blocks|key|5647079|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5647080|$string+=+'bla+test+bla+test+bla+test+bla+test+bla';

echo+preg_replace('~+test(?!.*+test)~',+'',+$string);|code-block|syntax|javascript|5647081|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this:
<pre><code>$string = 'bla test bla test bla test bla test bla';

echo preg_replace('~ test(?!.* test)~', '', $string);
</code></pre>

blocks|key|5647083|text|一种手动的方法是用分隔符将字符串分割成一个数组，检测最后一个主题位置(反转)，然后取消设置并将其粘合在一起。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5647084|var_dump(remove_last('bla+test+bla+test+bla+test+bla+test+bla',+'test',+'+'));

function+remove_last(string+$text,+string+$subject,+string+$separator):+string+{
++++$parts+=+explode($separator,+$text);
++++$pos+=+count($parts)+-1+-array_search($subject,+array_reverse($parts));

++++if+($parts[$pos]+??+false)+{
++++++++unset($parts[$pos]);
++++}

++++return+implode($separator,+$parts);
}|code-block|syntax|javascript|5647085|https://3v4l.org/X0F13|offset|length|5647086|使用substr_replace()的另一种方式|style|CODE|5647087|var_dump(remove_last('bla+test+bla+test+bla+test+bla+test+bla',+'test',+'+'));

function+remove_last(string+$text,+string+$subject,+string+$separator):+string+{
++++if+(($offset+=+strrpos($text,+"$separator$subject"))+===+false)+{
++++++++$offset+=+strrpos($text,+"$subject$separate");
++++}
++++
++++if+($offset+!==+false)+{
++++++++return+substr_replace($text,+'',+$offset,+strlen("$separator$subject"));
++++}
++++
++++return+$text;
}|5647088|https://3v4l.org/ZUULc|5647089|entityMap|0|LINK|mutability|MUTABLE|url|1^0|0|0|0|M|0|0|2|G|0|0|0|M|1|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|12|8|@]|9|@$I|13|J|14|1|15]]|A|$]]|$1|K|3|L|5|6|7|16|8|@$I|17|J|18|M|N]]|9|@]|A|$]]|$1|O|3|P|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|1A|8|@]|9|@$I|1B|J|1C|1|1D]]|A|$]]|$1|S|3|-4|5|6|7|1E|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|H]]|Z|$5|V|W|X|A|$Y|R]]]]

A manual way of doing it would be to split the string with a separator into an array, detect last subject position (in reverse), then unset and glue it back together.
<pre><code>var_dump(remove_last('bla test bla test bla test bla test bla', 'test', ' '));

function remove_last(string $text, string $subject, string $separator): string {
 $parts = explode($separator, $text);
 $pos = count($parts) -1 -array_search($subject, array_reverse($parts));

 if ($parts[$pos] ?? false) {
 unset($parts[$pos]);
 }

 return implode($separator, $parts);
}
</code></pre>
<a href="https://3v4l.org/X0F13" rel="nofollow noreferrer">https://3v4l.org/X0F13</a>
Another way using <code>substr_replace()</code>:
<pre><code>var_dump(remove_last('bla test bla test bla test bla test bla', 'test', ' '));

function remove_last(string $text, string $subject, string $separator): string {
 if (($offset = strrpos($text, &quot;$separator$subject&quot;)) === false) {
 $offset = strrpos($text, &quot;$subject$separate&quot;);
 }
 
 if ($offset !== false) {
 return substr_replace($text, '', $offset, strlen(&quot;$separator$subject&quot;));
 }
 
 return $text;
}
</code></pre>
<a href="https://3v4l.org/ZUULc" rel="nofollow noreferrer">https://3v4l.org/ZUULc</a>

blocks|key|1862201|text|首先还原字符串：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1862202|“bla+test+bla”变为“alb+tset+alb”。|1862203|然后在此字符串中将要替换的字符串的反向版本替换为要替换的字符串的反向版本。|1862204|因此:将‘tset’替换为‘’(添加空格以强制替换完整的单词)：|1862205|“alb+tset+alb”变为“alb+alb+tset+alb”。|1862206|然后再次恢复它：|1862207|'alb+alb+tset+alb‘变成了'bla+test+bla+bla’。|1862208|你可以把它放在一个线条中：|1862209|<?php
$string+=+'bla+test+bla+test+bla+test+bla+test+bla';
$word+=+'test';
echo+strrev(preg_replace('/'.preg_quote('+'.strrev($word).'+',+'/').'/',+'+',+strrev($string),+1));|code-block|syntax|javascript|1862210|​|1862211|entityMap^0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|11|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|12|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|13|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|14|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|15|8|@]|9|@]|A|$]]|$1|P|3|Q|5|R|7|16|8|@]|9|@]|A|$S|T]]|$1|U|3|V|5|6|7|17|8|@]|9|@]|A|$]]|$1|W|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|X|$]]

