在计算中,Table1的每一行都应该在Table1和Table2中找到包含多个列的最大值。Table1由下列组成: ID、代码、Value1、Value2、Max_value Table2由ID、代码、Perc1、Perc2组成
**Table1**
ID=1 (value1=1000, Value2=5000, Code=21);   Max_Value=? 
ID=2 (value1=2000, Value2=4000, Code=21);   Max_Value=?
ID=3 (value1=1000, Value2=5000, Code=21);   Max_Value=?
**Table2**
ID=25 (Perc1=5.2%, Perc2=3.5%, Code=21);    
ID=26 (Perc1=3.1%, Perc2=8.6%, Code=21);   
ID=27 (Perc1=2.5%, Perc2=3.4%, Code=21)
** Calculation**
formula:
    =[(1 ∗ 1)+(2 ∗ 2)]
              WHERE Table1.Code = Table2.Code
Max_Value (Table1.Id=1, Table2.Id=25) = 227
Max_Value (Table1.Id=1, Table2.Id=26) = 461 (max for ID 1)
Max_Value (Table1.Id=1, Table2.Id=27) = 195
Max_Value (Table1.Id=2, Table2.Id=25) = 224
Max_Value (Table1.Id=2, Table2.Id=26) = 406 (max for ID 2)
Max_Value (Table1.Id=2, Table2.Id=27) = 186
Max_Value (Table1.Id=3, Table2.Id=25) = 401
Max_Value (Table1.Id=3, Table2.Id=26) = 695 (max for ID 3)
Max_Value (Table1.Id=3, Table2.Id=27) = 313发布于 2020-03-06 19:52:49
如果我没记错的话,你想要join和row_number()
select t12.*
from (select t1.*, t2.*,
             (t2.perc1 * t1.value1 + t2.perc2 * t1.value2) as calc,
             row_number() over (partition by t1.id order by (t2.perc1 * t1.value1 + t2.perc2 * t1.value2) desc) as seqnum
      from table1 t1 join
           table2 t2
           on t1.code = t2.code
     ) t12
where seqnum = 1;您的公式和解释暗示了table1中的code列,尽管我在示例数据中看不到它。
https://stackoverflow.com/questions/60561075
复制相似问题