如何在完成表格后显示“已成功发送讯息”？
如何在完成表格后显示“已成功发送讯息”？
提问于 2021-03-10 00:40:27
我正在尝试在有人填写表单后显示“消息发送成功”。
以下是我的代码
<form action="contact.php" id="footer-form" method="post" role="form">
<div class="form-group has-feedback"><label class="sr-only" for="name2">Name</label> <input class="form-control" id="name2" name="name2" placeholder="Name" required="" type="text" /></div>
<div class="form-group has-feedback"><label class="sr-only" for="email2">Email address</label> <input class="form-control" id="email2" name="email2" placeholder="Enter email" required="" type="email" /></div>
<input class="btn btn-default" type="submit" value="Send" /></form>
<?php
$name = $_POST['name2'];
$email = $_POST['email2'];
$formcontent="From: $name \nEmail: $email";
$recipient = "email@domain.com";
$subject = "Website Under Construction";
$mailheader = "From: $email \r\n";
mail($recipient, $subject, $formcontent, $mailheader) or die("Error!");
?>回答 2
Stack Overflow用户
发布于 2021-03-10 01:06:10
只需将PHP代码置于HTML代码之上并定义一条消息即可。
然后，在您的HTML代码中回显它：
<?php
if(isset($_POST) {
$name = $_POST['name2'];
$email = $_POST['email2'];
$formcontent="From: $name \nEmail: $email";
$recipient = "email@domain.com";
$subject = "Website Under Construction";
$mailheader = "From: $email \r\n";
mail($recipient, $subject, $formcontent, $mailheader) or die("Error!");
// Set the message here:
$message = "Message sent!";
}
?>
<form action="contact.php" id="footer-form" method="post" role="form">
<div class="form-group has-feedback"><label class="sr-only" for="name2">Name</label> <input class="form-control" id="name2" name="name2" placeholder="Name" required="" type="text" /></div>
<div class="form-group has-feedback"><label class="sr-only" for="email2">Email address</label> <input class="form-control" id="email2" name="email2" placeholder="Enter email" required="" type="email" /></div>
<input class="btn btn-default" type="submit" value="Send" /></form>
<?php
// Put this wherever you want
if(isset($message)) echo $message;
?>解释
默认情况下，变量$message是未设置的。表单提交完成后，将字符串"Message sent!“赋给变量$message。
现在，在代码中的任何位置，都可以检查是否定义了变量$message并将其打印出来。
Stack Overflow用户
发布于 2021-03-10 01:09:49
index.php文件
<form action="contact.php" id="footer-form" method="post" role="form">
<div class="form-group has-feedback"><label class="sr-only"for="name2">Name</label>
<input class="form-control" id="name2" name="name2" placeholder="Name" required="" type="text" /></div>
<div class="form-group has-feedback"><label class="sr-only" for="email2">Email address</label> <input class="form-control" id="email2" name="email2" placeholder="Enter email" required="" type="email" /></div>
<input class="btn btn-default" type="submit" name="send_mail" value="Send" />
</form>contact.php文件
if (isset($_POST['send_mail'])) {
$name = $_POST['name2'];
$email = $_POST['email2'];
$formcontent="From: $name \nEmail: $email";
$recipient = "email@domain.com";
$subject = "Website Under Construction";
$mailheader = "From: $email \r\n";
$send_email = mail($recipient, $subject, $formcontent, $mailheader);
if ($send_email) {
echo 'Your success message';
} else {
die("Error!");
}
}说明
首先看一下index.php文件，这里的<form action="contact.php" id="footer-form" method="post" role="form">在表单标签上使用了action attribute，并使用了类似contact.php的action路径
还要检查<input class="btn btn-default" type="submit" name="send_mail" value="Send" />，这里我使用了name attribute name="send_mail"
当用户点击该按钮时，该页面将重定向到contact.php页面，并且该页面将检查用户是否点击该按钮并处理mail函数。经过处理后，最后显示消息。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/66551098
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