blocks|key|1139978|text|基本上，您可以将saveAlias指向temp；因此，您将拥有：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1139979|saveAlias+=+temp;|offset|length|style|CODE|1139980|正如Chris所指出的。这将使一个指针指向另一个指针。更正我的答案。我建议你用malloc定义saveAlias的大小，然后使用memcpy函数。您将拥有：|1139981|#include+<stdio.h>
#include+<string.h>
#include+<stdlib.h>
++
int+main(){++++
+++char+*temp+=+"your_char";

+++//with+malloc+you+make+sure+saveAlias+will+have+the+same+size+as+temp
+++//and+then+we+add+one+for+the+NULL+terminator
+++char+*saveAlias+=+(char*)+malloc(strlen(temp)+%2B+1);
++++++++++++
+++//then+just++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
+++strcpy(saveAlias,+temp);
+
+++printf("%25s\n",+temp);
+++printf("%25s",+saveAlias);
+++return+0;++++++++++++
}|code-block|syntax|javascript|1139982|也感谢chqrlie的解释。我搞错了memcpy。|1139983|entityMap^0|0|0|H|0|0|0|3|7|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@$D|U|E|V|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|W|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|X|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|Y|8|@$D|Z|E|10|F|G]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|R|$]]

You can basically point the saveAlias to temp; Thus you would have:
<code>saveAlias = temp;</code>
As noted by Chris. This will make one pointer point to another.
Correcting my answer. I suggest you define de size of saveAlias with malloc, and then use the memcpy function. You will have:
<pre><code>#include &lt;stdio.h&gt;
#include &lt;string.h&gt;
#include &lt;stdlib.h&gt;
 
int main(){ 
 char *temp = &quot;your_char&quot;;

 //with malloc you make sure saveAlias will have the same size as temp
 //and then we add one for the NULL terminator
 char *saveAlias = (char*) malloc(strlen(temp) + 1);
 
 //then just 
 strcpy(saveAlias, temp);
 
 printf(&quot;%s\n&quot;, temp);
 printf(&quot;%s&quot;, saveAlias);
 return 0; 
}
</code></pre>
Thank you <code>chqrlie</code> for the explanation also. I was mistaken about the memcpy.

blocks|key|1140008|text|假设您的temp变量指向一个适合nul-terminated的字符串(正如C中的字符串应该是这样)，那么您可以只使用strdup()+function来复制它，并在saveAlias中存储一个指向它的指针。这个函数将dup给定字符串复制到新分配的内存中；当不再需要时，应该使用free函数释放该内存：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|BOLD|entityRanges|data|1140009|#include+<stdio.h>
#include+<string.h>
#include+<stdlib.h>

int+main()
{
++++char*+temp+=+"source+string";
++++char*+saveAlias+=+strdup(temp);
++++printf("Temp+is+<%25s>+(at+%25p).\n",+temp,+(void*)temp);
++++printf("Alias+is+<%25s>+(at+%25p).\n",+saveAlias,+(void*)saveAlias);
++++free(saveAlias);
++++return+0;
}|code-block|syntax|javascript|1140010|strdup函数将malloc和strcpy有效地组合到一个函数调用中，上面显示的调用等同于：|1140011|++++char*+saveAlias+=+malloc(strlen(temp)+%2B+1);
++++strcpy(saveAlias,+temp);|1140012|entityMap|0|LINK|mutability|MUTABLE|url|https://en.cppreference.com/w/c/experimental/dynamic/strdup^0|4|4|G|3|1M|8|2A|9|3U|4|33|13|1M|H|0|0|0|0|1B|0|6|9|6|G|6|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|C]|$9|14|A|15|B|C]|$9|16|A|17|B|C]|$9|18|A|19|B|D]]|E|@$9|1A|A|1B|1|1C]]|F|$]]|$1|G|3|H|5|I|7|1D|8|@]|E|@]|F|$J|K]]|$1|L|3|M|5|6|7|1E|8|@$9|1F|A|1G|B|D]|$9|1H|A|1I|B|C]|$9|1J|A|1K|B|C]|$9|1L|A|1M|B|C]]|E|@]|F|$]]|$1|N|3|O|5|I|7|1N|8|@]|E|@]|F|$J|K]]|$1|P|3|-4|5|6|7|1O|8|@]|E|@]|F|$]]]|Q|$R|$5|S|T|U|F|$V|W]]]]

