blocks|key|2221640|text|在setUsers.|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2221641|The+function中传递函数时，您需要传递的函数将为您提供正在尝试更新的变量的previous+state。|unordered-list-item|2221642|
|2221643|使用该previous+state创建新状态(数组)并从函数中返回它。|2221644|2221645|返回值将在该状态中更新。|2221646|2221647|const+[users,+setUsers]+=+useState([]);

setUsers((prevStateOfUsers)+=>+{

+const+newStateOfUsers+=+[...prevStateOfUsers,+{+name:+'Alexandre'}+];

+return+newStateOfUsers;+

});

console.log(users);|code-block|syntax|javascript|2221648|Link+to+official+react+js+docs|2221649|One+liner解决方案适用于单眼线爱好者|2221650|setUsers((prevStateOfUsers)+=>+[...prevStateOfUsers,+{+name:+'Alexandre'}+]);|2221651|entityMap|0|LINK|mutability|MUTABLE|url|https://reactjs.org/docs/hooks-reference.html#functional-updates^0|1|8|0|16|E|0|0|3|E|0|0|0|0|0|0|U|0|0|0|0^^$0|@$1|2|3|4|5|6|7|19|8|@$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1C|8|@$9|1D|A|1E|B|C]]|D|@]|E|$]]|$1|I|3|J|5|6|7|1F|8|@]|D|@]|E|$]]|$1|K|3|L|5|H|7|1G|8|@$9|1H|A|1I|B|C]]|D|@]|E|$]]|$1|M|3|J|5|6|7|1J|8|@]|D|@]|E|$]]|$1|N|3|O|5|H|7|1K|8|@]|D|@]|E|$]]|$1|P|3|-4|5|6|7|1L|8|@]|D|@]|E|$]]|$1|Q|3|R|5|S|7|1M|8|@]|D|@]|E|$T|U]]|$1|V|3|W|5|6|7|1N|8|@]|D|@$9|1O|A|1P|1|1Q]]|E|$]]|$1|X|3|Y|5|6|7|1R|8|@]|D|@]|E|$]]|$1|Z|3|10|5|S|7|1S|8|@]|D|@]|E|$T|U]]|$1|11|3|-4|5|6|7|1T|8|@]|D|@]|E|$]]]|12|$13|$5|14|15|16|E|$17|18]]]]

<ol>
<li>You need to pass a function inside <code>setUsers</code>.</li>
<li>The function will provide you a <code>previous state</code> of the variable that you are trying to update.</li>
<li>Use that <code>previous state</code> to create a new state (array) and return it from the function.</li>
<li>The returned value will be updated in the state.</li>
</ol>
<pre><code>const [users, setUsers] = useState([]);

setUsers((prevStateOfUsers) =&gt; {

 const newStateOfUsers = [...prevStateOfUsers, { name: 'Alexandre'} ];

 return newStateOfUsers; 

});

console.log(users);
</code></pre>
<a href="https://reactjs.org/docs/hooks-reference.html#functional-updates" rel="nofollow noreferrer">Link to official react js docs</a>
One liner solution for oneliner-lovers
<pre><code>setUsers((prevStateOfUsers) =&gt; [...prevStateOfUsers, { name: 'Alexandre'} ]);
</code></pre>

blocks|key|3635331|text|请尝试以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3635332|import+React,+{+useState,+useEffect+}+from+'react';

function+Example()+{
++const+[users,+setUsers]+=+useState([]);

++useEffect(()+=>+{
++++setUsers([...users,+{+name:+'Alexandre'}+]);
++++console.log(users);
++},+[]);

++return+(
++++<div>
++++++something...
++++</div>
++);
}|code-block|syntax|javascript|3635333|关键字为useEffect。|3635334|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Please try this:
<pre><code>import React, { useState, useEffect } from 'react';

function Example() {
 const [users, setUsers] = useState([]);

 useEffect(() =&gt; {
 setUsers([...users, { name: 'Alexandre'} ]);
 console.log(users);
 }, []);

 return (
 &lt;div&gt;
 something...
 &lt;/div&gt;
 );
}
</code></pre>
Keyword is useEffect.

blocks|key|2221666|text|你能把页面的代码放进去吗？或者，您可以编写以下代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2221667|在函数中|2221668|import+React,+{+useState+}+from+'react';+

const+Component+=+({+setUsers+})+=>+{

++const+[users,+setUsers]+=+useState([]);

++const+addMember+=+(value)+=>+{
++++setUsers([...users,+{++++++
++++++name:+value,
++++}]);
++};

++return+(
++++your+code...
++);
};|code-block|syntax|javascript|2221669|或者正如useEffect中的Artem+Medianyk所指出的那样|2221670|import+React,+{+useState,+useEffect+}+from+'react';

+const+Component+=+()+=>+{

++const+[users,+setUsers]+=+useState([]);

++useEffect(()+=>+{
++++setUsers([...users,+{
+++++++name:+'Alexandre',
++++}]);
++},+[]);

++return+(
+++your+code...
++);
};|2221671|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

can you put the code of page ? or you can write this code :
In function
<pre><code>import React, { useState } from 'react'; 

const Component = ({ setUsers }) =&gt; {

 const [users, setUsers] = useState([]);

 const addMember = (value) =&gt; {
 setUsers([...users, { 
 name: value,
 }]);
 };

 return (
 your code...
 );
};
</code></pre>
Or as indicated by Artem Medianyk in useEffect
<pre><code>import React, { useState, useEffect } from 'react';

 const Component = () =&gt; {

 const [users, setUsers] = useState([]);

 useEffect(() =&gt; {
 setUsers([...users, {
 name: 'Alexandre',
 }]);
 }, []);

 return (
 your code...
 );
};
</code></pre>

<pre><code>const [users, setUsers] = useState([]);

setUsers([...users, { name: 'Alexandre'} ]);

console.log(users);
</code></pre>
that's the only thing i'm trying to do. Please, help me

I am trying to update an array declared with useState, but I am getting the error 'Too many re-renders'

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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const [users, setUsers] = useState([]);setUsers([...users, { name: 'Alexandre'} ]);console.log(users);这是我唯一想做的事。请帮帮我

问我正在尝试更新一个用useState声明的数组，但是我得到了一个错误'Too many‘
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问我正在尝试更新一个用useState声明的数组，但是我得到了一个错误'Too many‘EN