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社区首页 >问答首页 >在PHPleague中使用post请求访问access_token oauth2.0客户端错误

在PHPleague中使用post请求访问access_token oauth2.0客户端错误
EN

Stack Overflow用户
提问于 2021-12-08 15:40:51
回答 1查看 586关注 0票数 1

我目前正在开发一个web特性,它是通过phpleague实现oauth2服务器的。我认为我在服务器的设计上做得很好,但是我不知道为什么客户端会显示一个我不明白的错误。

我的客户代码:

代码语言:javascript
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<?php
require 'vendor/autoload.php';

$provider = new \League\OAuth2\Client\Provider\GenericProvider([
    'clientId'                => '1',    // The client ID assigned to you by the provider
    'clientSecret'            => 'haha',    // The client password assigned to you by the provider
    'redirectUri'             => 'http://localhost:4444/callback.php',
    'urlAuthorize'            => 'http://localhost:1337/authorize',
    'urlAccessToken'          => 'http://localhost:1337/access_token',
    'urlResourceOwnerDetails' => 'https://service.example.com/resource'
]);

// If we don't have an authorization code then get one
if (!isset($_GET['code'])) {

    // Fetch the authorization URL from the provider; this returns the
    // urlAuthorize option and generates and applies any necessary parameters
    // (e.g. state).
    $authorizationUrl = $provider->getAuthorizationUrl();

    // Get the state generated for you and store it to the session.
    $_SESSION['oauth2state'] = $provider->getState();

    // Redirect the user to the authorization URL.
    header('Location: ' . $authorizationUrl);
    exit;

// Check given state against previously stored one to mitigate CSRF attack
} elseif (empty($_GET['state']) || (isset($_SESSION['oauth2state']) && $_GET['state'] !== $_SESSION['oauth2state'])) {

    if (isset($_SESSION['oauth2state'])) {
        unset($_SESSION['oauth2state']);
    }

    exit('Invalid state');

} else {

    try {

        // Try to get an access token using the authorization code grant.
        $accessToken = $provider->getAccessToken('authorization_code', [
            'code' => $_GET['code']
        ]);
    
        // We have an access token, which we may use in authenticated
        // requests against the service provider's API.
        echo 'Access Token: ' . $accessToken->getToken() . "<br>";
        echo 'Refresh Token: ' . $accessToken->getRefreshToken() . "<br>";
        echo 'Expired in: ' . $accessToken->getExpires() . "<br>";
        echo 'Already expired? ' . ($accessToken->hasExpired() ? 'expired' : 'not expired') . "<br>";

        // Using the access token, we may look up details about the
        // resource owner.
        $resourceOwner = $provider->getResourceOwner($accessToken);

        var_export($resourceOwner->toArray());

        // The provider provides a way to get an authenticated API request for
        // the service, using the access token; it returns an object conforming
        // to Psr\Http\Message\RequestInterface.
        var_dump($access_token);

    } catch (\League\OAuth2\Client\Provider\Exception\IdentityProviderException $e) {

        // Failed to get the access token or user details.
        exit($e->getMessage());

    }

}

调用getAccessToken时回调中出现错误。

下面是堆栈跟踪:

代码语言:javascript
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Fatal error: Uncaught UnexpectedValueException:
Failed to parse JSON response: 
Syntax error in /opt/lampp/htdocs/oauth2_client/vendor/league/oauth2-client/src/Provider/AbstractProvider.php:645
Stack trace: 
#0 /opt/lampp/htdocs/oauth2_client/vendor/league/oauth2-client/src/Provider/AbstractProvider.php(686): League\OAuth2\Client\Provider\AbstractProvider->parseJson() 
#1 /opt/lampp/htdocs/oauth2_client/vendor/league/oauth2-client/src/Provider/AbstractProvider.php(626): League\OAuth2\Client\Provider\AbstractProvider->parseResponse() 
#2 /opt/lampp/htdocs/oauth2_client/vendor/league/oauth2-client/src/Provider/AbstractProvider.php(537): League\OAuth2\Client\Provider\AbstractProvider->getParsedResponse() 
#3 /opt/lampp/htdocs/oauth2_client/callback.php(43): League\OAuth2\Client\Provider\AbstractProvider->getAccessToken()
#4 {main} thrown in /opt/lampp/htdocs/oauth2_client/vendor/league/oauth2-client/src/Provider/AbstractProvider.php on line 645

我不明白为什么我有这个错误..。

EN

Stack Overflow用户

发布于 2021-12-09 10:55:29

我已经修正了错误。当我向我的access_token发送请求时,我注意到了错误,所以当我的客户端发送post请求并解析json时,它在解析时会导致一个错误,因为它试图直接将错误解析为字符串,而字符串不是json格式的。

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/70277730

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