有没有办法做到!radios.checked &&!radios1.检查&&!radios2.在循环中检查并在某些时候保持if条件不变?我的代码是:
    function afterLogin(event){
        event.preventDefault(); 
        if((!radios[0].checked && !radios[1].checked && !radios[2].checked) || userName.value === "" || numOfQuestions.value === ""){
            skillMsg.innerHTML = "Please check one of the skills before login";
            isTrue = false;
        }else{
            title[0].innerHTML = "Welcome " + userName.value;
            loginForm.style.display = "none";
            calForm.style.display = "block";
            formsColor.style.backgroundColor  = color.value;
            startTheGame();
            isTrue = true;
        }
        
    }
这就是我想做的:
    function afterLogin(event){
        event.preventDefault(); 
        for(let i = 0; i < radios.length; i++){
            if(!radios[i].checked || userName.value === "" || numOfQuestions.value === ""){
                //change the plase here
                skillMsg.innerHTML = "Please check one of the skills before login";
                return false;
            }else{
                title[0].innerHTML = "Welcome " + userName.value;
                loginForm.style.display = "none";
                calForm.style.display = "block";
                formsColor.style.backgroundColor  = color.value;
                //return true;
                startTheGame();
                //return true;
                
            }
        
        }
    }
发布于 2020-11-17 14:14:31
试试这个?您可以使用可用的Array.every方法。参考:https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/every
function afterLogin(event){
    event.preventDefault(); 
    if((!radios.every(radio => radio.checked) || userName.value === "" || numOfQuestions.value === ""){
        skillMsg.innerHTML = "Please check one of the skills before login";
        isTrue = false;
    }else{
        title[0].innerHTML = "Welcome " + userName.value;
        loginForm.style.display = "none";
        calForm.style.display = "block";
        formsColor.style.backgroundColor  = color.value;
        startTheGame();
        isTrue = true;
    }
    
}发布于 2020-11-17 14:15:56
是的,这是可能的,创建一个不同的验证函数来执行健全性检查,或者在相同的函数中执行
    function afterLogin(event){
        event.preventDefault(); 
        let notChecked = false;
        for(let i = 0; i < radios.length; i++){
            if(!radios[i].checked){
                notChecked = true;
                break;
            }
        }
        if(notChecked || userName.value === "" || numOfQuestions.value === ""){
            skillMsg.innerHTML = "Please check one of the skills before login";
            isTrue = false;
        }else{
            title[0].innerHTML = "Welcome " + userName.value;
            loginForm.style.display = "none";
            calForm.style.display = "block";
            formsColor.style.backgroundColor  = color.value;
            startTheGame();
            isTrue = true;
        }  
    }发布于 2020-11-17 14:16:35
是的,您可以使用every()函数来检查这一点。
var radios = [{checked: false}, {checked: false}, {checked: false}, {checked: false}];
if(radios.every(checkValue) || userName.value === "" || numOfQuestions.value === "") {
// your code
}
function checkValue({checked}) {
  return checked === false;
}也要尝试使用干净的代码原则。就像尝试使用Fail first方法一样,使用if和return,这样您就不必在那里使用else块。只需将else部分放在if块之外。
https://stackoverflow.com/questions/64870124
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