blocks|key|5834986|text|你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5834987|arr2.map((x)+=>+{
++let+result+=+arr1.filter((a1)+=>+a1.id+===+x.id);
++if+(result.length+>+0)+{
++++x.total+=+result[0].total;
++}
++return+x;
});|code-block|syntax|javascript|5834988|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You could do something like this:
<pre><code>arr2.map((x) =&gt; {
 let result = arr1.filter((a1) =&gt; a1.id === x.id);
 if (result.length &gt; 0) {
 x.total = result[0].total;
 }
 return x;
});
</code></pre>

blocks|key|5835052|text|我已经将find函数更改为filter函数，并将结果添加到原始数组中。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5835053|尝尝这个|5835054|​|5835055|const+arr1+=+[
{
++id:+1,
++value:+{+total:+0+},
},
{
++id:+2,
++value:+{+total:+0+},
},
{
++id:+3,
++value:+{+total:+0+},
},
{
++id:+4,
++value:+{+total:+0+},
}
]
const+arr2+=+[
++++{
++++++id:+2,
++++++value:+3+,
++++},
++++{
++++++id:+3,
++++++value:+5,
++++},
++];
++
arr1.map((item)+=>+{
++let+result+=+arr2.filter((element)+=>+element.id+==+item.id)
++if(result+&&+result.length)+{
++++item.value.total+%2B=+result[0].value
++}
++return+item;
});++


console.log(arr1)|code-block|syntax|javascript|5835056|5835057|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|P|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|Q|8|@]|9|@]|A|$I|J]]|$1|K|3|E|5|6|7|R|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|M|$]]

I have changed the find function to the filter function and will add the result to the original array.
try this
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const arr1 = [
{
 id: 1,
 value: { total: 0 },
},
{
 id: 2,
 value: { total: 0 },
},
{
 id: 3,
 value: { total: 0 },
},
{
 id: 4,
 value: { total: 0 },
}
]
const arr2 = [
 {
 id: 2,
 value: 3 ,
 },
 {
 id: 3,
 value: 5,
 },
 ];
 
arr1.map((item) =&gt; {
 let result = arr2.filter((element) =&gt; element.id == item.id)
 if(result &amp;&amp; result.length) {
 item.value.total += result[0].value
 }
 return item;
}); 


console.log(arr1)</code></pre>
</div>
</div>

blocks|key|2050301|text|你必须将map赋值给你的数组：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2050302|++this.arr1+=+this.arr1.map((item)+=>+{
++++++this.arr2.find((element)+=>+{
++++++++if+(element.id+===+item.id)+{
++++++++++item+=+{

++++++++++++...item,
++++++++++++value:+{
++++++++++++++...item.value,
++++++++++++++total:+item.value.total+%2B+element.value,
++++++++++++},
++++++++++};
++++++++++console.log(item);
++++++++}
++++++});
++++++return+item;
++++});|code-block|syntax|javascript|2050303|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You have to assign map to your array:
<pre><code> this.arr1 = this.arr1.map((item) =&gt; {
 this.arr2.find((element) =&gt; {
 if (element.id === item.id) {
 item = {

 ...item,
 value: {
 ...item.value,
 total: item.value.total + element.value,
 },
 };
 console.log(item);
 }
 });
 return item;
 });
</code></pre>

blocks|key|2050384|text|如果每个对象的id是唯一的(在每个数组中)，您可以执行以下操作：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2050385|arr1.forEach((obj1)+=>+{
++const+obj2Match+=+arr2.find((obj2)+=>+obj1.id+===+obj2.id+);

++if+(obj2Match)+{
++++obj1.value.total+%2B=+obj2Match.value;
++}
});|code-block|syntax|javascript|2050386|如果多个对象可以具有相同的id+(例如，arr2有两个id为2的对象)，则可以执行以下操作：|2050387|arr1.forEach((obj1)+=>+{
++const+obj2Matches+=+arr2.filter((obj2)+=>+obj1.id+===+obj2.id+);

++if+(obj2Matches.length)+{
++++obj1.value.total+%2B=+obj2Matches.reduce(((accum,+curr)+=>+accum++%2B+curr.value),+0);
++}
});|2050388|复杂性：|2050389|2050390|时间:+O(N+*M)|unordered-list-item|2050391|空间:+O(M)|2050392|N+=>+arr1.length，M+=>+arr2.length|2050393|2050394|entityMap^0|7|2|0|0|D|2|K|4|R|2|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|15|8|@$9|16|A|17|B|C]|$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|1C|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1D|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]|$1|R|3|S|5|T|7|1F|8|@]|D|@]|E|$]]|$1|U|3|V|5|T|7|1G|8|@]|D|@]|E|$]]|$1|W|3|X|5|T|7|1H|8|@]|D|@]|E|$]]|$1|Y|3|-4|5|6|7|1I|8|@]|D|@]|E|$]]|$1|Z|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]]|10|$]]

If each object's <code>id</code> is unique (within each array), you can do:
<pre class="lang-js prettyprint-override"><code>arr1.forEach((obj1) =&gt; {
 const obj2Match = arr2.find((obj2) =&gt; obj1.id === obj2.id );

 if (obj2Match) {
 obj1.value.total += obj2Match.value;
 }
});
</code></pre>
If more than one object can have the same <code>id</code> (e.g. <code>arr2</code> has two objects that have the <code>id</code> of 2), then you can do:
<pre class="lang-js prettyprint-override"><code>arr1.forEach((obj1) =&gt; {
 const obj2Matches = arr2.filter((obj2) =&gt; obj1.id === obj2.id );

 if (obj2Matches.length) {
 obj1.value.total += obj2Matches.reduce(((accum, curr) =&gt; accum + curr.value), 0);
 }
});
</code></pre>
Complexity:
<ul>
<li>Time: O(N * M)</li>
<li>Space: O(M)</li>
<li>N =&gt; arr1.length, M =&gt; arr2.length</li>
</ul>

i have two array of objects like below, am trying to compare two arrays and looking to update the object total value of arr1 if the id matches with arr2.
<pre><code>const arr1 = [
{
 id: 1,
 value: { total: 0 },
},
{
 id: 2,
 value: { total: 0 },
},
{
 id: 3,
 value: { total: 0 },
},
 id: 4,
 value: { total: 0 },
},
];

const arr2 = [
 {
 id: 2,
 value: 3 ,
 },
 {
 id: 3,
 value: 5,
 },

 ];
</code></pre>
I am trying to compare two arrays and looking to update the object total value of arr1 if the id matches with arr2
expected result is
<pre><code>const arr1 = [
 {
 id: 1,
 value: { total: 0 },
 },
{
id: 2,
value: { total: 3 },
},
{
 id: 3,
 value: { total: 5 },
 },
 {
 id: 4,
 value: { total: 0 },
 },
 ];
</code></pre>
I have tried the below code,
<pre><code>arr1.map((item) =&gt; {
arr2.find((element) =&gt; {
 if (element.id === item.id ) {
 item = {
 ...item,
 value: {
 ...item.value,
 total: item.value.total + element.value,
 },
 };
 console.log(item);
 }
});
return item;
});
</code></pre>

Update the value of nested object in the array based on the key

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有两个像下面这样的对象数组，我正在尝试比较两个数组，并在id与arr2匹配的情况下更新arr1的对象总值。const arr1 = [{  id: 1,  value: { total: 0 },},{  id: 2,  value: { total: 0 },},{  id: 3,  value: { total:...

问根据键更新数组中嵌套对象的值
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问根据键更新数组中嵌套对象的值EN