问如何在字符串数组中找到第二个最大值，其中特定元素的大小可以是1024？

EN

public static String secondMax(String[] ar) {
    if (ar == null || ar.length == 0 || ar.length == 1)
        return "-1";
    try {
        String largest = ar[0];
        String secLargest = null;
        for (int i = 1; i < ar.length; i++) {
            String item = ar[i];
            if(compareTo(item, largest) == 0)
                continue;
            if (compareTo(item, largest)  > 0) {
                secLargest = largest;
                largest = item;
            } else if (secLargest == null || compareTo(item, secLargest)  > 0) {
                secLargest = item;
            }
        }
        return Objects.requireNonNullElse(secLargest, "-1");
    } catch (Exception e) {
        throw new InternalError(e);
    }

}
static int compareTo(String ist, String sec)
{
    if(ist.contains("-") && !sec.contains("-"))
        return -1;
    if(!ist.contains("-") && sec.contains("-"))
        return 1;
    if(ist.contains("-") && sec.contains("-"))
    {
        String temp = ist;
        ist = sec;
        sec = temp;
    }
    if (ist.length() > sec.length())
    {
        return 1;
    }
    else if(ist.length() < sec.length())
    {
        return -1;
    }else {
        return ist.compareTo(sec);
    }
}