a given number is Even Number or not
 {
 sum = sum + i; // If the logic returns true, Calculate the Sum Value 
 evenlist.add(i); // Add the Integer to the previous defined Integer 
 // Arraylist by calling add method
 } 
 }
 System.out.println(evenlist); // Print the Output outside the loops
 System.out.println(sum);
 }
 }
</code></pre>
Output Generated as follows:--
<pre><code>[2, 4, 6, 8, 10, 12, 14, 16, 18, 20] 110
</code></pre>

blocks|key|562634|text|package+javaApp;

public+class+EvenSum+{

++++public+static+void+main(String[]+args)+{
++++++++int+num+=+20;
++++++++int+even[]+=+new+int[num];
++++++++int+sum+=+0,j+=+0;
++++++++String+evennums+=+"";
++++++++for(j=1;+j<=num;+j%2B%2B)+{
++++++++++++if(j%252==0)+{
++++++++++++++++sum=sum%2Bj;
++++++++++++++++evennums=evennums%2B","%2Bj;
++++++++++++}
++++++++}
++++++++evennums=evennums.replaceFirst(",","");
++++++++System.out.println(evennums);
++++++++System.out.println(sum);
++++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|562635|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>package javaApp;

public class EvenSum {

 public static void main(String[] args) {
 int num = 20;
 int even[] = new int[num];
 int sum = 0,j = 0;
 String evennums = &quot;&quot;;
 for(j=1; j&lt;=num; j++) {
 if(j%2==0) {
 sum=sum+j;
 evennums=evennums+&quot;,&quot;+j;
 }
 }
 evennums=evennums.replaceFirst(&quot;,&quot;,&quot;&quot;);
 System.out.println(evennums);
 System.out.println(sum);
 }
}
</code></pre>

blocks|key|3703879|text|如果偶数组的实际长度在初始时未知，为什么要初始化偶数组大小。在这种情况下，最好使用ArrayList，因为它具有动态增长的特性。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3703880|以这种方式尝试|offset|length|style|BOLD|3703881|++++public+static+void+main(String[]+args)+{
++++++++++++int+num+=++Integer.parseInt(args[0]);
++++++++++++List<Integer>+evens+=+new+ArrayList<Integer>();
++++++++++++int+sum+=+0;++++++++++++++++
++++++++++++for+(int+j+=+0;+j+<=+num;+j%2B%2B)+{
++++++++++++++++if+(j+%25+2+==+0)+{
++++++++++++++++++++sum+%2B=+j;
++++++++++++++++++++evens.add(j);
++++++++++++++++}
++++++++++++}+++++++
++++++++++++System.out.println("Even+Numbers+List+:+"%2Bevens);
++++++++++++System.out.println("Total+Sum+:+"%2Bsum);
++++++

+++++//+If+you+want+an+array+of+int+instead+of+ArrayList+you+can+convert+ArrayList+into+int[]+with+following+two+lines

+++++++++++int+evenArray[]+=+even.stream().mapToInt(x->x).toArray();++++++++++++++++
+++++++++++System.out.println("Even+Numbers+Array+:+"%2BevenArray);

++++++++}|code-block|syntax|javascript|3703882|entityMap^0|0|0|7|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|S|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Why initialized the even array size if its actual length is unknown in initially. It's better to go with ArrayList in this case which have characteristic to grow dynamically.
Try in this way
<pre><code> public static void main(String[] args) {
 int num = Integer.parseInt(args[0]);
 List&lt;Integer&gt; evens = new ArrayList&lt;Integer&gt;();
 int sum = 0; 
 for (int j = 0; j &lt;= num; j++) {
 if (j % 2 == 0) {
 sum += j;
 evens.add(j);
 }
 } 
 System.out.println(&quot;Even Numbers List : &quot;+evens);
 System.out.println(&quot;Total Sum : &quot;+sum);
 

 // If you want an array of int instead of ArrayList you can convert ArrayList into int[] with following two lines

 int evenArray[] = even.stream().mapToInt(x-&gt;x).toArray(); 
 System.out.println(&quot;Even Numbers Array : &quot;+evenArray);

 }
</code></pre>

blocks|key|3703924|text|public+static+void+main(String[]+args)+{
++++++++//+TODO+Auto-generated+method+stub
++++++++//System.out.println("Args:+"%2Bargs[0]);
++++++++int+num+=+Integer.parseInt(args[0]);
++++++++int+even[]+=+new+int[num];
++++++++int+sum+=+0,j+=+0;
++++++++String+evennums+=+"";
++++++++//Insert+your+code+here
++++++++for(j=0;+j<=num;+j%2B%2B)+{
++++++++++++if(j%252==0)+{
++++++++++++++++//even[j]=num;
++++++++++++++++sum=sum%2Bj;
++++++++++++++++if(j!=0)+evennums=evennums%2B","%2Bj;

++++++++++++}

++++++++}++++
++++++++evennums=evennums.substring(1);
++++++++System.out.println(evennums);
++++++++System.out.println(sum);
++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3703925|在eclipse中运行时，请执行以下步骤：|unstyled|3703926|右键单击class-->+Run+AS+-->+Run+Configuration转到Arguments选项卡并将值作为10传递单击Run+Output:+2,4,6,8,10+30|3703927|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>public static void main(String[] args) {
 // TODO Auto-generated method stub
 //System.out.println(&quot;Args: &quot;+args[0]);
 int num = Integer.parseInt(args[0]);
 int even[] = new int[num];
 int sum = 0,j = 0;
 String evennums = &quot;&quot;;
 //Insert your code here
 for(j=0; j&lt;=num; j++) {
 if(j%2==0) {
 //even[j]=num;
 sum=sum+j;
 if(j!=0) evennums=evennums+&quot;,&quot;+j;

 }

 } 
 evennums=evennums.substring(1);
 System.out.println(evennums);
 System.out.println(sum);
 }
</code></pre>
At time of running in eclipse follow below steps:
Right click on class--&gt; Run AS --&gt; Run Configuration
Go to Arguments tab and pass value as 10
Click Run
Output:
2,4,6,8,10
30

While running this code I am getting <code>ArrayIndexOutOfBoundsException</code>. 

<pre><code>public class Evensum {

 public static void main(String[] args) {
 int num = Integer.parseInt(args[0]);
 int even[] = new int[num];
 int sum = 0,j = 0;
 String evennums = "";
 //Insert your code here
 for(j=0; j&lt;=num; j++) {
 if(num%2==0) {
 even[j]=num;
 sum=sum+num;
 args[j]= Integer.toString(num);
 }
 evennums=String.join(",", args);
 } 
 System.out.println(evennums);
 System.out.println(sum);
 }
}
</code></pre>

Java code to generate comma separated values and sum

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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运行这段代码时，我得到了ArrayIndexOutOfBoundsException。public class Evensum {    public static void main(String[] args) {        int num = Integer.parseInt(args[0]);       ...

问用于生成逗号分隔值和总和的Java代码
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