问我需要在c++中打印此形状，但我在最后一行遇到问题

EN

std::string repeat(std::string s, int n) {
  std::string repeat;
  for (int i = 0; i < n; ++i)
    repeat += s;
  return repeat;
}

int main()
{
    int PADDING = 20; 
    int MAX = 7;
    for (int i = 1; i < MAX; ++i) {
        if (i == 5) continue;

        std::string padding(3*(PADDING-MAX-i), ' ');
        
        std::cout << padding << repeat("-.*", i)  << std::endl;
    }
}

                                -.*
                             -.*-.*
                          -.*-.*-.*
                       -.*-.*-.*-.*
                 -.*-.*-.*-.*-.*-.*

for (int i = 1; i <= 6; i++) {
    for (int j = 28 - i * 3; j >= 0; j--) {
        std::cout << " ";
    }
    for (int j = 0; j < i; j++) {
        std::cout << "-.*";
    }
    std::cout << std::endl;
    if (i == 4) i++;
}

#include <stdio.h>

int main(void) {
    int height = 5;
    char txt[3*height+1];
    char sym[]= "-.*";
    for(int i=0; i<3*height; ++i) txt[i]=sym[i%3];
    txt[3*height]=0;
    
    for(int i=0; i<height; ++i)
    printf("%s%*.*s\n", (i+1==height)? &txt[3*(height-1)] : "", 3*(height+(i+1<height)), (i+1)*3, txt);
    
    return 0;
}

Success #stdin #stdout 0s 5476KB
               -.*
            -.*-.*
         -.*-.*-.*
      -.*-.*-.*-.*
-.*-.*-.*-.*-.*-.*