First revert the string: 
'bla test bla test bla test bla test bla' becomes 'alb tset alb tset alb tset alb tset alb'. 
Then replace in this string the reversed version of the string to be replaced with the reversed version of the string to replace it with. 
So: replace ' tset ' with ' ' (add spaces to force that full words are being replaced): 
'alb tset alb tset alb tset alb tset alb' becomes 'alb alb tset alb tset alb tset alb'. 
Then revert it again: 
'alb alb tset alb tset alb tset alb' becomes 'bla test bla test bla test bla bla'. 
You can put it in a oneliner: 
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;?php
$string = 'bla test bla test bla test bla test bla';
$word = 'test';
echo strrev(preg_replace('/'.preg_quote(' '.strrev($word).' ', '/').'/', ' ', strrev($string), 1));</code></pre>
</div>
</div>

blocks|key|4178996|text|使用提供的字符串函数strrpos()从右到左在字符串处理中查找指针。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4178997|str_replace()你可以很简单地做到这一点|4178998|$string+=+'bla+test+bla+test+bla+test+bla+test+bla';
$needle+=+'test';
echo+$string+.+PHP_EOL;
$pos+=+strrpos($string,+$needle,+0);
if+(+$pos+!==+FALSE+){
++++//+it+was+found+in+the+string
++++$new_string+=+substr_replace($string,+'',+$pos,+strlen('test+'));
}+else+{
++++echo+"$needle+not+found+in+the+string";
}
echo+$new_string+.PHP_EOL;|code-block|syntax|javascript|4178999|结果|4179000|bla+test+bla+test+bla+test+bla+test+bla
bla+test+bla+test+bla+test+bla+bla|4179001|entityMap|0|LINK|mutability|MUTABLE|url|https://www.php.net/manual/en/function.strrpos|1|https://www.php.net/manual/en/function.substr-replace.php^0|A|9|A|9|0|0|0|D|0|D|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]]|E|$]]|$1|F|3|G|5|6|7|16|8|@$9|17|A|18|B|C]]|D|@$9|19|A|1A|1|1B]]|E|$]]|$1|H|3|I|5|J|7|1C|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1D|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|1E|8|@]|D|@]|E|$K|L]]|$1|Q|3|-4|5|6|7|1F|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]|Y|$5|T|U|V|E|$W|Z]]]]

Using the provided String Function <a href="https://www.php.net/manual/en/function.strrpos" rel="nofollow noreferrer"><code>strrpos()</code></a> Find needle in string processing from right to left.
and <a href="https://www.php.net/manual/en/function.substr-replace.php" rel="nofollow noreferrer"><code>str_replace()</code></a> you can do this quite simply
<pre><code>$string = 'bla test bla test bla test bla test bla';
$needle = 'test';
echo $string . PHP_EOL;
$pos = strrpos($string, $needle, 0);
if ( $pos !== FALSE ){
 // it was found in the string
 $new_string = substr_replace($string, '', $pos, strlen('test '));
} else {
 echo &quot;$needle not found in the string&quot;;
}
echo $new_string .PHP_EOL;
</code></pre>
RESULT
<pre><code>bla test bla test bla test bla test bla
bla test bla test bla test bla bla
</code></pre>

How can i delete the last word by a specific word in a string?
So example, this is the string
<pre><code>$string = 'bla test bla test bla test bla test bla'
</code></pre>
Now i want to delete <code>test</code> but just the last one, not everyone.
Output must be this
<pre><code>$string = 'bla test bla test bla test bla bla'
</code></pre>
i just find str_replace and something, but than i delete every test and not only the last one...
I also searched here but not finding something to delete the specific word that i will delete. Jsut find something with trim last space or something. But AFTER the last word i search for, there can be more words

PHP delete the last word in string by specific word

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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问PHP按特定单词删除字符串中的最后一个单词
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