blocks|key|4033998|text|当您将字符与空格连接在一起时，可以对字符串变量进行替换，以删除不需要的空格|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4033999|concatenatedString+=+concatenatedString.replaceAll("+,",+",")
+++++++.replaceAll("+\\.",+".");|code-block|syntax|javascript|4034000|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

As you are concatenating the chars with an space, you can make a replacement on the string variable to remove the spaces you dont want
<pre><code>concatenatedString = concatenatedString.replaceAll(&quot; ,&quot;, &quot;,&quot;)
 .replaceAll(&quot; \\.&quot;, &quot;.&quot;);
</code></pre>

blocks|key|4034092|text|通过对它进行编程。为什么quick和brown可以用空格分隔，而fox和,不能？Java显然不知道。你得说出来。您可以使用str.charAt(0)获取第一个字符，最后一个使用str.charAt(str.length()+-1)，您可以使用Character.isLetterOrDigit检查它是否是需要空格的字符类型(例如，不是冒号、空格、逗号、感叹号或其他类似字符)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4034093|在for+(String+word+:+words)循环中使用这些工具。确定要添加的字符串的开头是否为“非字母/数字”，如果是，则不要添加该空格。否则，请添加它。|4034094|entityMap^0|C|5|I|5|W|3|10|1|1P|D|2G|R|3D|P|0|1|P|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]|$9|Q|A|R|B|C]|$9|S|A|T|B|C]|$9|U|A|V|B|C]|$9|W|A|X|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|I|$]]

By programming it. Why is <code>quick</code> and <code>brown</code> eligible for separation with a space, but <code>fox</code> and <code>,</code> isn't? Java obviously doesn't know. You'd have to tell it. You can use <code>str.charAt(0)</code> to get the first character, <code>str.charAt(str.length() -1)</code> for the last, you can use <code>Character.isLetterOrDigit</code> to check if it's the kind of character where you'd want a space (e.g. NOT a colon or a space or a comma or an exclamation mark or any other such).
Use these tools inside your <code>for (String word : words)</code> loop. Determine if the start of the string you're about to add is a 'non letter/digit' and if so, do not add that space. Otherwise add it.

blocks|key|4837165|text|我会颠倒你的逻辑，这样如果要添加的单词在它之前需要一个空格，你就可以在前面加上一个空格。您将不得不处理不需要的初始单词(您可以检查concatenatedString是否为空，或者简单地将concatenatedString作为第一个单词并跳到第二个单词)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4837166|现在，您有两个问题：|4837167|4837168|您必须检查的单词是下一个单词，而不是当前单词，|ordered-list-item|4837169|您将在字符串上得到一个尾随空格，即使它没有出现在打印中，它也在那里。|4837170|4837171|如果在添加新单词时切换到前缀空格，则会使检查变得更容易。然后，如果是需要空格的单词，则只在单词前添加空格。|4837172|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|R|8|@]|9|@]|A|$]]|$1|H|3|I|5|G|7|S|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

I would flip your logic so that you prepend a space if the word being added needs one before it. You will have to handle the initial word not needing one (you could either check if concatenatedString is empty, or simply start out concatenatedString as the first word and skip to the second).
As it is now, you have two problems:
<ol>
<li>The word you have to check is the next word, not the current word, and</li>
<li>you're ending up with a trailing space on the string, which is there even if it doesn't show up in the print.</li>
</ol>
If you switch to prepending spaces on adding a new word, it makes it much easier to check. Then only add a space before the word if it's a word that needs a space.

<pre><code>public class Main {
 public static void main(String[] args) {
 String[] words = {&quot;The&quot;, &quot;quick&quot;, &quot;brown&quot;, &quot;fox&quot;, &quot;,&quot;, &quot;jumps&quot;, &quot;over&quot;, &quot;the&quot;, &quot;lazy&quot;, &quot;dog&quot;, &quot;.&quot;};
 String concatenatedString = &quot;&quot;;

 for (String word : words) {
 concatenatedString += word + &quot; &quot;;
 }
 
 System.out.println(concatenatedString);
}
</code></pre>
}
I am trying to concatenate all the words from a string array in a single string, and the output I get is like this : &quot;The quick brown fox , jumps over the lazy dog .&quot;
I would want the spaces before punctuation marks to be removed so the output could look like this : &quot;The quick brown fox, jumps over the lazy dog.&quot;
Any idea how could I do that?

Remove spaces before a punctuation mark in a string

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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public class Main {    public static void main(String[] args) {        String[] words = {"The", "quick", "brown", "fox", ",", "jumps", "over", "the", "lazy", "d...

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