Assuming that your <code>temp</code> variable points to a character string that is suitably <code>nul</code>-terminated (as strings in C should be), then you can just use the <a href="https://en.cppreference.com/w/c/experimental/dynamic/strdup" rel="nofollow noreferrer"><code>strdup()</code> function</a> to make a copy of it and store a pointer to that in <code>saveAlias</code>. This function will duplicate the given string into newly-allocated memory; that memory should be released, using the <code>free</code> function, when no longer needed:
<pre class="lang-c prettyprint-override"><code>#include &lt;stdio.h&gt;
#include &lt;string.h&gt;
#include &lt;stdlib.h&gt;

int main()
{
 char* temp = &quot;source string&quot;;
 char* saveAlias = strdup(temp);
 printf(&quot;Temp is &lt;%s&gt; (at %p).\n&quot;, temp, (void*)temp);
 printf(&quot;Alias is &lt;%s&gt; (at %p).\n&quot;, saveAlias, (void*)saveAlias);
 free(saveAlias);
 return 0;
}
</code></pre>
The <code>strdup</code> function effectively combines <code>malloc</code> and <code>strcpy</code> into a single function call, with the call shown above being the equivalent of:
<pre class="lang-c prettyprint-override"><code> char* saveAlias = malloc(strlen(temp) + 1);
 strcpy(saveAlias, temp);
</code></pre>

blocks|key|4408863|text|如果要为temp当前指向的字符串的副本分配内存，请使用strdup()|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4408864|#include+<stdio.h>
#include+<string.h>

int+main()+{
++++char+buf[128];
++++char+*temp;
++++char+*saveAlias+=+NULL;

++++if+((temp+=+fgets(buf,+sizeof+buf,+stdin))+!=+NULL)+{
++++++++saveAlias+=+strdup(temp);
++++++++if+(saveAlias+==+NULL)+{
++++++++++++fprintf(stderr,+"allocation+failed\n");
++++++++}+else+{
++++++++++++printf("saveAlias:+%25s\n",+saveAlias);
++++++++}
++++}
++++free(saveAlias);
++++return+0;
}|code-block|syntax|javascript|4408865|entityMap^0|4|4|R|8|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

If you want to allocate memory for a copy of the string currently pointed to by <code>temp</code>, use <code>strdup()</code>:
<pre><code>#include &lt;stdio.h&gt;
#include &lt;string.h&gt;

int main() {
 char buf[128];
 char *temp;
 char *saveAlias = NULL;

 if ((temp = fgets(buf, sizeof buf, stdin)) != NULL) {
 saveAlias = strdup(temp);
 if (saveAlias == NULL) {
 fprintf(stderr, &quot;allocation failed\n&quot;);
 } else {
 printf(&quot;saveAlias: %s\n&quot;, saveAlias);
 }
 }
 free(saveAlias);
 return 0;
}
</code></pre>

I have two char pointers:
<pre><code>char *temp;
char *saveAlias;
</code></pre>
I want to assign <code>saveAlias</code> with whatever is stored in <code>temp</code>; <code>saveAlias</code> is currently empty while <code>temp</code> has a string of an unknown size saved from user input.
Note that I don't want <code>saveAlias</code> to point to where <code>temp</code> points; I want the content of <code>temp</code> and assign (get pointed) it to <code>saveAlias</code>.
I have attempted using <code>strcat</code> and <code>strcpy</code> but to no avail.

Assign a char pointer the value of another char pointer

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

我有两个字符指针：char *temp;char *saveAlias;我希望将存储在temp中的内容赋给saveAlias；saveAlias当前为空，而temp有一个从用户输入中保存的未知大小的字符串。请注意，我不希望saveAlias指向temp所指向的位置；我希望将temp的内容分配(指向)给saveAlias...

问将一个字符指针赋值为另一个字符指针的值
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问将一个字符指针赋值为另一个字符指针的值EN